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Calculations H.C.F. L.C.M. using Prime Factors © T Madas.

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Presentation on theme: "Calculations H.C.F. L.C.M. using Prime Factors © T Madas."— Presentation transcript:

1 Calculations H.C.F. L.C.M. using Prime Factors © T Madas

2 Round 1 © T Madas

3 Find the H.C.F. and the L.C.M. of 24 and 36
= 2 x 2 x 2 x 3 = 23 x 31 12 36 = 2 x 2 x 3 x 3 = 22 x 32 2 2 6 18 2 9 2 3 2 3 3 3 1 3 1 © T Madas

4 Find the H.C.F. and the L.C.M. of 24 and 36
= 2 x 2 x 2 x 3 = 23 x 31 36 = 2 x 2 x 3 x 3 = 22 x 32 © T Madas

5 12 H.C.F. = 22 x 31 = Find the H.C.F. and the L.C.M. of 24 and 36 24
= 2 x 2 x 2 x 3 = 23 x 31 36 = 2 x 2 x 3 x 3 = 22 x 32 12 H.C.F. = 22 x 31 = The H.C.F is given by the product of: Common prime factors with the lowest power © T Madas

6 72 L.C.M. = 23 x 32 = Find the H.C.F. and the L.C.M. of 24 and 36 24
= 2 x 2 x 2 x 3 = 23 x 31 36 = 2 x 2 x 3 x 3 = 22 x 32 72 L.C.M. = 23 x 32 = The H.C.F is given by the product of: Common prime factors with the lowest power The L.C.M is given by the product of: All prime factors with the highest power © T Madas

7 Round 2 © T Madas

8 Find the H.C.F. and the L.C.M. of 30 and 48
= 2 x 3 x 5 = 21 x 31 x 51 15 48 = 2 x 2 x 2 x 2 x 3 = 24 x 31 2 3 5 24 2 5 1 2 12 2 6 2 3 3 1 © T Madas

9 Find the H.C.F. and the L.C.M. of 30 and 48
= 2 x 3 x 5 = 21 x 31 x 51 48 = 2 x 2 x 2 x 2 x 3 = 24 x 31 © T Madas

10 6 H.C.F. = 21 x 31 = Find the H.C.F. and the L.C.M. of 30 and 48 30
= 2 x 3 x 5 = 21 x 31 x 51 48 = 2 x 2 x 2 x 2 x 3 = 24 x 31 6 H.C.F. = 21 x 31 = The H.C.F is given by the product of: Common prime factors with the lowest power © T Madas

11 240 L.C.M. = 24 x 31 x 51= Find the H.C.F. and the L.C.M. of 30 and 48
= 2 x 2 x 2 x 2 x 3 = 24 x 31 240 L.C.M. = 24 x 31 x 51= The H.C.F is given by the product of: Common prime factors with the lowest power The L.C.M is given by the product of: All prime factors with the highest power © T Madas

12 Round 3 © T Madas

13 Find the H.C.F. and the L.C.M. of 60 and 72
= 2 x 2 x 3 x 5 = 22 x 31 x 51 30 72 = 2 x 2 x 2 x 3 x 3 2 = 23 x 32 2 15 36 2 3 5 2 18 2 9 5 1 3 3 3 1 © T Madas

14 Find the H.C.F. and the L.C.M. of 60 and 72
= 2 x 2 x 3 x 5 = 22 x 31 x 51 72 = 2 x 2 x 2 x 3 x 3 = 23 x 32 © T Madas

15 12 H.C.F. = 22 x 31 = Find the H.C.F. and the L.C.M. of 60 and 72 60
= 2 x 2 x 3 x 5 = 22 x 31 x 51 72 = 2 x 2 x 2 x 3 x 3 = 23 x 32 12 H.C.F. = 22 x 31 = The H.C.F is given by the product of: Common prime factors with the lowest power © T Madas

16 360 L.C.M. = 23 x 32 x 51= Find the H.C.F. and the L.C.M. of 60 and 72
= 2 x 2 x 3 x 5 = 22 x 31 x 51 72 = 2 x 2 x 2 x 3 x 3 = 23 x 32 360 L.C.M. = 23 x 32 x 51= The H.C.F is given by the product of: Common prime factors with the lowest power The L.C.M is given by the product of: All prime factors with the highest power © T Madas

17 Round 4 © T Madas

18 Find the H.C.F. and the L.C.M. of 48 and 120
= 2 x 2 x 2 x 2 x 3 = 24 x 31 24 120 = 2 x 2 x 2 x 3 x 5 2 = 23 x 31 x 51 2 12 60 2 2 6 2 30 2 15 2 3 3 5 3 1 5 1 © T Madas

19 Find the H.C.F. and the L.C.M. of 48 and 120
= 2 x 2 x 2 x 2 x 3 = 24 x 31 120 = 2 x 2 x 2 x 3 x 5 = 23 x 31 x 51 © T Madas

20 24 H.C.F. = 23 x 31 = Find the H.C.F. and the L.C.M. of 48 and 120 48
= 2 x 2 x 2 x 2 x 3 = 24 x 31 120 = 2 x 2 x 2 x 3 x 5 = 23 x 31 x 51 24 H.C.F. = 23 x 31 = The H.C.F is given by the product of: Common prime factors with the lowest power © T Madas

21 Find the H.C.F. and the L.C.M. of 48 and 120
= 2 x 2 x 2 x 2 x 3 = 24 x 31 120 = 2 x 2 x 2 x 3 x 5 = 23 x 31 x 51 240 L.C.M. = 24 x 31 x 51= The H.C.F is given by the product of: Common prime factors with the lowest power The L.C.M is given by the product of: All prime factors with the highest power © T Madas

22 Round 5 © T Madas

23 Find the H.C.F. and the L.C.M. of 120 and 168
= 2 x 2 x 2 x 3 x 5 = 23 x 31 x 51 60 168 = 2 x 2 x 2 x 3 x 7 2 = 23 x 31 x 71 2 30 84 2 2 15 2 42 2 21 3 5 3 7 5 1 7 1 © T Madas

24 Find the H.C.F. and the L.C.M. of 120 and 168
= 2 x 2 x 2 x 3 x 5 = 23 x 31 x 51 168 = 2 x 2 x 2 x 3 x 7 = 23 x 31 x 71 © T Madas

25 Find the H.C.F. and the L.C.M. of 120 and 168
= 2 x 2 x 2 x 3 x 5 = 23 x 31 x 51 168 = 2 x 2 x 2 x 3 x 7 = 23 x 31 x 71 24 H.C.F. = 23 x 31 = The H.C.F is given by the product of: Common prime factors with the lowest power © T Madas

26 Find the H.C.F. and the L.C.M. of 120 and 168
= 2 x 2 x 2 x 3 x 5 = 23 x 31 x 51 168 = 2 x 2 x 2 x 3 x 7 = 23 x 31 x 71 840 L.C.M. = 23 x 31 x 51 x 71 = The H.C.F is given by the product of: Common prime factors with the lowest power The L.C.M is given by the product of: All prime factors with the highest power © T Madas

27 © T Madas


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