Presentation is loading. Please wait.

Presentation is loading. Please wait.

Copyright © 2009 Pearson Education, Inc. Chapter 29 Electromagnetic Induction and Faraday’s Law.

Similar presentations


Presentation on theme: "Copyright © 2009 Pearson Education, Inc. Chapter 29 Electromagnetic Induction and Faraday’s Law."— Presentation transcript:

1 Copyright © 2009 Pearson Education, Inc. Chapter 29 Electromagnetic Induction and Faraday’s Law

2 Copyright © 2009 Pearson Education, Inc. Induced EMF Faraday’s Law of Induction; Lenz’s Law EMF Induced in a Moving Conductor Electric Generators Back EMF and Counter Torque; Eddy Currents Units of Chapter 29

3 Copyright © 2009 Pearson Education, Inc. Transformers and Transmission of Power A Changing Magnetic Flux Produces an Electric Field Applications of Induction: Sound Systems, Computer Memory, Seismograph, GFCI Units of Chapter 29

4 Copyright © 2009 Pearson Education, Inc. Almost 200 years ago, Faraday looked for evidence that a magnetic field would induce an electric current with this apparatus: 29-1 Induced EMF

5 Copyright © 2009 Pearson Education, Inc. He found no evidence when the current was steady, but did see a current induced when the switch was turned on or off. 29-1 Induced EMF

6 Copyright © 2009 Pearson Education, Inc. Therefore, a changing magnetic field induces an emf. Faraday’s experiment used a magnetic field that was changing because the current producing it was changing; the previous graphic shows a magnetic field that is changing because the magnet is moving. 29-1 Induced EMF

7 Copyright © 2009 Pearson Education, Inc. The induced emf in a wire loop is proportional to the rate of change of magnetic flux through the loop. Magnetic flux: Unit of magnetic flux: weber, Wb: 1 Wb = 1 T·m 2. 29-2 Faraday’s Law of Induction

8 Copyright © 2009 Pearson Education, Inc. This drawing shows the variables in the flux equation: 29-2 Faraday’s Law of Induction

9 Copyright © 2009 Pearson Education, Inc. The magnetic flux is analogous to the electric flux – it is proportional to the total number of magnetic field lines passing through the loop. 29-2 Faraday’s Law of Induction

10 Copyright © 2009 Pearson Education, Inc. 29-2 Faraday’s Law of Induction Conceptual Example 29-1: Determining flux. A square loop of wire encloses area A 1. A uniform magnetic field B perpendicular to the loop extends over the area A 2. What is the magnetic flux through the loop A 1 ?

11 Copyright © 2009 Pearson Education, Inc. Faraday’s law of induction: the emf induced in a circuit is equal to the rate of change of magnetic flux through the circuit: 29-2 Faraday’s Law of Induction or

12 Copyright © 2009 Pearson Education, Inc. 29-2 Faraday’s Law of Induction Example 29-2: A loop of wire in a magnetic field. A square loop of wire of side l = 5.0 cm is in a uniform magnetic field B = 0.16 T. What is the magnetic flux in the loop (a) when B is perpendicular to the face of the loop and (b) when B is at an angle of 30° to the area A of the loop? (c) What is the magnitude of the average current in the loop if it has a resistance of 0.012 Ω and it is rotated from position (b) to position (a) in 0.14 s?

13 If a north pole moves toward the loop from above the page, in what direction is the induced current? 1) clockwise 2) counterclockwise 3) no induced current ConcepTest 29.2a Moving Bar Magnet I

14 If a north pole moves toward the loop from above the page, in what direction is the induced current? 1) clockwise 2) counterclockwise 3) no induced current into the page larger out of the pagecounterclockwise The magnetic field of the moving bar magnet is pointing into the page and getting larger as the magnet moves closer to the loop. Thus the induced magnetic field has to point out of the page. A counterclockwise induced current will give just such an induced magnetic field. ConcepTest 29.2a Moving Bar Magnet I Follow-up: What happens if the magnet is stationary but the loop moves?

