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Chapter 5: Nuclear Chemistry

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Presentation on theme: "Chapter 5: Nuclear Chemistry"— Presentation transcript:

1 Chapter 5: Nuclear Chemistry
Radioactivity Nuclear Equations Radiation Detection Half-Life Medical Applications

2 Average Atomic weight of Hydrogen
Isotopes of Hydrogen Isotopes = Atoms of the same element but having different masses. 1 2 1 3 1 H H H + - + - + - Protium 99.99% Tritium Trace % Deuterium 0.01% Average Atomic weight of Hydrogen = amu

3 Average Atomic weight of C= 12.011 amu
Isotopes of Carbon C 6 12 C 6 13 C 6 14 - - + - + - + - 98.89% 1.11% Trace % Average Atomic weight of C= amu

4 So falls apart (decays) Giving radioactive particles
Radioactive Isotopes 3 1 H C 6 14 - + + - - Hydrogen-3 Carbon-14 Nucleus is unstable So falls apart (decays) Giving radioactive particles

5 Radioactive Isotopes in Medicine
123 53 I Diagnose thyroid function 131 53 I Treat hyperthyroid (destroys cells) 60 27 Co Destroy tumors (g radiation) Tc 43 99m Diagnose bone, tissue (most common)

6 Alpha Decay He a Particle Po Pb Po Pb He + 4 2 210 84 + 82 206 210 84

7 - Beta Decay e C b Particle N n H e -1 14 6 + + - + 7 14 1 1 -1 +
-1 e - 14 6 C b Particle + + - + N 7 14 1 n 1 H -1 e + neutron proton electron

8 - Beta Decay e C b Particle N N e C -1 14 6 + + - + 14 7 14 14 -1 6 7
-1 e - 14 6 C b Particle + + - + N 7 14 14 6 C N 7 14 -1 e +

9 Gamma Decay 99m 43 Tc g decay + + 99 43 Tc 99m 43 Tc Tc 43 99 g +

10 Radiation knocks off an electron
Ionizing Radiation Radiation knocks off an electron - An ion A radical Ions & radicals cause damaging chain reactions

11 Radiation knocks off an electron Ions detected by Counter
Geiger Counter Radiation knocks off an electron - An ion Gas in instrument tube Ions detected by Counter

12 - Radiation: Penetration through Air a b g 2 - 4 cm 200 - 300 cm 500 m
+ 2 - 4 cm b cm - 500 m g

13 - Radiation: Shielding a b g Heavy Cloth Pb, thick concrete
+ Pb, thick concrete Paper Cloth b - g

14 Tissue Penetration Depth
+ 0.05 mm 4-5 mm b - >50 cm g

15 a: Radon gas in Buildings
Nuclear Equations a: Radon gas in Buildings 226 88 222 4 2 He Ra Rn + 86 218 4 2 He Po + 84 Cancer

16 b: Thyroid check & treatment
Nuclear Equations b: Cancer Treatment 60 27 Co 60 -1 e Ni + 28 b: Thyroid check & treatment 131 53 I 131 -1 e Xe + 54

17 Radiation Detection Activity Curie (Ci):
# of disintegrations by of 1g Ra Curie (Ci): 1 Ci = 3.7 x 1010disintegrations sec Becquerel (Bq) 1 Bq = 1 disintegration sec

18 Radiation Detection Absorbed Dose

19 - Radiation Detection: Biological Effect Tissue Penetration Depth a b
+ a - b g Tissue Penetration Depth 0.05 mm mm >50 cm Radiation Absorbed Dose (Rad) (D): 1 rad = 1 x 10-2 J kg tissue 1 rad = 2.4 x 10-3 cal kg tissue

20 - Radiation Detection: Biological Effect Tissue Penetration Depth a b
+ 0.05 mm mm b - >50 cm g Radiation Absorbed Dose (Rad) (D): 1 Gray = 1 J kg tissue 100 rad = 1 Gray

21 Radiation Detection Biological Damage

22 Radiation Equivalent for Man (rem)
(relative biological effectiveness) a RBE 20 1 b g Damage (rem) = absorbed dose (rad) X factor 1 rem = 1 rad x RBE 100 rem = 1 sievert (Sv)

23 Learning Check

24 Learning Check: Solution

25 Annual Radiation Exposure in USA
Total = 170 mrem / yr Cosmic = 40 mrem Air, H2O, Food = 30 mrem X-rays: Chest = 50 mrem Dental = 20 Smoking = 35 mrem TV = 2 mrem Radon = 200 mrem Wood,concrete,bricks = 50 mrem Ground = 15 mrem

