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Math in HVAC Presented by Mike Veeder HVAC instructor Columbia Greene Questar.

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Presentation on theme: "Math in HVAC Presented by Mike Veeder HVAC instructor Columbia Greene Questar."— Presentation transcript:

1 Math in HVAC Presented by Mike Veeder HVAC instructor Columbia Greene Questar

2 Whole House Heat Loss question #1  Determine design temp difference  Find total square foot of windows and doors  Find gross walls  Subtract windows and doors from gross walls to find net walls  Determine exposed ceiling area  Find floor area

3  Multiply each by U factor  Add all btu’s/degree Fahrenheit  Multiply by temp difference  Multiply by 15% for duct losses  Arrive at heating btu loss for house

4 Calculate annual heat loss Question #2  BTU annual = BTUH x HDD x 24hr/day x.75

5 BTU annual = 875 x 6860 x 24 x.75 BTU annual = 875 x 6860 x 24 x.75 Annual heat loss is 108,045,000 btus Annual heat loss is 108,045,000 btus

6 Propane Determine how many gallons of propane burned per year Determine how many gallons of propane burned per year Gal/yr = annual btu / 92,000btu / gal Gal/yr = annual btu / 92,000btu / gal Gal/yr = 108,045,000/92,000 Gal/yr = 108,045,000/92,000 Gal/yr = 1174 gal Gal/yr = 1174 gal Cost/yr = 1174 gal x $2.60/gal Cost/yr = 1174 gal x $2.60/gal Cost/yr = $3052.40 x stack loss of furnace Cost/yr = $3052.40 x stack loss of furnace Cost/yr = $3662.88 Cost/yr = $3662.88

7 Electricity Determine the amount of electricity used on a annual basis Determine the amount of electricity used on a annual basis Watt/yr = btu annual / 3.41 btu/watt Watt/yr = btu annual / 3.41 btu/watt Watt/yr = 108,045,000/3.41 Watt/yr = 108,045,000/3.41 Watt/yr = 31,684,750 / 1000 Watt/yr = 31,684,750 / 1000 KW/yr =31,684 x.14/kw KW/yr =31,684 x.14/kw Yearly cost of electric is $4435.87 Yearly cost of electric is $4435.87

8 Calculate BTU output of a Heat Pump Question 5 BTU=1.08 x cfm x delta “T” BTU=1.08 x cfm x delta “T” CFM= FPM x.66 x sq. ft of duct area CFM= FPM x.66 x sq. ft of duct area

9 Determine cfm of a Geothermal Heat pump Question #4 CFM = fpm x.66 x sq. ft CFM = fpm x.66 x sq. ft CFM = 606 fpm x.66 x 2 CFM = 606 fpm x.66 x 2 CFM = 800 cfm CFM = 800 cfm Btu = 1.08 x cfm x delta “t” Btu = 1.08 x cfm x delta “t” Btu = 1.08x 800 x (92 – 65) Btu = 1.08x 800 x (92 – 65) Btu = 23,328 btu Btu = 23,328 btu

10 Geothermal loop performance Question #6 Loop filled with 20% Methanol Btu = 485 x gpm x Delta “t” Btu = 485 x 6 x (40 – 32) Btu = 23,280 btu

11 BPI Building Airflow Standard (BAS) Living Space Area = 1500 sq. ft. Basement area = 700 sq. ft. Ceiling height = 8 ft. # of Occupants = 4 # of stories above grade = 2 Location = Albany, NY

12 Calculate ventilation required for building Airflow(b) =.35 x volume/60 Volume = 8 x (1500 + 700) = 17,600 cu. ft. Airflow(b) =.35 x 17,600 / 60 Airflow(b) = 102 cfm

13 Calculate ventilation required for people Airflow(p) = 15 x # of occupants Airflow(p) = 15 x 4 = 60 cfm

14 Using the higher airflow requirement Convert cfm to cfm50 Minimum cfm50 = airflow x N N = LBL conversion factor Minimium cfm50 = 102 cfm x 15.4 = 1570 cfm50

15 When we read the cfm50 from the blower door, 1570 is what is recommended for infiltration for this house

16 Determine course of action for home  Cfm50 x.7 = minimum ventilation  1570 cfm50 x.7 = 1099 cfm50

17  If the blower door reads: –Above 1570 cfm then the house is too loose and you would recommend air sealing

18  If the blower door reads: –Between 1570 cfm50 and 1099 cfm50, then the house is within the normal range for infiltration and ventilation

19  If the blower door reads: –Below 1099 cfm50 then you need to mechanically ventilate the house using a hrv or equivalent device. The house is too tight at this point.

20 My class after a math lesson

21 Thanks for your attention !!  Any questions??????????


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