15 If a north pole moves toward the loop in the plane of the page, in what direction is the induced current? 1) clockwise 2) counterclockwise 3) no induced current ConcepTest 29.2b Moving Bar Magnet II

16 no magnetic flux through the loop induced current is zero Since the magnet is moving parallel to the loop, there is no magnetic flux through the loop. Thus the induced current is zero. If a north pole moves toward the loop in the plane of the page, in what direction is the induced current? 1) clockwise 2) counterclockwise 3) no induced current ConcepTest 29.2b Moving Bar Magnet II

17 Copyright © 2009 Pearson Education, Inc. The minus sign gives the direction of the induced emf: A current produced by an induced emf moves in a direction so that the magnetic field it produces tends to restore the changed field. or: An induced emf is always in a direction that opposes the original change in flux that caused it. 29-2 Faraday’s Law of Induction; Lenz’s Law

18 Copyright © 2009 Pearson Education, Inc. Magnetic flux will change if the area of the loop changes. 29-2 Faraday’s Law of Induction; Lenz’s Law

19 Copyright © 2009 Pearson Education, Inc. Magnetic flux will change if the angle between the loop and the field changes. 29-2 Faraday’s Law of Induction; Lenz’s Law

20 Copyright © 2009 Pearson Education, Inc. 29-2 Faraday’s Law of Induction; Lenz’s Law Conceptual Example 29-3: Induction stove. In an induction stove, an ac current exists in a coil that is the “burner” (a burner that never gets hot). Why will it heat a metal pan but not a glass container?

21 Copyright © 2009 Pearson Education, Inc. Problem Solving: Lenz’s Law 1.Determine whether the magnetic flux is increasing, decreasing, or unchanged. 2.The magnetic field due to the induced current points in the opposite direction to the original field if the flux is increasing; in the same direction if it is decreasing; and is zero if the flux is not changing. 3.Use the right-hand rule to determine the direction of the current. 4.Remember that the external field and the field due to the induced current are separate. 29-2 Faraday’s Law of Induction; Lenz’s Law

22 Copyright © 2009 Pearson Education, Inc. 29-2 Faraday’s Law of Induction; Lenz’s Law Conceptual Example 29-4: Practice with Lenz’s law. In which direction is the current induced in the circular loop for each situation?

23 Copyright © 2009 Pearson Education, Inc. 29-2 Faraday’s Law of Induction; Lenz’s Law Example 29-5: Pulling a coil from a magnetic field. A 100-loop square coil of wire, with side l = 5.00 cm and total resistance 100 Ω, is positioned perpendicular to a uniform 0.600-T magnetic field. It is quickly pulled from the field at constant speed (moving perpendicular to B ) to a region where B drops abruptly to zero. At t = 0, the right edge of the coil is at the edge of the field. It takes 0.100 s for the whole coil to reach the field-free region. Find (a) the rate of change in flux through the coil, and (b) the emf and current induced. (c) How much energy is dissipated in the coil? (d) What was the average force required ( F ext )?

24 Copyright © 2009 Pearson Education, Inc. This image shows another way the magnetic flux can change: 29-3 EMF Induced in a Moving Conductor

25 Copyright © 2009 Pearson Education, Inc. The induced current is in a direction that tends to slow the moving bar – it will take an external force to keep it moving. 29-3 EMF Induced in a Moving Conductor

26 Copyright © 2009 Pearson Education, Inc. The induced emf has magnitude 29-3 EMF Induced in a Moving Conductor This equation is valid as long as B, l, and v are mutually perpendicular (if not, it is true for their perpendicular components).

27 Copyright © 2009 Pearson Education, Inc. 29-3 EMF Induced in a Moving Conductor Example 29-8: Force on the rod. To make the rod move to the right at speed v, you need to apply an external force on the rod to the right. (a) Explain and determine the magnitude of the required force. (b) What external power is needed to move the rod?

28 A wire loop is being pulled away from a current-carrying wire. What is the direction of the induced current in the loop? I 1) clockwise 2) counterclockwise 3) no induced current ConcepTest 29.8a Loop and Wire I

29 into the page decreasing oppose this decrease into the page, clockwise The magnetic flux is into the page on the right side of the wire and decreasing due to the fact that the loop is being pulled away. By Lenz’s law, the induced B field will oppose this decrease. Thus, the new B field points into the page, which requires an induced clockwise current to produce such a B field. I ConcepTest 29.8a Loop and Wire I 1) clockwise 2) counterclockwise 3) no induced current A wire loop is being pulled away from a current-carrying wire. What is the direction of the induced current in the loop?

