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Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x –

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Presentation on theme: "Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x –"— Presentation transcript:

1 Equations – Success if you can do these 3x = 64x + 2 = 3x + 7 x/4 = 25x – 3 = 7 + 3x x + 3 = 173(x + 2) = 12 x – 4 = 134(x + 5) = 32 3x + 4 = 253(2x – 2) = 2(x + 6) 4x – 3 = 174(3x + 5) = 2(x + 15)

2 How to solve the x + 3 = 10 type of equation The 3 and 10 Could be any number

3 You get rid of the + 3 by - 3 But you must subtract 3 from both sides x + 3 =10 x + 3 – 3 = 10 - 3 x = 7

4 For equations like x + 3 = 10 just subtract 3 from both sides x + 3 = 10 x = 10 - 3 x = 7 Like this

5 How to solve the x – 3 = 7 type of equation The 3 and 7 can be any numbers

6 You get rid of the – 3 by + 3 But you must to add 3 to both sides x – 3 = 7 x – 3 + 3 = 7 + 3 x = 10

7 For equations like x – 3 = 7 just add 3 to both sides x – 3 = 7 x – 3 + 3 = 7 + 3 x =10 Like this

8 Try these 1 x + 4 = 167x – 5 = 12 2x + 7 = 218x – 7 = 3 3x + 9 = 359x – 13 = 5 4x + 12 = 2810x – 15 = 6 5x + 6 = 711x – 19 = 7 6x + 23 = 5212x – 12 = 18

9 Remember, always do the same thing to both sides. Felix is checking that you do this properly. x + 3 = 12 x + 3 – 3 = 12 – 3 x = 9


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