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Modern Chemistry Chapter 9 Stoichiometry

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Presentation on theme: "Modern Chemistry Chapter 9 Stoichiometry"— Presentation transcript:

1 Modern Chemistry Chapter 9 Stoichiometry
Sections 1-3 Introduction to Stoichiometry Ideal Stoichiometric Calculations Limiting Reactant and Percent Yield

2 Chapter 9 Vocabulary Composition Stoichiometry Reaction Stoichiometry
Mole Ratio Limiting Reactant Excess Reactant Actual Yield Theoretical Yield Percent Yield

3 Chapter 9 Section 1 Introduction to Stoichiometry
Chapter 9 Section 1 Intro. Stoichiometry pages

4 Chapter 9 Section 1 Intro. Stoichiometry pages 299-303
Definitions Composition stoichiometry deals with the mass relationships of elements in compounds. Reaction stoichiometry involves the mass relationships between reactants and products in a chemical reaction. Chapter 9 Section 1 Intro. Stoichiometry pages

5 Stoichiometry Animation
Chapter 9 Section 1 Intro. Stoichiometry pages p. xx

6 Chapter 9 Section 1 Intro. Stoichiometry pages 299-303
Definitions A mole ratio is a conversion factor that relates the amounts in moles of any two substances involved in a chemical reaction Example: 2Al2O3(l)  4Al(s) + 3O2(g) Mole Ratios: 2 mol Al2O mol Al2O mol Al 4 mol Al 3 mol O mol O2 Chapter 9 Section 1 Intro. Stoichiometry pages

7 Chapter 9 Section 1 Intro. Stoichiometry pages 299-303
Using the Mole Ratio Chapter 9 Section 1 Intro. Stoichiometry pages p. xx

8 Mg(s) + 2HCl(aq)  MgCl2(aq) + H2(g)
Mole – Mole Examples Mg(s) + 2HCl(aq)  MgCl2(aq) + H2(g) If 2 mol of HCl react, how many moles of H2 are obtained? How many moles of Mg will react with 2 mol of HCl? If 4 mol of HCl react, how many mol of each product are produced? How would you convert from moles of substances to masses? Chapter 9 Section 1 Intro. Stoichiometry pages

9 Chapter 9 Section 1 Intro. Stoichiometry pages 299-303
Converting from gmol Chapter 9 Section 1 Intro. Stoichiometry pages p. xx

10 Chapter 9 Section 1 Intro. Stoichiometry pages 299-303
Section 1 Homework Page 301 #1-4 Chapter 9 Section 1 Intro. Stoichiometry pages

11 Chapter 9 Section 2 Ideal Stoichiometric Calculations
Chapter 9 Section 2 Ideal Stoichiometry pages

12 Reactants  Products MASS OF SUBSTANCE GIVEN MASS OF SUBSTANCE WANTED
MOLAR MASS MOLAR MASS MOLES OF SUBSTANCE GIVEN MOLES OF SUBSTANCE WANTED MOLE RATIO Chapter 9 Section 2 Ideal Stoichiometry pages

13 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Tool Box GRAMSmL DENSITY GRAMSMOLES MOLAR MASS MOLES MOLES MOLE RATIO MOLES PARTICLES 6.02x1023 1000 g = 1kg 1000 mL = 1L 1000 mg = 1g Chapter 9 Section 2 Ideal Stoichiometry pages

14 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Kg L mg mL g MOLES MOLES g mg mL L Kg Chapter 9 Section 2 Ideal Stoichiometry pages

15 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Sample Problem How many kilograms of ethane are required to react with excess oxygen to produce 8.70 L of carbon dioxide? The density of carbon dioxide gas at standard temperature is g/L. kg Chapter 9 Section 2 Ideal Stoichiometry pages

16 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Kg L mg mL g MOLES MOLES g mg mL L Kg Chapter 9 Section 2 Ideal Stoichiometry pages

17 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
L CO2 g CO2 mol CO2 mol C2H6 g C2H6 kg C2H6 x x x x x L CO2 g CO2 mol CO2 mol C2H6 g C2H6 Kg g MOLES MOLES g L Chapter 9 Section 2 Ideal Stoichiometry pages

18 C2H6 (g) + O2 (g)  CO2 (g) + H2O (g) + E
8.70L ? Kg g g MOLES MOLES L CO2 g CO2 mol CO2 mol C2H6 g C2H6 kg C2H6 x x x x x L CO2 g CO2 mol CO2 mol C2H6 g C2H6 Chapter 9 Section 2 Ideal Stoichiometry pages

