1. MOTION

2. How do you know if something is in motion?

3. How do you know if something is in motion?
Motion – changing position in space.

4. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary

5. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving).

6. The Earth is moving, so everything on Earth is in motion.

7. The Earth is moving, so everything on Earth is in motion.
Two ways the Earth moves are:
1. Rotation

8. The Earth is moving, so everything on Earth is in motion.
Two ways the Earth moves are:
1. Rotation (spinning)

9. The Earth is moving, so everything on Earth is in motion.
Two ways the Earth moves are:
1. Rotation (spinning) – this causes day and night.

10. The Earth is moving, so everything on Earth is in motion.
Two ways the Earth moves are:
Rotation (spinning) – this causes day and night.
Revolution

11. The Earth is moving, so everything on Earth is in motion.
Two ways the Earth moves are:
Rotation (spinning) – this causes day and night.
Revolution (going around the Sun) -

12. The Earth is moving, so everything on Earth is in motion.
Two ways the Earth moves are:
Rotation (spinning) – this causes day and night.
Revolution (going around the Sun) – this causes the seasons to change.

13. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:

14. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:
TIME

15. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:
TIME
DISTANCE

16. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:
TIME
DISTANCE
SPEED

17. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:
TIME
DISTANCE
SPEED (velocity) – how fast an object is moving

18. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:
TIME
DISTANCE
SPEED (velocity) – how fast an object is moving d s t
Speed formula

19. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:
TIME
DISTANCE
SPEED (velocity) – how fast an object is moving
E.g. If you fly 660 Km in 60 minutes, what is your speed? d s t

20. How do you know if something is in motion?
Motion – changing position in space.
Reference Point – an object that is considered stationary (not moving). We compare moving objects to a reference point so that we can make measurements of its motion:
TIME
DISTANCE
SPEED (velocity) – how fast an object is moving
E.g. If you fly 660 Km in 60 minutes, what is your speed?
2) If you travel 40 Km/h for 5 hours, how far will you go? d s t

21. Acceleration -

22. Acceleration – changing something about your motion:

23. Acceleration – changing something about your motion: 1. speeding up

24. Acceleration – changing something about your motion: 1. speeding up 2. slowing down

25. Acceleration – changing something about your motion: 1. speeding up slowing down changing direction

26. Acceleration – changing something about your motion: 1. speeding up slowing down are all ways to accelerate 3. changing direction

27. Acceleration – changing something about your motion: 1. speeding up slowing down are all ways to accelerate 3. changing direction
Constant speed -

28. Acceleration – changing something about your motion: 1. speeding up slowing down are all ways to accelerate 3. changing direction
Constant speed – keeping the same speed all the time.

29. Acceleration – changing something about your motion: 1. speeding up slowing down are all ways to accelerate 3. changing direction
Constant speed – keeping the same speed all the time. A graph showing constant speed would have
Distance
T i m e

30. Acceleration – changing something about your motion: 1. speeding up slowing down are all ways to accelerate 3. changing direction
Constant speed – keeping the same speed all the time. A graph showing constant speed would have a straight line.
Distance
T i m e

31. 3 People Running a Course80 70
Greg
Ray
Bob 60 50
Distance (meters) 40 30 20 10 2 4 6 8 10 12 14 16 18 20 22 24
Time (seconds)

32. Varying the speed will give a curve with different slopes.
Distance
T i m e

33. Varying the speed will give a curve with different slopes.
Distance
faster
faster
T i m e

34. Varying the speed will give a curve with different slopes.
Distance
slower
faster
faster
slower
T i m e

35. Acceleration has a formula too:

36. Acceleration has a formula too (when speed changes):DS
DS = change in speed a t

37. Acceleration has a formula too (when speed changes):DS
DS = change in speed a t
(DS = S2 – S1)

38. Acceleration has a formula too (when speed changes):DS
DS = change in speed a t
(DS = S2 – S1)
a = rate of acceleration

39. Acceleration has a formula too (when speed changes):DS
DS = change in speed a t
(DS = S2 – S1)
a = rate of acceleration
t = time

40. Acceleration has a formula too (when speed changes):DS
DS = change in speed a t
(DS = S2 – S1)
a = rate of acceleration
t = time
A positive acceleration means that the object is getting faster;

41. Acceleration has a formula too (when speed changes):DS
DS = change in speed a t
(DS = S2 – S1)
a = rate of acceleration
t = time
A positive acceleration means that the object is getting faster; a negative acceleration means slowing down.

42. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? DS a t

43. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? DS a t

44. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? DS a t S1

45. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? S2 S1 DS a t

46. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? S2 S1
time DS a t

47. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? S2 S1
time DS a t
DS = S2 – S1

48. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? S2 S1
time DS a t
DS = S2 – S1 = 100 – 80 = 20 m/s

49. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? S2 S1
time DS a t
DS = S2 – S1 = 100 – 80 = 20 m/s DS
a = t

50. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? S2 S1
time DS a t
DS = S2 – S1 = 100 – 80 = 20 m/s DS 20
a = = t 4

51. A car going 80 m/s speeds up to 100 m/s in 4 seconds
A car going 80 m/s speeds up to 100 m/s in 4 seconds. What is its rate of acceleration? S2 S1
time DS a t
DS = S2 – S1 = 100 – 80 = 20 m/s DS 20
a = =
= 5 m/s2 t 4

52. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? DS a t

53. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? DS a t

54. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 DS a t

55. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2 DS a t

56. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2
time DS a t

57. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2
time DS a t
DS = S2 – S1 =

58. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2
time DS a t
DS = S2 – S1 = 20 – 80 =

59. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2
time DS a t
DS = S2 – S1 = 20 – 80 = m/s

60. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2
time DS a t
DS = S2 – S1 = 20 – 80 = m/s DS
a = t

61. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2
time DS a t
DS = S2 – S1 = 20 – 80 = m/s DS
- 60 m/s
a = = t
5 sec.

62. A car going 80 m/s slows down to 20 m/s in 5 seconds
A car going 80 m/s slows down to 20 m/s in 5 seconds. What is its rate of acceleration? S1 S2
time DS a t
DS = S2 – S1 = 20 – 80 = m/s DS
- 60 m/s
a = =
= -12 m/s2 t
5 sec.

63. DS a t Solve for the new speed:
1. A stopped car accelerates at a rate of 4 m/s2. What is its new speed after 6 seconds? DS a t

64. DS a t Solve for the new speed:
2. A train going at a speed of 30 m/s starts to accelerate at a rate of 2 m/s2. What is its new speed after 12 seconds? DS a t

65. DS a t Solve for the new speed:
3. A train going at a speed of 30 m/s starts to accelerate at a rate of -2 m/s2. What is its new speed after 10 seconds? DS a t

66. DS a t Solve for the new speed:
4. A car going at a speed of 40 m/s starts to accelerate at a rate of 3 m/s2. What is its new speed after 5 seconds? DS a t

67. DS a t Solve for the new speed:
5. A motorcycle is going at a speed of 50 m/s. The bridge ahead is out. If it starts to accelerate at a rate of -12 m/s2 for 4 seconds it has left before going off the bridge, will he stop in time? DS a t

68. Galileo

69. Galileo found that all objects should fall at the ____ rate.

70. Galileo found that all objects should fall at the same rate.

71. Galileo studied falling objects and discovered that all things fall at the same rate, despite their weight. .

72. Galileo studied falling objects and discovered that all things fall at the same rate, despite their weight. .
Both objects fell at the same rate.

73. Galileo found that all objects should fall at the same rate
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects,

74. Galileo found that all objects should fall at the same rate
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their _____________

75. Galileo found that all objects should fall at the same rate
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)

76. Having more surface area means that there is more air pushing against the parachute, slowing it down.

77. Galileo found that all objects should fall at the same rate
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)
He also found that objects speed up as they fall.

78. Galileo found that all objects should fall at the same rate
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)
He also found that objects speed up as they fall.
If air friction wasn’t a factor, all objects would accelerate toward Earth by 9.8 m/s2 (g).

79. Galileo found that all objects should fall at the same rate
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)
He also found that objects speed up as they fall.
If air friction wasn’t a factor, all objects would accelerate toward Earth by 9.8 m/s2 (g).
If an object falls for some time, its speed is 9.8 x time it fell.
S = g x t

80. Galileo found that all objects should fall at the same rate
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)
He also found that objects speed up as they fall.
Another thing he figured out was why satellites (like the moon) stay in orbit.

81. He also found that objects speed up as they fall.
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)
He also found that objects speed up as they fall.
Another thing he figured out was why satellites (like the moon) stay in orbit. They are pulled toward
pull of gravity
the earth, but their forward motion pulls them away,

82. He also found that objects speed up as they fall.
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)
He also found that objects speed up as they fall.
Another thing he figured out was why satellites (like the moon) stay in orbit. They are pulled toward
forward motion
pull of gravity
the earth, but their forward motion pulls them away, so they keep going around it.

