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Atomos: Not to Be Cut Chapter 5 Lesson 1. 2 Atomic Theory Atoms are building blocks of elements Atoms are building blocks of elements Similar atoms in.

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Presentation on theme: "Atomos: Not to Be Cut Chapter 5 Lesson 1. 2 Atomic Theory Atoms are building blocks of elements Atoms are building blocks of elements Similar atoms in."— Presentation transcript:

1 Atomos: Not to Be Cut Chapter 5 Lesson 1

2 2 Atomic Theory Atoms are building blocks of elements Atoms are building blocks of elements Similar atoms in each element Similar atoms in each element Different from atoms of other elements Different from atoms of other elements Two or more different atoms bond in simple ratios to form compounds Two or more different atoms bond in simple ratios to form compounds

3 3 Subatomic Particles ParticleSymbol Charge Relative Mass Electron e - 1- 0 Proton p + + 1 Neutron n0 1

4 4 Location of Subatomic Particles 10 -13 cm 10 -13 cm electrons electrons protons protons neutrons neutrons 10 -8 cm 10 -8 cm nucleus

5 5 Atomic Number Counts the number ofprotons in an atom

6 6 Periodic Table Represents physical and chemical behavior of elements Represents physical and chemical behavior of elements Arranges elements by increasing atomic number Arranges elements by increasing atomic number Repeats similar properties in columns known as chemical families or groups Repeats similar properties in columns known as chemical families or groups

7 7 Periodic Table 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 11 Na

8 8 Atomic Number on the Periodic Table 11Na Atomic Number Symbol

9 9 All atoms of an element have the same number of protons 11Na 11 protons Sodium

10 10 Learning Check AT 1 State the number of protons for atoms of each of the following: A. Nitrogen 1) 5 protons 2) 7 protons 3) 14 protons B. Sulfur 1) 32 protons 2) 16 protons 3) 6 protons C. Barium 1) 137 protons 2) 81 protons 3) 56 protons

11 11 Solution AT 1 State the number of protons for atoms of each of the following: A. Nitrogen 2) 7 protons 2) 7 protons B. Sulfur 2) 16 protons C. Barium 3) 56 protons

12 12 Number of Electrons An atom is neutral An atom is neutral The net charge is zero The net charge is zero Number of protons = Number of electrons Number of protons = Number of electrons Atomic number = Number of electrons Atomic number = Number of electrons

13 13 Mass Number Counts the number of protons and neutrons in an atom

14 14 Atomic Symbols Show the mass number and atomic number Show the mass number and atomic number Give the symbol of the element Give the symbol of the element mass number 23 Na sodium-23 23 Na sodium-23 atomic number 11 atomic number 11

15 15 More Atomic Symbols 163165 O P Zn O P Zn 81530 81530 8 p + 15 p + 30 p + 8 n16 n35 n 8 e - 15 e - 30 e -

16 16 Isotopes Atoms with the same number of protons, but different numbers of neutrons. Atoms with the same number of protons, but different numbers of neutrons. Atoms of the same element (same atomic number) with different mass numbers Atoms of the same element (same atomic number) with different mass numbers Isotopes of chlorine Isotopes of chlorine 35 Cl 37 Cl 1717 chlorine - 35 chlorine - 37 chlorine - 35 chlorine - 37

17 17 Learning Check AT 2 Naturally occurring carbon consists of three isotopes, 12 C, 13 C, and 14 C. State the number of protons, neutrons, and electrons in each of these carbon atoms. Naturally occurring carbon consists of three isotopes, 12 C, 13 C, and 14 C. State the number of protons, neutrons, and electrons in each of these carbon atoms. 12 C 13 C 14 C 6 6 6 6 6 6 #P _______ _______ _______ #N _______ _______ _______ #E _______ _______

18 18 Solution AT 2 12 C 13 C 14 C 6 6 6 6 6 6 #P __6___ _ 6___ ___6___ #N __6___ _ _7___ ___8___ #E __6___ _ 6___ ___6___

19 19 Learning Check AT 3 An atom of zinc has a mass number of 65. A.Number of protons in the zinc atom A.Number of protons in the zinc atom 1) 302) 353) 65 1) 302) 353) 65 B.Number of neutrons in the zinc atom B.Number of neutrons in the zinc atom 1) 302) 353) 65 1) 302) 353) 65 C. What is the mass number of a zinc isotope with 37 neutrons? 1) 372) 653) 67 1) 372) 653) 67

20 20 Solution AT 3 An atom of zinc has a mass number of 65. A.Number of protons in the zinc atom A.Number of protons in the zinc atom 1) 30 1) 30 B.Number of neutrons in the zinc atom B.Number of neutrons in the zinc atom 2) 35 C. What is the mass number of a zinc isotope with 37 neutrons? 3) 67