19 C2H6 (g) + O2 (g)  CO2 (g) + H2O (g) + E
8.70L ? Kg g g 1000g=1Kg MOLAR MASS MOLAR MASS MOLAR RATIO MOLES MOLES DENSITY L CO2 g CO2 mol CO2 mol C2H6 g C2H6 kg C2H6 x x x x x L CO2 g CO2 mol CO2 mol C2H6 g C2H6 Chapter 9 Section 2 Ideal Stoichiometry pages

20 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Sample Problem p. 306 In photosynthesis, plants use energy from the sun to produce glucose, C6H12O6, and oxygen from the reaction of carbon dioxide and water. What mass, in grams, of glucose is produced when 3.00 mol of water react with carbon dioxide? 90.1 g C6H12O6 Chapter 9 Section 2 Ideal Stoichiometry pages mol-mass

21 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Sample Problem p. 310 Tin (II) fluoride, SnF2, is used in some toothpastes. It is made by the reaction of tin with hydrogen fluoride according to the following equation. Sn(s) + 2HF(g)  SnF2(s) + H2(g) How many grams of SnF2 are produced from the reaction of g HF with Sn? 117.5 g SnF2 Chapter 9 Section 2 Ideal Stoichiometry pages mass-mass.

22 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Sample Problem p. 305 In a spacecraft, the carbon dioxide exhaled by astronauts can be removed by its reaction with lithium hydroxide, LiOH, according to the following chemical equation. CO2(g) + 2LiOH(s)  Li2CO3(s) + H2O(l) How many moles of lithium hydroxide are required to react with 20 mol CO2, the average amount exhaled by a person each day? 40 mol LiOH Chapter 9 Section 2 Ideal Stoichiometry pages mol-mol

23 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Sample Problem p. 309 The first step in the industrial manufacture of nitric acid is the catalytic oxidation of ammonia. NH3(g) + O2(g)  NO(g) + H2O(g) (unbalanced) The reaction is run using 824 g NH3 and excess oxygen. a. How many moles of NO are formed? b. How many moles of H2O are formed? 48.4mol NO; mol H2O Chapter 9 Section 2 Ideal Stoichiometry pages mass-mol

24 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Problem Magnesium burns in oxygen to produce magnesium oxide. How many grams magnesium will burn in the presence of 189 mL of oxygen? The density of oxygen is 1.429g/L. 0.410 g Mg Chapter 9 Section 2 Ideal Stoichiometry pages mL-g

25 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Problem Limestone, CaCO3, can be decomposed with heat to form lime, CaO, and carbon dioxide. How many moles of lime would be formed from the decomposition of 20.1 kilograms of limestone? 201 moles CaO Chapter 9 Section 2 Ideal Stoichiometry pages Kg-mol.

26 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Section 2 Homework Page 311 #1-5 Chapter 9 Section 2 Ideal Stoichiometry pages

27 Section 2 Homework Problem Bank
Page #176, 177, 179, 180, 184, 187, 190, 191, 192, 194, 196 Chapter 9 Section 2 Ideal Stoichiometry pages

28 Chapter 9 Section 3 Limiting Reactant and Percent Yield
Chapter 9 Section 3 Limiting Reactant pages

29 Chapter 9 Section 3 Limiting Reactant pages 312-318
Definitions The limiting reactant is the reactant that limits the amount of the other reactant that can combine and the amount of product that can form in a chemical reaction. The excess reactant is the substance that is not used up completely in a reaction. Chapter 9 Section 3 Limiting Reactant pages

30 Chapter 9 Section 3 Limiting Reactant pages 312-318
S’mores Given the bag o’ reactants find the number of s’mores you could produce if the balanced equation is 2 Tg + 1 Mm  1 Sm Tg = Teddy Graham Mm = Minimarshmallow Sm = S’more Chapter 9 Section 3 Limiting Reactant pages

31 Chapter 9 Section 3 Limiting Reactant pages 312-318
S’mores What is the limiting reactant? What is the reactant in excess? What is the amount in excess ? What is the theoretical yield? What is the actual yield? What is the percent yield? Chapter 9 Section 3 Limiting Reactant pages