83. He also found that objects speed up as they fall.
Galileo found that all objects should fall at the same rate. Air friction slows down falling objects, some more than others because of their surface area. (parachute)
He also found that objects speed up as they fall.
Another thing he figured out was why satellites (like the moon) stay in orbit. They are pulled toward
forward motion
pull of gravity
orbit
the earth, but their forward motion pulls them away, so they keep going around it.

84. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?

85. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?

86. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
mass
speed
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?
length
time

87. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
mass
speed
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?
length
time
What is the question asking?

88. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
mass
speed
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?
length
time
What is the question asking? Distance

89. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
mass
speed
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?
length
time
What is the question asking? Distance
d = s x t

90. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
mass
speed
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?
length
time
What is the question asking? Distance
d = s x t

91. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
mass
speed
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?
length
time
What is the question asking? Distance
d = s x t = 45 x 3

92. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
mass
speed
Ex. #1: A car with a mass of 835 Kg is going 45 Km/hr along a 2500 Km road for 3 hours. How far did the car travel?
length
time
What is the question asking? Distance
d = s x t = 45 x 3 = 135 Km

93. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration?

94. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration?
What is the question asking?

95. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration?
What is the question asking? acceleration

96. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration?
What is the question asking? acceleration Ds
a = t

97. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t s1
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration? s2
time
What is the question asking? acceleration
Ds s2 – s1
a =
t t

98. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t s1
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration? s2
time
What is the question asking? acceleration
Ds s2 – s
a =
t t

99. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t s1
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration? s2
time
What is the question asking? acceleration
Ds s2 – s –
a =
t t

100. Using the Correct Formula:d Ds
Ds = s2 – s1
s(falling) = g x t s t a t s1
Ex. #2: A car with a mass of 835 Kg is going 20 m/s along a 14 foot wide road. If it slows down to 5 m/s in 3 seconds, what’s its rate of acceleration? s2
time
What is the question asking? acceleration
Ds s2 – s –
a =
-5 m/s2
t t

101. FORCES & MOTION

102. FORCES & MOTION
Force – a lift, push, pull, etc. that can cause a change in an object’s motion, shape or energy level.

103. FORCES & MOTION
Force – a lift, push, pull, etc. that can cause a change in an object’s motion, shape or energy level.
There are balanced forces, which are equal in strength, but

104. FORCES & MOTION
Force – a lift, push, pull, etc. that can cause a change in an object’s motion, shape or energy level.
There are balanced forces, which are equal in strength, but opposite in direction.

105. FORCES & MOTION
Force – a lift, push, pull, etc. that can cause a change in an object’s motion, shape or energy level.
There are balanced forces, which are equal in strength, but opposite in direction. The object does not accelerate with balanced forces.

106. FORCES & MOTION
Force – a lift, push, pull, etc. that can cause a change in an object’s motion, shape or energy level.
There are balanced forces, which are equal in strength, but opposite in direction. The object does not accelerate with balanced forces.

107. An object can have unbalanced forces working on it, and they would make the object __________

108. An object can have unbalanced forces working on it, and they would make the object accelerate.

109. An object can have unbalanced forces working on it, and they would make the object accelerate.
Forces are measured in Newtons.

110. An object can have unbalanced forces working on it, and they would make the object accelerate.
Forces are measured in Newtons. (1 Newton is about the amount of force needed to hold up a stick of butter.)

111. An object can have unbalanced forces working on it, and they would make the object accelerate.
Forces are measured in Newtons. (1 Newton is about the amount of force needed to hold up a stick of butter.)
Sir Isaac Newton developed his “3 Laws of Motion” while observing the world around him.

112. Newton’s Laws of Motion:

113. Newton’s Laws of Motion:
First Law of Motion – “inertia”

114. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest,

115. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion.

116. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion. Neither would change unless acted upon by an unbalanced force.

117. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion. Neither would change unless acted upon by an unbalanced force.
Inertia is an object’s tendency to maintain its motion.

118. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion. Neither would change unless acted upon by an unbalanced force.
Inertia is an object’s tendency to maintain its motion.
What is the outside force that slows things down?

119. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion. Neither would change unless acted upon by an unbalanced force.
Inertia is an object’s tendency to maintain its motion.
What is the outside force that slows things down?
Friction

120. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion. Neither would change unless acted upon by an unbalanced force.
Inertia is an object’s tendency to maintain its motion.
What is the outside force that slows things down?
Friction – two surfaces rubbing together.

121. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion. Neither would change unless acted upon by an unbalanced force.
Inertia is an object’s tendency to maintain its motion.
What is the outside force that slows things down?
Friction – two surfaces rubbing together.
There may be other forces that accelerate objects also.

122. Newton’s Laws of Motion:
First Law of Motion – “inertia”
An object at rest tends to stay at rest, while an object in motion tends to stay in motion. Neither would change unless acted upon by an unbalanced force.
Inertia is an object’s tendency to maintain its motion.
What is the outside force that slows things down?
Friction – two surfaces rubbing together.
There may be other forces that accelerate objects also.
Seat belts are “anti-inertia” devices.

124. Second Law of Motion – “F = m x a”

125. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than

126. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than an object with less mass.

127. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than an object with less mass. (E.g. it takes more of a push to get a car going than a bike.)

128. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than an object with less mass. (E.g. it takes more of a push to get a car going than a bike.)
If the same force is applied to 2 different objects, the one with a smaller mass will accelerate _____.

129. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than an object with less mass. (E.g. it takes more of a push to get a car going than a bike.)
If the same force is applied to 2 different objects, the one with a smaller mass will accelerate more.

130. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than an object with less mass. (E.g. it takes more of a push to get a car going than a bike.)
If the same force is applied to 2 different objects, the one with a smaller mass will accelerate more. (E.g. if you hit a golf ball and a bowling ball with a 5 iron, the golf ball will go faster.)

131. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than an object with less mass. (E.g. it takes more of a push to get a car going than a bike.)
If the same force is applied to 2 different objects, the one with a smaller mass will accelerate more. (E.g. if you hit a golf ball and a bowling ball with a 5 iron, the golf ball will go faster.)
How much force is needed to accelerate a 60 Kg person on a bike by 3 m/s2?

132. Second Law of Motion – “F = m x a”
An object that has more mass needs more force to accelerate it than an object with less mass. (E.g. it takes more of a push to get a car going than a bike.)
If the same force is applied to 2 different objects, the one with a smaller mass will accelerate more. (E.g. if you hit a golf ball and a bowling ball with a 5 iron, the golf ball will go faster.)
How much force is needed to accelerate a 60 Kg person on a bike by 3 m/s2?
F = m x a = 60 x 3 = 180 N

133. How much will a 450 Kg car accelerate if 1350 N of force are applied to it?

134. How much will a 450 Kg car accelerate if 1350 N of force are applied to it?
F = m x a

135. How much will a 450 Kg car accelerate if 1350 N of force are applied to it?
F = m x a F m a

136. How much will a 450 Kg car accelerate if 1350 N of force are applied to it?
F = m x a F F
a = =
= 3 m/s2 m m a

137. Third Law of Motion – “Action & Reaction”

138. Third Law of Motion – “Action & Reaction”
For every action

139. Third Law of Motion – “Action & Reaction”
For every action (a force exerted in some direction),

140. Third Law of Motion – “Action & Reaction”
For every action (a force exerted in some direction), there is an equal and opposite reaction.

141. Third Law of Motion – “Action & Reaction”
For every action (a force exerted in some direction), there is an equal and opposite reaction.
When one object exerts a force on a second object (a rocket pushing its exhaust out the back),

142. Third Law of Motion – “Action & Reaction”
For every action (a force exerted in some direction), there is an equal and opposite reaction.
When one object exerts a force on a second object (a rocket pushing its exhaust out the back), the second object exerts the same force back on the first object (the exhaust pushes the rocket forward).

143. Third Law of Motion – “Action & Reaction”
For every action (a force exerted in some direction), there is an equal and opposite reaction.
When one object exerts a force on a second object (a rocket pushing its exhaust out the back), the second object exerts the same force back on the first object (the exhaust pushes the rocket forward).
We often don’t see both objects move because of Newton’s 2nd Law -

144. Third Law of Motion – “Action & Reaction”
For every action (a force exerted in some direction), there is an equal and opposite reaction.
When one object exerts a force on a second object (a rocket pushing its exhaust out the back), the second object exerts the same force back on the first object (the exhaust pushes the rocket forward).
We often don’t see both objects move because of Newton’s 2nd Law – the object with less mass does the most accelerating.
When you do a push-up, are you really pushing up?