2. Chapter 10 Rotational Motion

3. 2

4. 3 10.1 Rigid Object A rigid object is one that is nondeformable The relative locations of all particles making up the object remain constant All real objects are deformable to some extent, but the rigid object model is very useful in many situations where the deformation is negligible

5. 4 Angular Position Axis of rotation is the center of the disc Choose a fixed reference line Point P is at a fixed distance r from the origin Fig 10.1

6. 5 Angular Position, 2 Point P will rotate about the origin in a circle of radius r Every particle on the disc undergoes circular motion about the origin, O Polar coordinates are convenient to use to represent the position of P (or any other point) P is located at (r,  ) where r is the distance from the origin to P and  is the measured counterclockwise from the reference line

7. 6 Angular Position, 3 As the particle moves, the only coordinate that changes is  As the particle moves through  it moves though an arc length s. The arc length and r are related: s =  r Fig 10.1

8. 7 Radian This can also be expressed as  is a pure number, but commonly is given the artificial unit, radian One radian is the angle subtended by an arc length equal to the radius of the arc

9. 8 Conversions Comparing degrees and radians Converting from degrees to radians

10. 9 Angular Position, final We can associate the angle  with the entire rigid object as well as with an individual particle Remember every particle on the object rotates through the same angle The angular position of the rigid object is the angle  between the reference line on the object and the fixed reference line in space The fixed reference line in space is often the x- axis

11. 10 Angular Displacement The angular displacement is defined as the angle the object rotates through during some time interval This is the angle that the reference line of length r sweeps out Fig 10.2

12. 11 Average Angular Speed The average angular speed, , of a rotating rigid object is the ratio of the angular displacement to the time interval

13. 12 Instantaneous Angular Speed The instantaneous angular speed is defined as the limit of the average speed as the time interval approaches zero

14. 13 Angular Speed, final Units of angular speed are radians/sec rad/s or s -1 since radians have no dimensions Angular speed will be positive if  is increasing (counterclockwise) Angular speed will be negative if  is decreasing (clockwise)

15. 14 Average Angular Acceleration The average angular acceleration, , of an object is defined as the ratio of the change in the angular speed to the time it takes for the object to undergo the change:

16. 15 Instantaneous Angular Acceleration The instantaneous angular acceleration is defined as the limit of the average angular acceleration as the time goes to 0 Units of angular acceleration are rad/s 2 or s -2 since radians have no dimensions

17. 16 Angular Motion, General Notes When a rigid object rotates about a fixed axis in a given time interval, every portion on the object rotates through the same angle in a given time interval and has the same angular speed and the same angular acceleration So  all characterize the motion of the entire rigid object as well as the individual particles in the object

18. 17 Directions, details Strictly speaking, the speed and acceleration (  are the magnitudes of the velocity and acceleration vectors The directions are actually given by the right-hand rule Fig 10.3

19. 18 Directions, final The direction of is along the axis of rotation By convention, its direction is out of the plane of the diagram when the rotation is counterclockwise its direction is into of the plane of the diagram when the rotation is clockwise The direction of is the same as if the angular speed is increasing and antiparallel if the speed is decreasing

20. 19 10.2 Rotational Kinematics Under constant angular acceleration, we can describe the motion of the rigid object using a set of kinematic equations These are similar to the kinematic equations for linear motion The rotational equations have the same mathematical form as the linear equations

21. 20 Rotational Kinematic Equations

22. 21 Comparison Between Rotational and Linear Equations

23. 22

24. 23

25. 24 10.3 Relationship Between Angular and Linear Quantities Displacements Speeds Accelerations Every point on the rotating object has the same angular motion Every point on the rotating object does not have the same linear motion

26. 25 Speed Comparison The linear velocity is always tangent to the circular path called the tangential velocity The magnitude is defined by the tangential speed Fig 10.4

27. 26 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 10.4

28. 27 Acceleration Comparison The tangential acceleration is the derivative of the tangential velocity Fig 10.5

29. 28 Speed and Acceleration Note All points on the rigid object will have the same angular speed, but not the same tangential speed All points on the rigid object will have the same angular acceleration, but not the same tangential acceleration The tangential quantities depend on r, and r is not the same for all points on the object

30. 29 Centripetal Acceleration An object traveling in a circle, even though it moves with a constant speed, will have an acceleration Therefore, each point on a rotating rigid object will experience a centripetal acceleration

31. 30 Resultant Acceleration The tangential component of the acceleration is due to changing speed The centripetal component of the acceleration is due to changing direction Total acceleration can be found from these components

32. 31 10.4 Rotational Kinetic Energy An object rotating about some axis with an angular speed, , has rotational kinetic energy even though it may not have any translational kinetic energy Each particle has a kinetic energy of K i = 1/2 m i v i 2 Since the tangential velocity depends on the distance, r, from the axis of rotation, we can substitute v i =  i r

33. 32 Fig 10.6

34. 33 Rotational Kinetic Energy, cont The total rotational kinetic energy of the rigid object is the sum of the energies of all its particles Where I is called the moment of inertia

