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Slide 1 11-4 Surface Area  Surface Area of Right Prisms  Surface Area of a Cylinder  Surface Area of a Pyramid  Surface Area of a Cone  Surface Area.

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Presentation on theme: "Slide 1 11-4 Surface Area  Surface Area of Right Prisms  Surface Area of a Cylinder  Surface Area of a Pyramid  Surface Area of a Cone  Surface Area."— Presentation transcript:

1 Slide 1 11-4 Surface Area  Surface Area of Right Prisms  Surface Area of a Cylinder  Surface Area of a Pyramid  Surface Area of a Cone  Surface Area of a Sphere

2 Slide 2 Surface Area of Right Prisms Lateral area: the sum of the areas of the lateral faces Surface area: The sum of the lateral surface area and the area of the bases.

3 Slide 3 Cube Surface area = 6e 2 e = edge line Find the surface area of a cube with an edge line of 1½ yards Example: (6)(1.5) 2 (6)(2.25) 13.5 yds 2 or 13 ½ yrds 2

4 Slide 4 Right Pentagonal Prism Surface area = ph + 2B, p = the perimeter of the base h = the height of the prism B = the area of the base

5 Slide 5 Example Find the surface area of the prism. Answer: p = 6 x 4 = 24 h = 10 2B = SA = (24)(10) + SA = 240 + SA ≈ 243.46

6 Slide 6 Surface Area of a Cylinder As the number of sides of a right regular prism increases then the figure approaches the shape of a right regular cylinder.

7 Slide 7 Right circular cylinder Surface area = 2πr 2 + 2πrh Example: Find the surface area of a right circular cylinder with r = 8.7 and h = 5.3

8 Slide 8 Surface Area of a Pyramid Surface area = n(½ b l) + B n = the number of faces l = the slant height B = the area of the base.

9 Slide 9 Example Find the surface area of the pyramid. Answer: n = number of sides B = Area of the base Surface area = n(½ b l) + B S.A. = (4)(½)(16)(15) + (16)(16) S.A. = 480 + 256 S.A. = 736 cm 2

10 Slide 10 Surface Area of a Cone Cone Surface area = π r 2 + π r  r = radius of the cone  is the slant height.

11 Slide 11 Example Find the surface area of the pyramid. Answer: Surface area = π r 2 + π r l S.A. = (π)(6 2) + (π)(12)(6) S.A. = π 36 + π 72 S.A. = 72 π + 36 π S.A. = 226.08 + 113.04 S.A. ≈ 339.12

12 Slide 12 Surface Area of a Sphere Sphere Surface area = 4πr 2 Example: Find the surface area of a sphere with r = 2/3 in Surface area = 4π r 2 S.A. = (4)(π)(2/3) 2 S.A. = (4)(3.14)(.67) 2 S.A. = (4)(3.14)(.4489) S.A. ≈ 5.6 in 2

13 Slide 13 HOMEWORK 11-4 Pages 793 - 795 # 1, 5, 9, 15


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