1. To Do… Electronic homework (Lon-Capa) HW4 Type 1 due Monday, March 10 by 7 pm; HW4 Type 2 due Wednesday, March 12 by 7 pm HW5 Type 1 due Monday, March 17 by 7 pm; HW5 Type 2 due Wednesday, March 19 by 7 pm Exam 2 review: due Wednesday, March 19 by 7pm Exam #2: Thursday, March 20, 7 pm

2. Stoichiometry Determine the amount(s) of reactant(s) or product(s) given amount(s) of reactant(s) or product(s). We must have a balanced chemical equation. Reactions occur by numbers of atoms/molecules.

3. Determine Number of Moles Use mass and molar masses. Use volume and concentration for solutions. Use pressure, volume, and temperature for gases.

4. Clicker Question If you have 8 moles of hydrogen and all the oxygen you need, how many moles of water can you make? 2H 2 + O 2 → 2H 2 O A)1 mol B)2 mol C)4 mol D)8 mol E)16 mol 4

5. Clicker Question If you have 6 moles of oxygen and all the hydrogen you need, how many moles of water can you make? 2H 2 + O 2 → 2H 2 O A)1 mol B)2 mol C)3 mol D)6 mol E)12 mol 5

6. Clicker Question If you have 8 moles of hydrogen and 6 moles of oxygen, how many moles of water can you make? 2H 2 + O 2 → 2H 2 O A)6 mol B)8 mol C)12 mol D)14 mol E)16 mol 6

7. Starting with Mass… If you have 48.0 g of oxygen gas and all the hydrogen gas you need, what mass of water is produced? 2H 2 + O 2 → 2H 2 O 7

8. Solids, Solutions, and Gases NaHCO 3 (s) + HC 2 H 3 O 2 (aq) → Na C 2 H 3 O 2 (aq) + H 2 O(l) + CO 2 (g) Which balloon will be the biggest? 8 Trial #Mass of NaHCO 3 Volume of 0.833 M HC 2 H 3 O 2 13.30 g150.0 mL 25.70 g150.0 mL 310.5 g150.0 mL 421.0 g150.0 mL 531.8 g150.0 mL

9. Solids, Solutions, and Gases NaHCO 3 (s) + HC 2 H 3 O 2 (aq) → Na C 2 H 3 O 2 (aq) + H 2 O(l) + CO 2 (g) Determine the volumes of the balloons. 9 Trial #Mass of NaHCO 3 Volume of 0.833 M HC 2 H 3 O 2 13.30 g150.0 mL 25.70 g150.0 mL 310.5 g150.0 mL 421.0 g150.0 mL 531.8 g150.0 mL

10. Solids, Solutions, and Gases NaHCO 3 (s) + HC 2 H 3 O 2 (aq) → Na C 2 H 3 O 2 (aq) + H 2 O(l) + CO 2 (g) Determine the mass of left-over sodium bicarbonate in Trial #5. 10 Trial #Mass of NaHCO 3 Volume of 0.833 M HC 2 H 3 O 2 13.30 g150.0 mL 25.70 g150.0 mL 310.5 g150.0 mL 421.0 g150.0 mL 531.8 g150.0 mL

11. Solids, Solutions, and Gases NaHCO 3 (s) + HC 2 H 3 O 2 (aq) → Na C 2 H 3 O 2 (aq) + H 2 O(l) + CO 2 (g) Determine the concentration of left-over acetic acid in Trial #1. 11 Trial #Mass of NaHCO 3 Volume of 0.833 M HC 2 H 3 O 2 13.30 g150.0 mL 25.70 g150.0 mL 310.5 g150.0 mL 421.0 g150.0 mL 531.8 g150.0 mL