35. 34 Rotational Kinetic Energy, final There is an analogy between the kinetic energies associated with linear motion (K = 1/2 mv 2 ) and the kinetic energy associated with rotational motion (K R = 1/2 I  2 ) Rotational kinetic energy is not a new type of energy, the form is different because it is applied to a rotating object The units of rotational kinetic energy are Joules (J)

36. 35 Moment of Inertia The definition of moment of inertia is The dimensions of moment of inertia are ML 2 and its SI units are kg. m 2 We can calculate the moment of inertia of an object more easily by assuming it is divided into many small volume elements, each of mass  m i

37. 36 Moment of Inertia, cont We can rewrite the expression for I in terms of  m With the small volume segment assumption, If  is constant, the integral can be evaluated with known geometry, otherwise its variation with position must be known

38. 37

39. 38

40. 39

41. 40

42. 41

43. 42

44. 43 Fig 10.7

45. 44

46. 45

47. 46

48. 47

49. 48 Moment of Inertia of a Uniform Solid Cylinder Divide the cylinder into concentric shells with radius r, thickness dr and length L Then for I Fig 10.8

50. 49

51. 50

52. 51

53. 52 Fig 10.9

54. 53

55. 54

56. 55

57. 56 10.5 Torque Torque, , is the tendency of a force to rotate an object about some axis Torque is a vector  = r F sin  = F d F is the force  is the angle the force makes with the horizontal d is the moment arm (or lever arm)

58. 57 Torque, cont The moment arm, d, is the perpendicular distance from the axis of rotation to a line drawn along the direction of the force d = r sin  Fig 10.10

59. 58 Torque, final The horizontal component of the force (F cos  ) has no tendency to produce a rotation Torque will have direction If the turning tendency of the force is counterclockwise, the torque will be positive If the turning tendency is clockwise, the torque will be negative

60. 59 Net Torque The force F 1 will tend to cause a counterclockwise rotation about O The force F 2 will tend to cause a clockwise rotation about O  net      F 1 d 1 – F 2 d 2 Fig 10.11

61. 60 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 10.11

62. 61 Torque vs. Force Forces can cause a change in linear motion Described by Newton’s Second Law Forces can cause a change in rotational motion The effectiveness of this change depends on the force and the moment arm The change in rotational motion depends on the torque

63. 62 Torque Units The SI units of torque are N. m Although torque is a force multiplied by a distance, it is very different from work and energy The units for torque are reported in N. m and not changed to Joules

64. 63 Torque as a Vector Product Torque is the vector product or cross product of two other vectors Fig 10.12

65. 64 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 10.12

66. 65 Vector Product, General Given any two vectors, and The vector product is defined as a third vector, whose magnitude is The direction of C is given by the right-hand rule Fig 10.13

67. 66 Properties of Vector Product The vector product is not commutative If is parallel (  = 0 o or 180 o ) to then This means that If is perpendicular to then

68. 67 Vector Products of Unit Vectors The signs are interchangeable For example,

69. 68

70. 69 Fig 10.14

71. 70

72. 71

73. 72

74. 73

75. 74 10.6 The Rigid Object In Equilibrium Fig 10.15 (a) & (b)

76. 75 Problem Solving Strategy – Rigid Object in Equilibrium Conceptualize Identify the forces acting on the object Think about the effect of each force on the rotation of the object, if the force was acting by itself Categorize Confirm the object is a rigid object in equilibrium

77. 76 Problem Solving Strategy – Rigid Object in Equilibrium, 2 Analyze Draw a free body diagram Label all external forces acting on the object Resolve all the forces into rectangular components Apply the first condition of equilibrium

78. 77 Problem Solving Strategy – Rigid Object in Equilibrium, 3 Analyze, cont Choose a convenient axis for calculating torques Choose an axis that simplifies your calculations Apply the second condition of equilibrium Solve the simultaneous equations Finalize Be sure your results are consistent with the free body diagram Check calculations

79. 78

80. 79 Fig 10.16(a)

81. 80

82. 81 Fig 10.16(b) & (c)

83. 82

84. 83

85. 84

86. 85

87. 86

88. 87

89. 88 Fig 10.17

90. 89

91. 90

92. 91

93. 92 10.7 Torque and Angular Acceleration on a Particle The magnitude of the torque produced by a force around the center of the circle is  = F t r = (ma t ) r The tangential acceleration is related to the angular acceleration  =  (ma t ) r =  (mr  ) r =  (mr 2 )  Since mr 2 is the moment of inertia of the particle,  = I  The torque is directly proportional to the angular acceleration and the constant of proportionality is the moment of inertia

94. 93

95. 94 Fig 10.18(a) & (b)

96. 95

97. 96

98. 97

99. 98

100. 99

101. 100 Work in Rotational Motion Find the work done by a force on the object as it rotates through an infinitesimal distance ds = r d  The radial component of the force does no work because it is perpendicular to the displacement Fig 10.19

