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: CATHY JONES Secondary Math Instruction Specialist Center for Mathematics and Science Education Arkansas NASA Education Resource Center 346 N. West Avenue,

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Presentation on theme: ": CATHY JONES Secondary Math Instruction Specialist Center for Mathematics and Science Education Arkansas NASA Education Resource Center 346 N. West Avenue,"— Presentation transcript:

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2 : CATHY JONES Secondary Math Instruction Specialist Center for Mathematics and Science Education Arkansas NASA Education Resource Center 346 N. West Avenue, Room 202 Fayetteville, Arkansas 72701 (479) 575-3875 (479) 575-5680 (FAX) e-mail: cej001@uark.edu http://www.uark.edu/~k12 info/ Presented by: Related Activities for End-of-Course Algebra I

3 Part I Simplifying radicals: NUTSHELL MATH http://www.nutshellmath.com http://www.nutshellmath.com Independent & Dependent Variables: AIMS Proportional Reasoning…Mystery Mass Slope and Parallel & Perpendicular Line: Modeling Mathematics Perpendicular Lines on a Coordinate Plane Slope Activity Solving Quadratics: Solving Quadratic Equations with Algebra Tiles Geometric Patterns: Building Algebraic Thinking with Progressive Pattern

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6 From AIMS Find the MASS of your objects using INDIRECT measurement. Complete your MYSTERY MASS table. Construct your graphs. Be sure to label and number the axes. Graph a line for each of the two pans. Be sure to show if the data is discrete or continuous. Complete the worksheets.

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11 Factor 2x 2 + 5x + 3 Using algebra tiles, build a rectangle containing the tiles specified in this problem: 2…x 2 -tiles, 5…x-tiles and 3…1-tiles. Here is one possible arrangement: After the pattern is established, it can be seen that the top edge of the pattern (the length) is composed of tiles with dimensions 2x + 3. The side edge of the pattern (the width) is composed of tiles with dimensions x + 1. Consequently, 2x 2 + 5x + 3 = (2x + 3)(x + 1). Factoring with Algebra Tiles Key: - x - 1 1 x

12 From Developing Concepts Using Algebra Tiles 1 1 1 1 1 1 1 1 1 Solve x 2 – 6x – 4 = 3 Choose the tiles to set up the problem and place them in a square, if possible. Use 1…x 2 tile, 6…-x tiles, and 4…-1 tiles. Here is one arrangement: The square on the left is incomplete. The 4…-1 tiles do not complete the square model. Add 4…+1 tiles to both sides of the equation. The ones on the left now are ZERO, so remove them. Now add enough +1 tiles on the left to complete the square model. Add the same to the right of the equal sign to also make a square. Solving Quadratic Equations with Algebra Tiles - x - X = - x - 1 1 1 1 1 - x - 1 1 1 1 1 1 1 1 1 1 1 1 1 Across the bottom see that –x + 3 = 4 and down the right side see that –x + 3 = 4. To the right of the equal sign is 4 2 but it could also be (-4) 2 so solve both equations: -x + 3 = 4 and –x + 3 = -4. Solution: x = -1 or x = 7 1 1 1 1

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