21 21 Learning Check AT 4 Write the atomic symbols for atoms with the following: A. 8 p +, 8 n, 8 e - ___________ B.17p +, 20n, 17e - ___________ C. 47p +, 60 n, 47 e - ___________

22 22 Solution AT 4 16 O A. 8 p +, 8 n, 8 e - 8 B.17p +, 20n, 17e - 37 Cl 17 17 C. 47p +, 60 n, 47 e - 107 Ag 47 47

23 23 Learning Check AT 5 An atom has 14 protons and 20 neutrons. A.Its atomic number is 1) 142) 163) 34 B. Its mass number is 1) 142) 163) 34 C. The element is 1) Si2) Ca3) Se D.Another isotope of this element is 1) 34 X 2) 34 X 3) 36 X 16 14 14 16 14 14

24 24 Solution AT 5 An atom has 14 protons and 20 neutrons. A.It has atomic number 1) 14 B. It has a mass number of 3) 34 C. The element is 1) Si D.Another isotope of this element would be 3) 36 X 14 14

25 25 Masses of Atoms A scale designed for atoms gives their small atomic masses in atomic mass units (amu) A scale designed for atoms gives their small atomic masses in atomic mass units (amu) An atom of 12 C was assigned an exact mass of 12.00 amu An atom of 12 C was assigned an exact mass of 12.00 amu Relative masses of all other atoms was determined by comparing each to the mass of 12 C Relative masses of all other atoms was determined by comparing each to the mass of 12 C An atom twice as heavy has a mass of 24.00 amu. An atom half as heavy is 6.00 amu. An atom twice as heavy has a mass of 24.00 amu. An atom half as heavy is 6.00 amu.

26 26 Atomic Mass Listed on the periodic table Listed on the periodic table Gives the mass of “average” atom of each element compared to 12 C Gives the mass of “average” atom of each element compared to 12 C Average atom based on all the isotopes and their abundance % Average atom based on all the isotopes and their abundance % Atomic mass is not a whole number Atomic mass is not a whole number Na 22.99

27 27 Learning Check AT6 Using the periodic table, specify the atomic mass of each element (round to the tenths place): A.calcium__________ B. aluminum__________ C. lead__________ D. barium__________ E. iron__________

28 28 Solution AT6 Using the periodic table, specify the atomic mass of each element (round to the tenths place): A.calcium_40.1 amu _ B. aluminum_27.0 amu _ C. lead_207.2 amu_ D. barium_137.3 amu_ E. iron_55.8 amu__

29 29 Calculating Atomic Mass Percent(%) abundance of isotopes Percent(%) abundance of isotopes Mass of each isotope of that element Mass of each isotope of that element Weighted average = Weighted average = mass isotope 1 (%) + mass isotope 2 (%) + … mass isotope 1 (%) + mass isotope 2 (%) + … 100 100 100 100

30 30 Atomic Mass of Magnesium Isotopes Mass of Isotope Abundance 24 Mg =24.0 amu 78.70% 25 Mg = 25.0 amu 10.13% 26 Mg = 26.0 amu 11.17% 26 Mg = 26.0 amu 11.17% Atomic mass (average mass) Mg = 24.3 amu Mg 24.3

31 31 Learning Check AT7 Gallium is a metallic element found in small lasers used in compact disc players. In a sample of gallium, there is 60.2% of gallium-69 (68.9 amu) atoms and 39.8% of gallium-71 (70.9 amu) atoms. What is the atomic mass of gallium ?

32 32 Solution AT7 Ga-69 68.9 amu x 60.2 = 41.5 amu for 69 Ga 100 100 Ga-71 (%/100) 70.9 amu x 39.8 = 28.2 amu for 71 Ga 100 100 Atomic mass Ga = 69.7 amu

33 33 Finding An Isotopic Mass A sample of boron consists of 10 B (mass 10.0 amu) and 11 B (mass 11.0 amu). If the average atomic mass of B is 10.8 amu, what is the % abundance of each boron isotope?

34 34 Assign X and Y values: X = % 10 B Y = % 11 B Determine Y in terms of X X + Y = 100 Y = 100 - X Solve for X: X (10.0) + (100 - X )(11.0) = 10.8 100 100 100 100 Multiply through by 100 10.0 X + 1100 - 11.0X = 1080

35 35 Collect X terms 10.0 X - 11.0 X = 1080 - 1100 - 1.0 X = -20 - 1.0 X = -20 X = -20 = 20 % 10 B X = -20 = 20 % 10 B - 1.0 - 1.0 Y = 100 - X % 11 B = 100 - 20% = 80% 11 B


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