102. 101 Work in Rotational Motion, cont Work is also related to rotational kinetic energy: This is the same mathematical form as the work-kinetic energy theorem for translation If an object is both rotating and translating, W =  K +  K R

103. 102 Power in Rotational Motion The rate at which work is being done in a time interval dt is the power This is analogous to P = Fv in a linear system

104. 103

105. 104

106. 105 Fig 10.20

107. 106

108. 107

109. 108 10.8 Angular Momentum The instantaneous angular momentum of a particle relative to the origin O is defined as the cross product of the particle’s instantaneous position vector and its instantaneous linear momentum Fig 10.21

110. 109 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 10.21

111. 110 Torque and Angular Momentum The torque is related to the angular momentum Similar to the way force is related to linear momentum This is the rotational analog of Newton’s Second Law The torque and angular momentum must be measured about the same origin This is valid for any origin fixed in an inertial frame

112. 111 More About Angular Momentum The SI units of angular momentum are (kg. m 2 )/ s The axes used to define the torque and the angular momentum must be the same When several forces are acting on the object, the net torque must be used

113. 112 Angular Momentum of a System of Particles The total angular momentum of a system of particles is defined as the vector sum of the angular momenta of the individual particles Differentiating with respect to time

114. 113 Angular Momentum of a Rotating Rigid Object, cont To find the angular momentum of the entire object, add the angular momenta of all the individual particles This is analogous to the translational momentum of p = m v

115. 114 Summary of Useful Equations

116. 115

117. 116

118. 117

119. 118

120. 119

121. 120 10.9 Conservation of Angular Momentum The total angular momentum of a system is conserved if the resultant external torque acting on the system is zero Net torque = 0 -> means that the system is isolated For a system of particles, L tot =  L n = constant

122. 121 Conservation of Angular Momentum, cont If the mass of an isolated system undergoes redistribution, the moment of inertia changes The conservation of angular momentum requires a compensating change in the angular velocity I i  i = I f  f This holds for rotation about a fixed axis and for rotation about an axis through the center of mass of a moving system The net torque must be zero in any case

123. 122 Conservation Law Summary For an isolated system - (1) Conservation of Energy: E i = E f (2) Conservation of Linear Momentum: (3) Conservation of Angular Momentum:

124. 123 Gyroscope Angular momentum is the basis of the operation of a gyroscope A gyroscope is a spinning object used to control or maintain the orientation in space of the object or a system containing the object Gyroscopes undergo precessional motion The symmetry axis rotates, sweeping out a cone

125. 124 Fig 10.22

126. 125 Fig 10.23

127. 126 Fig 10.24

128. 127

129. 128

130. 129

131. 130

132. 131

133. 132

134. 133 10.10 Precessional Motion of a Gyroscope The external forces acting on the top are the normal and the gravitational forces The torque due to the gravitational force is in the xy plane Only the direction of the angular momentum changes, causing the precession Fig 10.25

135. 134 10.11 Rolling Object The red curve shows the path moved by a point on the rim of the object This path is called a cycloid The green line shows the path of the center of mass of the object Fig 10.26

136. 135 Pure Rolling Motion The surfaces must exert friction forces on each other Otherwise the object would slide rather than roll In pure rolling motion, an object rolls without slipping In such a case, there is a simple relationship between its rotational and translational motions

137. 136 Rolling Object, Center of Mass The velocity of the center of mass is The acceleration of the center of mass is

138. 137 Rolling Object, Other Points A point on the rim, P, rotates to various positions such as Q and P ’ At any instant, the point on the rim located at point P is at rest relative to the surface since no slipping occurs Fig 10.27

139. 138 Total Kinetic Energy of a Rolling Object The total kinetic energy of a rolling object is the sum of the translational energy of its center of mass and the rotational kinetic energy about its center of mass K = 1/2 I CM  2 + 1/2 Mv CM 2

140. 139 Parallel-Axis Theorem For an arbitrary axis, the parallel-axis theorem often simplifies calculations The theorem states I p = I CM + MD 2 I p is about any axis parallel to the axis through the center of mass of the object I CM is about the axis through the center of mass D is the distance from the center of mass axis to the arbitrary axis

141. 140 Total Kinetic Energy, Example Accelerated rolling motion is possible only if friction is present between the sphere and the incline The friction produces the net torque required for rotation

142. 141 Total Kinetic Energy, Example cont Despite the friction, no loss of mechanical energy occurs because the contact point is at rest relative to the surface at any instant Let U = 0 at the bottom of the plane K f + U f = K i + U i K f = 1/2 (I CM / R 2 ) v CM 2 + 1/2 Mv CM 2 U i = Mgh U f = K i = 0

143. 142

144. 143 Fig 10.28

145. 144

146. 145

147. 146

148. 147 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 10.28

149. 148 10.12 Turning a Spacecraft Here the gyroscope is not rotating The angular momentum of the spacecraft about its center of mass is zero Fig 10.29(a)

150. 149 Turning a Spacecraft, cont Now assume the gyroscope is set into motion The angular momentum must remain zero The spacecraft will turn in the direction opposite to that of the gyroscope Fig 10.29(b)