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Modeling of Power Transformers A Static Device. Transformers The transformer enables us to utilize different voltage levels across the system for the.

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Presentation on theme: "Modeling of Power Transformers A Static Device. Transformers The transformer enables us to utilize different voltage levels across the system for the."— Presentation transcript:

1 Modeling of Power Transformers A Static Device

2 Transformers The transformer enables us to utilize different voltage levels across the system for the most economical value. Stepping up the generator voltage to high voltage, is done through power transformers to minimize losses and increase the transmission capacity of the lines. This transmission voltage level is then stepped down in many stages for distribution and utilization purposes.

3 General Theory A transformer contains two or more windings linked by a mutual field. The primary winding is connected to an alternating voltage source. The input current results in an alternating flux whose magnitude depends on the voltage and number of turns of the primary winding. The alternating flux links the secondary winding and induces a voltage in it with a value that depends on the number of turns of the secondary winding.

4 Transformers Basic components of single phase transformer

5 Transformers 5.2 Single phase transformer arrangement

6 Transformers Polarity for transformer

7 Transformers Small transformer construction a) Lamination b) Iron core with winding

8 Transformers Dry-type three-phase transformer

9 Transformers Oil Insulated and cooled transformer

10 Power Transformers

11 Transformation ratio Primary (supply)Secondary (Load)

12 Transformers at no load The no load current I  is needed to supply the no load losses and to magnetize the transformer core.  Im Ic E1E1 II cc E1E1 II II Im

13 Loaded Transformer Z 2 ’ is the load impedance referred to the primary

14 Transformer losses The transformer losses are divided into electrical losses (copper losses) and Magnetic losses (Iron losses). Copper losses in both the primary and secondary windings. Magnetic losses, these losses are divided into eddy current losses and hysteresis losses.

15 Equivalent circuit V 1 : Primary voltage (supply) I 1 : Primary current. V 2 : Secondary voltage (load) I 2: : Secondary current

16 Exact Circuit

17 Approximate Circuit The no load current ranges from 1% to 3% of the full load current. Therefore, the circuit can be simplified to circuit (b). (a) (b)

18 Phasor Diagram

19 Performance Measures The percent regulation The transformer efficiency

20 Voltage Regulation

21 Example A 100-kVA, 400/2000 V, single-phase transformer has the following parameters R1 = 0.01 R2 = 0.25 ohms X1 = 0.03 ohms X2 = 0.75 ohms The transformer supplies a load of 90 kVA at 2000 V and 0.8 PF lagging.  Calculate the primary voltage and current using the simplest equivalent circuit.  Find also the V.R. and efficiency for the transformer


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