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Motion Equations Mr. Kings Science Class. WORK WORK = FORCE X DISTANCE.

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Presentation on theme: "Motion Equations Mr. Kings Science Class. WORK WORK = FORCE X DISTANCE."— Presentation transcript:

1 Motion Equations Mr. Kings Science Class

2 WORK WORK = FORCE X DISTANCE

3 WORK Feet or cm

4 WORK WORK = FORCE X DISTANCE Feet or cm Pounds or grams

5 WORK WORK = FORCE X DISTANCE Feet or centimeters Pounds or grams Foot pounds or gram centimeters

6 WORK WORK = FORCE X DISTANCE Feet or centimeters Pounds or grams Foot pounds or gram centimeters 10 cm

7 WORK WORK = FORCE X DISTANCE Feet or centimeters Pounds or grams Foot pounds or gram centimeters 10 cm X

8 WORK WORK = FORCE X DISTANCE Feet or centimeters Pounds or grams Foot pounds or gram centimeters 10 cm X 20 g

9 WORK WORK = FORCE X DISTANCE Feet or centimeters Pounds or grams Foot pounds or gram centimeters 10 cm X 20 g =

10 WORK WORK = FORCE X DISTANCE Feet or centimeters Pounds or grams Foot pounds or gram centimeters 10 cm X 20 g = 200 joules

11 WORK Lets try a word problem! Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How much work did Johneal do?

12 WORK Lets try a word problem! Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How much work did Johneal do? WORK = FORCE X DISTANCE

13 WORK Lets try a word problem! Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How much work did Johneal do? WORK = FORCE X DISTANCE ? = 80g X 25cm

14 WORK Lets try a word problem! Johneal pulled a 100 gram weight using a spring scale up the smooth side of a chalk board. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How much work did Johneal do? WORK = FORCE X DISTANCE ? = 80g X 25cm ? = 2,000 joule

15 POWER

16 POWER Power

17 POWER Power =

18 POWER Work

19 POWER Power = Work

20 POWER Power = Work Time

21 POWER Power = Work Time Watt

22 POWER Power = Work Time Watt Joules

23 POWER Power = Work Time Watt Joules Seconds

24 POWER Power = Work Time Watt Joules Seconds

25 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as she pulled it evenly 25 centimeters. How Much work did Trevor do?

26 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as he pulled it evenly 25 centimeters. How Much work did Trevor do? WORK = FORCE X DISTANCE = 80 grams x 25 cm

27 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as he pulled it evenly 25 centimeters. How Much work did Trevor do? WORK = FORCE X DISTANCE = 80 grams x 25 cm = 2000 joules

28 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as he pulled it evenly 25 centimeters. How Much work did Trevor do? WORK = FORCE X DISTANCE = 80 grams x 25 cm = 2000 joules POWER = WORK TIME

29 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as he pulled it evenly 25 centimeters. How Much work did Trevor do? WORK = FORCE X DISTANCE = 80 grams x 25 cm = 2000 joules POWER = WORK TIME

30 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as he pulled it evenly 25 centimeters. How Much work did Trevor do? WORK = FORCE X DISTANCE = 80 grams x 25 cm = 2000 joules POWER = WORK TIME 2000 joules

31 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as he pulled it evenly 25 centimeters. How Much work did Trevor do? WORK = FORCE X DISTANCE = 80 grams x 25 cm = 2000 joules POWER = WORK TIME 2000 joules 5 seconds

32 Now, lets try a problem! Trevor pulled a 100 gram weight using a spring scale up the smooth side of a chalk board in 5 s. The spring scale read 80 grams as he pulled it evenly 25 centimeters. How Much work did Trevor do? WORK = FORCE X DISTANCE = 80 grams x 25 cm = 2000 joules POWER = WORK TIME 2000 joules 5 seconds 400 watts

33 Velocity

34 Velocity VELOCITY

35 Velocity VELOCITY =

36 Velocity DISTANCE

37 Velocity VELOCITY = DISTANCE

38 Velocity VELOCITY = DISTANCE TIME Miles or meters

39 Velocity VELOCITY = DISTANCE TIME Miles or meters Seconds or hours

40 Velocity VELOCITY = DISTANCE TIME Miles or meters Seconds or hours Miles per hour Meter per second

41 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity?

42 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY

43 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY =

44 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY = DISTANCE

45 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY = DISTANCE

46 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY = DISTANCE TIME

47 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY = DISTANCE TIME 600 meters

48 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY = DISTANCE TIME 600 meters 50 seconds

49 Lets now try a problem! Ryan ran 600 meter in 50 seconds, what is his Velocity? VELOCTIY = DISTANCE TIME 600 meters 50 seconds 12 meters/second

50 ACCELERATION

51 ACCELERATION ACCELERATION

52 ACCELERATION ACCELERATION =

53 ACCELERATION VELOCITY ENDING

54 ACCELERATION ACCELERATION = VELOCITY ENDING

55 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING

56 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME

57 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME

58 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME Meters/second Miles/hour

59 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME Meters/second Miles/hour

60 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME Meters/second Miles/hour Meters/second Miles/hour

61 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME Meters/second Miles/hour Meters/second Miles/hour Seconds/hours

62 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME Meters/second Miles/hour Meters/second Miles/hour Seconds/hours

63 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME Meters/second Miles/hour Meters/second Miles/hour Seconds/hours

64 ACCELERATION ACCELERATION = VELOCITY ENDING VELOCITY STARTING TIME Meters/second Miles/hour Meters/second Miles/hour Seconds/hours Meters/second/second Miles/hour/hour

65 OK - Lets try an acceleration problem

66 Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate?

67 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME

68 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME 3 m/s

69 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME 3 m/s 7 m/s

70 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME 3 m/s 7 m/s

71 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME 3 m/s 7 m/s 8 seconds

72 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME 3 m/s = 4m/s 7 m/s 8 seconds

73 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME 3 m/s = 4m/s 7 m/s 8 seconds 4 / 8 = 1/2 meters/sec/sec

74 OK - Lets try an acceleration problem Brandon is traveling in his bike at 3 m/s. He then speeds up Going down hill and at the bottom of the hill he is traveling 7 m/s. 8 seconds was the time he took to bike down the hill. What is his acceleration rate? ACCELERATION = VELOCITY END START TIME 3 m/s = 4m/s 7 m/s 8 seconds 4 / 8 = 1/2 meters/sec/sec 1/2 or.5 m/s/s


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