26 Annual Radiation Exposure in USA

27 Biological Effects of Radiation
Dose in rem (at one time) 0-25 genetic damage possible but usually undetected decrease # of white blood cells (temporary) mild radiation sickness (vomit, diarrhea, strong decrease # white blood cells) >300 (diarrhea, hair loss, infection) 500 LD50 for humans

28 Biological Effects of Radiation
Dose in rem 300 LD50 for dogs 800 LD50 for rats 50,000 LD50 for Bacterium 100,000 LD50 for Insects 500 LD50 for humans

29 Therapeutic Doses of Radiation
Dose in rem 4, Lymphoma 5,000 – 6,000 Skin cancer 6, Lung cancer 6,000 – Brain Tumor

30 FDA approved killing of bacteria with:
0.3 – 1 kGy ionizing radiation from Co-60 or Cs-137 (gamma producers)

31 Half-Life I t1/2 = Time for 1/2 sample to decay 131 53 5 g 10 g 20 g
8 days 131 53 I 8 days 5 g 10 g 20 g

32 Half-Life I days Co yrs Tc-99m 6 hrs

33 Half-Life I t1/2 = Time for 1/2 sample to decay 131 53 5 g 10 g 20 g
8 days 131 53 I 8 days 5 g 10 g 20 g Youtube: Bill Nye Explains Half Life (1:04)

34 + Positron Emission Tomography (PET) C e b+ Positron B H n e 11 6 +1 +
+1 e + b+ Positron + + B 5 11 1 H 1 n +1 e + proton neutron positron

35 - + Positron Emission Tomography (PET) e C e 2g rays b+ Positron
-1 e electron 11 6 C +1 e - + 2g rays b+ Positron + Detectable g rays  image Shows blood flow + B 5 11 11 6 11 5 B +1 e C + positron

36 - + Positron Emission Tomography (PET) e C e 2g rays b+ Positron
-1 e electron 11 6 C +1 e - + 2g rays b+ Positron + Detectable g rays  image Shows blood flow + B 5 11 +1 e -1 e 2g + positron electron gamma

37 Fission Energy Kr U U n Ba Splitting atoms for Energy 91 36 235 92 236
n Energy + unstable 142 56 Ba Uses: Atomic Bomb Nuclear Power

38 Fission Need critical mass of U-235 to sustain chain rxn to produce enough E for an explosion

39 Fission U-235 Nuclear Power plants: Controlled fission
avoids critical mass

40 > E than from fission But impractical since heat too high
Fusion Combining atoms for Energy + 2 1 H 4 2 He 1 n Deuterium Energy + 100,000,000OC + + Tritium 3 1 H + > E than from fission But impractical since heat too high Uses: Sun Hydrogen Bomb

41 Radiometric Dating N e C Ar Ca 2 K 14 14 -1 6 7 40 40 40 20 19 18 + +
C-14 dating of artifacts (bones, wood,….); t½ = 5760 years 14 6 C N 7 14 -1 e + Issues: Production of C-14 by sun varies in atmosphere. 14CO2(g) amounts vary in atmosphere U-238   Pb-206 U-235   Pb-207 Issues: Assumes all Pb was once U K  Ar (t ½ K-40 = x 109 years) 40 19 K Ar 18 40 40 20 Ca 2 + Issues: Ar(g) solubility Starting amount of K-40

42 Learning Check

43 Learning Check: Solution

44 Videos Video: Frontline NOVA Fukushima: Nuclear Aftershocks (53.41 min)

45 Learning Check: Chromium-55 undergoes beta decay wth a half life of 3.5 minutes. What is the primary identity of the sample after decay? 55 24 Cr +

46 Learning Check: Solution
Chromium-55 undergoes beta decay wth a half life of 3.5 minutes. What is the primary identity of the sample after decay? 55 24 Cr 55 -1 e Mn + 25

47 Learning Check: Chromium-55 undergoes beta decay wth a half life of 3.5 minutes. What is the primary identity of the sample after decay? 55 24 Cr 55 -1 e Mn + 25 If you start with 120 g; How much Cr-55 will be left after 14 minutes?

48 Learning Check: Solution
Chromium-55 undergoes beta decay wth a half life of 3.5 minutes. What is the primary identity of the sample after decay? 55 24 Cr 55 -1 e Mn + 25 If you start with 120 g; How much Cr-55 will be left after 14 minutes? 55 24 Cr t1/2 = 3.5 min 3.5 min 3.5 min 3.5 min (7 min Total) (10.5 min Tot) (14 min Total) 15 g 7.5 g 60 g 30 g 120 g


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