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ECE Networks & Systems Jose E. Schutt-Aine

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Presentation on theme: "ECE Networks & Systems Jose E. Schutt-Aine"— Presentation transcript:

1 ECE 342 1. Networks & Systems Jose E. Schutt-Aine
Electrical & Computer Engineering University of Illinois

2 What is Capacitance? 3 1 2 Voltage = 6V Voltage=0 Voltage build up
No Charge No Current 1 2 Voltage build up Charge build up Transient Current 3 Voltage = 6V Charge=Q No Current

3 What is Capacitance? 4 6 5 Voltage=0 Voltage decaying Voltage=6V
Charge=Q No Current 4 Voltage decaying Charge decaying Transient Current 5 Voltage=0 No Charge No Current 6

4 Capacitance Relation: Q = Cv Q: charge stored by capacitor C: capacitance v: voltage across capacitor i: current into capacitor

5 What is Inductance? Current in wire produces magnetic field
Flux is magnetic field integrated over area

6 Inductance

7 Inductance Relation: Y = Li Y: flux stored by inductor L: inductance i: current through inductor v: voltage across inductor

8 Low-Pass Circuit Need to solve for vo(t)

9 Low-Pass Circuit Need to solve for vo(t)

10 Reactive Circuit Need to solve for vx(t)

11 Laplace Transforms The Laplace transform F(s) of a function f(t) is defined as: To a mathematician, this is very meaningful; however circuit engineers seldom use that integral The Laplace transform provides a conversion from the time domain into a new domain, the s domain

12 s = jw Laplace Transforms
The Laplace transform of the derivative of a function f(t) is given by Differentiation in the time domain becomes a multiplication in the s domain. That is why Laplace transforms are useful to circuit engineers s = jw

13 Low-Pass Circuit Time domain s domain Time domain s domain

14 Low-Pass Circuit - Solution
Pole exists at Assume that Vi(s)=Vd/s Inversion

15 Reactive Circuit

16 Reactive Circuit - Solution
Exercise: Use inversion to solve for vx(t)

17 Table of Laplace Transforms
Function Transform

18 Capacitance – s Domain The capacitor is a reactive element
Assume time-harmonic behavior of voltage and current variables jw = s The capacitor is a reactive element

19 Inductance – s Domain The inductor is a reactive element
Assume time-harmonic behavior of voltage and current variables jw = s The inductor is a reactive element

20 Thevenin Equivalent Principle Application
Any linear two-terminal network consisting of current or voltage sources and impedances can be replaced by an equivalent circuit containing a single voltage source in series with a single impedance. Application To find the Thevenin equivalent voltage at a pair of terminals, the load is first removed leaving an open circuit. The open circuit voltage across this terminal pair is the Thevenin equivalent voltage. The equivalent resistance is found by replacing each independent voltage source with a short circuit (zeroing the voltage source), replacing each independent current source with an open circuit (zeroing the current source) and calculating the resistance between the terminals of interest. Dependent sources are not replaced and can have an effect on the value of the equivalent resistance.

21 Norton Equivalent Principle Application
Any linear two-terminal network consisting of current or voltage sources and impedances can be replaced by an equivalent circuit containing a single current source in parallel with a single impedance. Application To find the Norton equivalent current at a pair of terminals, the load is first removed and replaced with a short circuit. The short-circuit current through that branch is the Norton equivalent current. The equivalent resistance is found by replacing each independent voltage source with a short circuit (zeroing the voltage source), replacing each independent current source with an open circuit (zeroing the current source) and calculating the resistance between the terminals of interest. Dependent sources are not replaced and can have an effect on the value of the equivalent resistance.

22 Thevenin Equivalent - Example
Circuit for calculating impedance Calculating Thevenin voltage KCL law at node A’ gives 1+Iy = Ix Also KVL gives 10=2Iy+3Ix Combining these equations gives Ix = 2.4 mA From which we calculate Vx = Vth=3(2.4)=7.2 V

23 Thevenin Example Find voltage across R4 From which

24 Thevenin Equivalent Circuit for calculating impedance
(current source is replaced with open circuit)

25 Circuit with Thevenin Equivalent
ZTH VTH

26 Need to find the current i1(t) in resistor R3
Thevenin Example Need to find the current i1(t) in resistor R3

27 Thevenin voltage calculation
Thevenin Example Thevenin voltage calculation

28 Calculating the impedance
Thevenin Example Calculating the impedance

29 Thevenin Example

30 Expanding using partial fraction The time-domain current i1(t) is:
Thevenin Example Expanding using partial fraction With K1 = 3.33, K2 = -5, K3 = 1.67 The time-domain current i1(t) is:


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