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Review for Test #3  Responsible for: - Chapters 9 (except 9.8), 10, and 11 (except 11.9) - The spring (6.2, 7.3, 8.2-8.3) - Problems worked in class,

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Presentation on theme: "Review for Test #3  Responsible for: - Chapters 9 (except 9.8), 10, and 11 (except 11.9) - The spring (6.2, 7.3, 8.2-8.3) - Problems worked in class,"— Presentation transcript:

1 Review for Test #3  Responsible for: - Chapters 9 (except 9.8), 10, and 11 (except 11.9) - The spring (6.2, 7.3, 8.2-8.3) - Problems worked in class, class notes - Homework assignments  Test format: - 13 problems, 11 simple, 1 intermediate, 1 advanced, 7.7 pts each - Time: 50 minutes only  Test materials: - Pencil, paper, eraser, and calculator - No formulae sheet - Closed textbook and notes

2 Material Covered  Chapter 9: Impulse and Momentum - Impulse-momentum theorem - Conservation of Linear momentum - 1 and 2D collisions - Center of mass  Chapter 10: Rotational Kinematics and Energy - , , , a r, and a t - Rotational kinematic equations - Rolling motion (tire) - Moment of inertia - Rotational work and kinetic energy - Conservation of Energy with rotation

3 Example Problem, Grades returned by next Monday? A 0.200-m bar with a mass of 0.750 kg is released from rest in the vertical position. A spring is  Chapter 11: Rotational Dynamics and Static Equilibrium - ,  =I  - Applications of  =0,  F=0 - Center of gravity - Angular momentum, conservation of...  The Spring - Force due to a spring (Hooke’s Law) - Work and potential energy of a spring

4 attached, initially unstrained, and has a spring constant of 25.0 N/m. Find the tangential speed with which the free end strikes the horizontal surface. (drawing to be provided) Solution: Bar rotating with axis at one end  rotational KE, no translational KE Bar falls from some height  gravitional PE (U g ) A spring is attached to bar  spring PE (U s ) Bar  rigid body  need moment of inertia  Use Conservation of Energy

5 y i  h since this would mean all mass of rod is at y i =h, but mass is distributed. So, take mass to be located at center of gravity

6 From geometry of problem Return to Conservation of Energy and solve for v t


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