 # Section 16.1 Pythagorean Theorem a=11.6. x=3.86 y=4.60 x=9.90 35.7 15.3.

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Section 16.1 Pythagorean Theorem a=11.6

x=3.86 y=4.60 x=9.90 35.7 15.3

Isosceles Triangles (Diagonal divides into two congruent triangles) Basic Knowledge Two sides are congruent The two angles opposite the congruent sides are congruent

A parallelogram has two parallel pairs of opposite sides. - 2 sets of congruent sides - opposite angles congruent - consecutive angles supplementary - diagonals bisect each other - diagonals form 2 congruent triangles A rectangle has two pairs of opposite sides parallel, and four right angles. It is also a parallelogram, since it has two pairs of parallel sides. -4 right angles - diagonals congruent -Makes two pairs of congruent isosceles triangles -Top and bottom; left and right A rhombus is defined as a parallelogram with four equal sides. Is a rhombus always a rectangle? No, because a rhombus does not have to have 4 right angles. - 4 congruent sides - diagonals bisect angles - diagonals perpendicular

A square has two pairs of parallel sides, four right angles, and all four sides are equal. It is also a rectangle and a parallelogram. Trapezoids only have one pair of parallel sides. It's a type of quadrilateral that is not a parallelogram. (British name: Trapezium) I have only one set of parallel sides. [The median of a trapezoid is parallel to the bases and equal to one-half the sum of the bases.] Isosceles Trapezoid - only one set of parallel sides - base angles congruent - legs congruent - diagonals congruent - opposite angles supplementary

Section 16.4 – Area of a Triangle Given any triangle with sides a and b, and the included angle the area A is given by, Ex. #5) A parallelogram has two adjacent sides of length 4 cm and 6 cm respectively. IF the included angle measures 52, find the area of the parallelogram.

Section 17.4 Prisms Prisms: 3D figures that have 2 distinct parallel bases connected by rectangles. Prisms are named by their bases. Volume = Area of base x height of prism Volume = Base is a ½ bh x l Distance between the two bases

Volume of Prisms V= ½ bh x l V= ½(8)(5) x 10 V= 200 cm 3

Volume of Prisms V= ½ bh x l V= ½(12)(9) x 18 V= 972 cm 3

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