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Problem 6.164 The pin at B is attached to member ABCD and can slide along a slot cut in member BE. Neglecting the effect of friction, determine the couple.

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Presentation on theme: "Problem 6.164 The pin at B is attached to member ABCD and can slide along a slot cut in member BE. Neglecting the effect of friction, determine the couple."— Presentation transcript:

1 Problem 6.164 The pin at B is attached to member ABCD and can slide along a slot cut in member BE. Neglecting the effect of friction, determine the couple M required to hold the system in equilibrium. A B C D E 15 in 80 lb 40 lb 36 in M

2 Solving Problems on Your Own The pin at B is attached to member ABCD and can slide along a slot cut in member BE. Neglecting the effect of friction, determine the couple M required to hold the system in equilibrium. A B C D E 15 in 80 lb 40 lb 36 in M For this problem we note that there are no two- force members. In solving this problem, we 1. Dismember the frame, and draw a free-body diagram for each member. Problem 6.164 2. To simplify the solution, seek a way to write an equation involving a single unknown.

3 + Dismember the frame, and draw a free-body diagram for each member. B E 15 in 36 in M 5 12 13 ExEx EyEy Free-Body: Member BE BE = (15 2 + 36 2 ) 1/2 = 39 in 15 36 39 5 12 13 To simplify the solution, seek a way to write an equation involving a single unknown.  M E = 0: M - B (39 in) = 0 M = B (39 in) (1) Problem 6.164 Solution

4 Dismember the frame, and draw a free-body diagram for each member. B 5 12 13 Free-Body: Member BE A C D 15 in 80 lb 40 lb DxDx DyDy + To simplify the solution, seek a way to write an equation involving a single unknown.  M D = 0: (40 lb)(45 in) + (80 lb)(15 in) - B(30 in) = 0 5 13 B = 260 lb

5 Problem 6.164 Solution B 5 12 13 A C D 15 in 80 lb 40 lb DxDx DyDy B = 260 lb B E 15 in 36 in M 5 12 13 ExEx EyEy M = B (39 in) From EQ (1) M = B (39 in) = (260 lb) (39 in) = 10,140 lb-in M = 10.14 kip-in


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