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Fugacity-based environmental modelsmodels Level 1--the equilibrium distribution of a fixed quantity of conserved chemical, in a closed environment at equilibrium,

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Presentation on theme: "Fugacity-based environmental modelsmodels Level 1--the equilibrium distribution of a fixed quantity of conserved chemical, in a closed environment at equilibrium,"— Presentation transcript:

1 Fugacity-based environmental modelsmodels Level 1--the equilibrium distribution of a fixed quantity of conserved chemical, in a closed environment at equilibrium, with no degrading reactions, no advective processes, and no intermedia transport processes (eg. no wet deposition, or sedimentation). Level 2-- describes a situation in which a chemical is continuously discharged at a constant rate and achieves a steady-state and equilibrium condition at which the input and output rates are equal. Degrading reactions and advective processes are the loss or output processes treated. Intermedia transport processes (eg. no wet deposition, or sedimentation) are not quantified. Level 3--A Level III simulation describes a situation which is one step more complex and realistic than the Level II model. Like the Level II model, chemical is continuously discharged at a constant rate and achieves a steady state condition in which input and output rates are equal. The loss processes are degrading reactions and advection. Unlike the Level II model, equilibrium between media is not assumed and, in general, each medium is at a different fugacity. A mass balance applies not only to the system as a whole, but to each compartment. Rates of intermedia transport are calculated using D values which contain information on mass transfer coefficients, areas, deposition and resuspension rates, diffusion rates, and soil runoff rates. It is now essential to define inputs to each medium separately, whereas in Level II only the total input rate was requested.

2 Level 1 program Physical-chemical properties are used to quantify a chemical's behavior in an evaluative environment. Three types of chemicals are treated in this model: chemicals that partition into all media (Type 1), involatile chemicals (Type 2), and chemicals with zero, or near-zero, solubility (Type 3). The Level I Program assumes a simple, evaluative, closed environment with user-defined volumes and densities for the following homogeneous environmental media (or compartments): air, water, soil, sediment, suspended sediment, fish and aerosols. This model is useful for establishing the general features of a new or existing chemical's behaviour. A Level I calculation gives the general impression of the likely media into which a chemical will tend to partition and an indication of relative concentrations in each medium. The results of changes in chemical and environmental properties may be explored.

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4 Inputs and outputs The required input data are: Chemical Properties: chemical name molecular mass data temperature Type 1 chemicals - water solubility - vapor pressure - log Kow - melting point Type 2 and 3 chemicals - partition coefficients Environmental Properties: volumes for all 7 media densities for all 7 media organic carbon content (soil, sediment & suspended sediment only) fish lipid content (Type I chemicals only) Emissions: chemical amount Model Output: partition coefficients (Type 1) Z values fugacity of the system concentrations and amounts for each compartment a summary diagram

5 Z = “fugacity capacity” C = Z  f concentration = Z  fugacity units:mol/m 3 = mol/m 3 Pa  Pa like Henry’s law, Z could also be dimensionless At eqbm, f is equal in all phases: f 1 = f 2 = C 1 /Z 1 = C 2 /Z 2 soK 12 = C 1 /C 2 or Z 2 /Z 1 all these parameters (C, Z, K) depend on T, P, properties of solute/solvent, etc.

6 Z is like C (heat capacity) At equilibrium, all phases will have same fugacity (temperature). C (heat capacity) = amount of heat (energy in J/unit volume)/Temperature Z = amount of chemical (moles per unit volume)/fugacity

7 Types of chemicals Type 1: chemicals that partition into all media –input VP, solubility, program calculates Kh –Z factor of air is one (1/RT to convert units) Type 2: involatile chemicals –VP not available, so input everything as partition coefficients –Z factor of water is one Type 3: chemicals with zero, or near-zero, solubility –Solubility not available, so input everything as K’s –Z factor of air is one (1/RT to convert units) ? All K’s must be internally consistent if everything is at equilibrium

8 Air Water Octanol A gas is a gas is a gas T, P Fresh, salt, ground, pore T, salinity NOM, biological lipids, other solvents Pure Phase (l) or (s) Ideal behavior PoLPoL C sat w C sat o K H = P o L /C sat w K oa KHKH K ow = C sat o /C sat w K ow K oa = C sat o /P o L

9 The fact that these are the same is an artifact, arising because the ratio of Kow to VP is the same for both PCB 52 and pyrene


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