30 What is the induced current if the wire loop moves in the direction of the yellow arrow? 1) clockwise 2) counterclockwise 3) no induced current I ConcepTest 29.8b Loop and Wire II

31 magnetic flux through the loop is not changing no induced current The magnetic flux through the loop is not changing as it moves parallel to the wire. Therefore, there is no induced current. I 1) clockwise 2) counterclockwise 3) no induced current What is the induced current if the wire loop moves in the direction of the yellow arrow? ConcepTest 29.8b Loop and Wire II

32 Copyright © 2009 Pearson Education, Inc. A generator is the opposite of a motor – it transforms mechanical energy into electrical energy. This is an ac generator: The axle is rotated by an external force such as falling water or steam. The brushes are in constant electrical contact with the slip rings. 29-4 Electric Generators

33 Copyright © 2009 Pearson Education, Inc. 29-4 Electric Generators If the loop is rotating with constant angular velocity ω, the induced emf is sinusoidal: For a coil of N loops,

34 Copyright © 2009 Pearson Education, Inc. 29-4 Electric Generators Example 29-9: An ac generator. The armature of a 60-Hz ac generator rotates in a 0.15-T magnetic field. If the area of the coil is 2.0 x 10 -2 m 2, how many loops must the coil contain if the peak output is to be V 0 = 170 V?

35 Copyright © 2009 Pearson Education, Inc. A dc generator is similar, except that it has a split-ring commutator instead of slip rings. 29-4 Electric Generators

36 Copyright © 2009 Pearson Education, Inc. An electric motor turns because there is a torque on it due to the current. We would expect the motor to accelerate unless there is some sort of drag torque. That drag torque exists, and is due to the induced emf, called a back emf. 29-5 Back EMF and Counter Torque; Eddy Currents

37 Copyright © 2009 Pearson Education, Inc. A similar effect occurs in a generator – if it is connected to a circuit, current will flow in it, and will produce a counter torque. This means the external applied torque must increase to keep the generator turning. 29-5 Back EMF and Counter Torque; Eddy Currents

38 Copyright © 2009 Pearson Education, Inc. Induced currents can flow in bulk material as well as through wires. These are called eddy currents, and can dramatically slow a conductor moving into or out of a magnetic field. 29-5 Back EMF and Counter Torque; Eddy Currents

39 Copyright © 2009 Pearson Education, Inc. A transformer consists of two coils, either interwoven or linked by an iron core. A changing emf in one induces an emf in the other. 29-6 Transformers and Transmission of Power

40 Copyright © 2009 Pearson Education, Inc. 29-6 Transformers and Transmission of Power

41 Copyright © 2009 Pearson Education, Inc. 29-6 Transformers and Transmission of Power Example 29-12: Cell phone charger. The charger for a cell phone contains a transformer that reduces 120-V ac to 5.0-V ac to charge the 3.7-V battery. (It also contains diodes to change the 5.0-V ac to 5.0-V dc.) Suppose the secondary coil contains 30 turns and the charger supplies 700 mA. Calculate (a) the number of turns in the primary coil, (b) the current in the primary, and (c) the power transformed.

42 Copyright © 2009 Pearson Education, Inc. Transformers work only if the current is changing; this is one reason why electricity is transmitted as ac. 29-6 Transformers and Transmission of Power

43 Copyright © 2009 Pearson Education, Inc. 29-6 Transformers and Transmission of Power Example 29-13: Transmission lines. An average of 120 kW of electric power is sent to a small town from a power plant 10 km away. The transmission lines have a total resistance of 0.40 Ω. Calculate the power loss if the power is transmitted at (a) 240 V and (b) 24,000 V.

44 1) 1/4 A 2) 1/2 A 3) 1 A 4) 2 A 5) 5 A Given that the intermediate current is 1 A, what is the current through the lightbulb? ConcepTest 29.12b Transformers II 1 A 120 V 240 V 120 V

45 Power in = Power out 240 V  1 A = 120 V  ??? The unknown current is 2 A The unknown current is 2 A. 1) 1/4 A 2) 1/2 A 3) 1 A 4) 2 A 5) 5 A Given that the intermediate current is 1 A, what is the current through the lightbulb? ConcepTest 29.12b Transformers II 1 A 120 V 240 V 120 V

46 1) greater than 6 V 2) 6 V 3) less than 6 V 4) zero A 6 V battery is connected to one side of a transformer. Compared to the voltage drop across coil A, the voltage across coil B is: AB 6 V ConcepTest 29.12c Transformers III

47 The voltage across B is zero changing dc current The voltage across B is zero. Only a changing magnetic flux induces an emf. Batteries can provide only dc current. 1) greater than 6 V 2) 6 V 3) less than 6 V 4) zero AB 6 V ConcepTest 29.12c Transformers III A 6 V battery is connected to one side of a transformer. Compared to the voltage drop across coil A, the voltage across coil B is:


Download ppt "Copyright © 2009 Pearson Education, Inc. Chapter 29 Electromagnetic Induction and Faraday’s Law."

Similar presentations


Ads by Google