1. Objectives The student will be able to: Factor using the greatest common factor (GCF). SOL: A.2c Designed by Skip Tyler, Varina High School

2. Review: What is the GCF of 25a 2 and 15a? 5a Let’s go one step further… 1) FACTOR 25a 2 + 15a. Find the GCF and divide each term 25a 2 + 15a = 5a( ___ + ___ ) Check your answer by distributing. 5a3

3. 2) Factor 18x 2 - 12x 3. Find the GCF 6x 2 Divide each term by the GCF 18x 2 - 12x 3 = 6x 2 ( ___ - ___ ) Check your answer by distributing. 32x

4. 3) Factor 28a 2 b + 56abc 2. GCF = 28ab Divide each term by the GCF 28a 2 b + 56abc 2 = 28ab ( ___ + ___ ) Check your answer by distributing. 28ab(a + 2c 2 ) a2c 2

5. Factor 20x 2 - 24xy 1.x(20 – 24y) 2.2x(10x – 12y) 3.4(5x 2 – 6xy) 4.4x(5x – 6y)

6. 5) Factor 28a 2 + 21b - 35b 2 c 2 GCF = 7 Divide each term by the GCF 28a 2 + 21b - 35b 2 c 2 = 7 ( ___ + ___ - ____ ) Check your answer by distributing. 7(4a 2 + 3b – 5b 2 c 2 ) 4a 2 5b 2 c 2 3b

7. Factor 16xy 2 - 24y 2 z + 40y 2 1.2y 2 (8x – 12z + 20) 2.4y 2 (4x – 6z + 10) 3.8y 2 (2x - 3z + 5) 4.8xy 2 z(2 – 3 + 5)