32 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Sample Problem p. 313 Silicon dioxide (quartz) is usually quite unreactive but reacts readily with hydrogen fluoride according to the following equation. SiO2(s) + 4HF(g)  SiF4(g) + 2H2O(l) If 6.0 mol HF is added to 4.5 mol SiO2, which is the limiting reactant? HF Chapter 9 Section 2 Ideal Stoichiometry pages mol & mol limiting

33 Chapter 9 Section 3 Limiting Reactant pages 312-318
Problem I need a problem that requires them to answer these questions a. Which compound is the limiting reactant? b. What is the theoretical yield of product? c. What is the reactant in excess, and how much remains after the reaction is completed? 8.940 x 1023 molecules Chapter 9 Section 3 Limiting Reactant pages mass & mass, limiting, actual

34 Chapter 9 Section 3 Limiting Reactant pages 312-318
Problem I need another problem that requires them to answer these questions a. Which compound is the limiting reactant? b. What is the theoretical yield of product? c. What is the reactant in excess, and how much remains after the reaction is completed? 8.940 x 1023 molecules Chapter 9 Section 3 Limiting Reactant pages mass & mass, limiting, actual

35 Chapter 9 Section 3 Limiting Reactant pages 312-318
p. xx

36 Chapter 9 Section 3 Limiting Reactant pages 312-318
Section 3 Homework Page 318 #1 & 2 Chapter 9 Section 3 Limiting Reactant pages

37 Chapter 9 Section 3 Limiting Reactant pages 312-318
Definitions The theoretical yield is the maximum amount of product that can be produced from a give amount of reactant. The actual yield is the measured amount of product obtained from a reaction. The percentage yield is the ratio of the actual yield to the theoretical yield, multiplied by 100. Chapter 9 Section 3 Limiting Reactant pages

38 Chapter 9 Section 3 Limiting Reactant pages 312-318
Percent Yield Chapter 9 Section 3 Limiting Reactant pages p. xx

39 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Sample Problem p. 317 Chlorobenzene, C6H5Cl, is used in the production of many important chemicals, such as aspirin, dyes, and disinfectants. One industrial method of preparing chlorobenzene is to react benzene, C6H6, with chlorine, as represented by the following equation. C6H6 (l) + Cl2 (g)  C6H5Cl (l) + HCl (g) When 36.8 g C6H6 react with an excess of Cl2, the actual yield of C6H5Cl is 38.8 g. What is the percentage yield of C6H5Cl? 73.2% Chapter 9 Section 2 Ideal Stoichiometry pages mass-mass percent

40 Chapter 9 Section 3 Limiting Reactant pages 312-318
Problem Hydrogen sulfide gas can be formed by the action of HCl and FeS, forming FeCl2 as product. What is the theoretical yield in molecules of hydrogen sulfide if g of FeS are mixed with g of HCl? If the percent yield in the lab is 93.6% what is the actual yield? 8.940 x 1023 molecules Chapter 9 Section 3 Limiting Reactant pages mass & mass, limiting, actual

41 Chapter 9 Section 2 Ideal Stoichiometry pages 304-311
Problem Benzene, C6H6, is reacted with bromine, Br2, to produce bromobenzene, C6H5Br, and hydrogen bromide, HBr, as shown below. When 40.0 g of benzene are reacted with 95.0 g of bromine, 65.0 g of bromobenzene is produced. C6H6 + Br2  C6H5Br + HBr a. Which compound is the limiting reactant? b. What is the theoretical yield of bromobenzene? c. What is the reactant in excess, and how much remains after the reaction is completed? d. What is the percentage yield? Benzene, 80.4g, Br2 13.2g, 80.8% Chapter 9 Section 2 Ideal Stoichiometry pages

42 Chapter 9 Section 3 Limiting Reactant pages 312-318
Molarity Molarity measures the concentration of solutions. (aq) Molarity = moles / liter 3 mol 3M = 1 L Chapter 9 Section 3 Limiting Reactant pages

43 Chapter 9 Section 3 Limiting Reactant pages 312-318
Problem When 20.0 mL of 0.90M solution of lithium nitrate and 15.0 mL of 0.40M solution of calcium phosphate react, a precipitate is formed. The mass of the precipitate produced in the lab is 0.66 grams. What is the reactant in excess, the limiting reactant, the amount in excess, the theoretical yield and the percent yield. 0.69 grams theo. Chapter 9 Section 3 Limiting Reactant pages

44 Section 3 Homework Problem Bank
Page #201, 208, 214, 217, 219, 223, 226, 229, 232 Chapter 9 Section 3 Limiting Reactant pages


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