1. Oh no! I can’t see a thing. I think I lost my eye sight!!

2. Before we move on, We have… Representing the video clips available Representing the applets available Representing the websites available

3. Pupils should be able to  recall and use the terms for reflection, including normal, angle of incidence and angle of reflection.  state that, for reflection, the angle of incidence is equal to the angle of reflection and use this principle in constructions, measurements and calculations. Introduction to Light Lesson objectives

4. Teacher demonstration In these demonstrations, your teacher will use a laser pointer to illustrate some interesting phenomena related to light. Pls turn to PB page 63 for detail. Lesson Trigger What is light? How do you know this is true? What evidence do you have to show this property?

5. 1 Light travels in a straight line. 2 Light travels at a speed of 3  10 8 m/s. 3 Light can travel through vacuum. 4Light is a wave that carries energy (light energy) from one place to another. Properties of Light

6. Seeing the Light When light meets any surface, reflection of light occurs. Reflection always involves two rays – an incoming or incident ray that strikes a surface, and an outgoing or reflected ray that leaves the same surface. Reflection of Light incident ray reflected ray

7. Normal Laws of Reflection: This is an imaginary line perpendicular to the surface at the point where the light strikes. It is drawn to indicate the angle of incidence i and angle of reflection r. Reflection of Light normal ir incident ray reflected ray 2The incident ray, reflected ray and normal at the point of incidence all lie on the same plane. 1angle of incidence = angle of reflection i = r What can you say about the angle of incidence and angle of reflection? What can you say about the orientation of the incident ray, reflected ray and the normal? Go to Exp11a.mpg

8. Reflection is great! The fact that light reflects off objects allow us to see them. smooth surface When light reflects from a smooth surface, it maintains its geometry. Incident parallel rays are reflected as parallel reflected rays. This is called specular reflection. Specular Reflection

9. When a reflecting surface is rough, diffuse reflection occurs. The law of reflection still holds, but incident parallel rays do not reflect as parallel rays any more. In diffuse reflection, the reflected rays leave the surface at so many different directions such that the image is disrupted. rough surface Diffuse Reflection

10. On a mirror or a calm water surface, reflection is specular. The image formed on such surfaces are clear and sharp. However, if the surface is rough, or the water surface is disturbed, diffuse reflection occurs. The image formed is blur. Specular and diffuse Reflection

11. A directed straight line is normally drawn to represent a ray, which is the path taken by light from source to target. A beam of light is a stream of light rays, and is represented by a number of directed straight lines. Representing Light source target

12. Reflect on your daily encounters with light, (a)generate one other possible evidence to support the statement that 'light travels in a straight line', and discuss with your partner how you can demonstrate your statement with a safe, simple activity. (b)list two examples each for diffuse and specular reflections around you. Lesson Closure

13. We look at mirror everyday. What we see on the mirror is called our image. How do you describe your image on a plane mirror? Mirror mirror on the wall Characteristics of image on a plane mirror Same size as object As far behind the mirror as the object is in front. Virtual, as it cannot be captured on the screen Laterally inverted Go to Exp11b.mpg

14. The image of an object is formed on a plane mirror when light ray from the object incidents on the mirror. object plane mirror Light will reflect at a mirror surface such that the angle of incidence and reflection are equal. i r Image on a plane mirror

15. There are many light rays reflected from an object to reach the mirror surface. However, only some light rays will be captured by the eyes. To view the image of an object in a mirror, the eye should be positioned along the direction where the reflected rays from the mirror can be captured by the eye. object plane mirror Drawing Ray Diagrams

16. To the eye, the light ray reaching the eye appears to come from the image behind the mirror. plane mirror object This type of image is called a virtual image because it is formed at a place where there is no light from the object. The mirror simply makes the light appear to be coming from behind it. Drawing Ray Diagrams

17. Steps involved in drawing ray diagrams 1 st - draw the image of the triangle, such that it is of the same size and same shape, and as far behind the mirror as the object is in front. Supposing a triangular object is placed in front of a mirror. We can draw a ray diagram to show how the eye sees the image in the mirror. plane mirror image object Drawing Ray Diagrams x cm

18. 2 nd – draw two diverging rays from any point on the image towards where the eye is positioned. 3rd – draw two diverging rays from the corresponding point on the object to the mirror to meet the reflected rays. object plane mirror image Drawing Ray Diagrams Go to E-SimPhy_308.exe

19. (i) Mark Caroline’s image on the glass window, at appropriate position. (ii)Draw ray diagrams to show how Sarah can see her friend by reflection on the shop window glass. SC (a)Sarah S went shopping with Caroline C one Sunday afternoon. Both girls stood in front of a shop admiring the window display. SC S C Shop windowwall Ray diagram Practice 1 Where should you mark Caroline’s image on the glass window? Why? Which direction does the light ray seems to reach Sarah’s eye? Which direction is the light ray actually coming from?

20. Shop windowwall C’ (b)Caroline moves away from Sarah to a new location C’ to look at the display at the next shop. (i)Mark Caroline’s new image position (ii) Show by ray diagram, whether Sarah can still see her friend by reflection. (ii)Explain how your ray diagram helps you conclude on whether Caroline can be seen by reflection. Light rays from Caroline can still be reflected on the glass window, obeying the Laws of Reflection, where i = r. i rS C Ray diagram Practice 1 Which direction does the light ray seems to reach Sarah’s eye? Which direction is the light ray actually coming from?

21. Fun with Billiard Visit the website below to practise your billiard skill! Have fun playing and learning the Physics of billiard, and see how the Laws of Reflection can be applied in playing billiard. Beyond classroom activity

22. Enrichment / Extension Think about the various type of mirror you encounter in your daily life. (a)Look at the image formed. Can you explain the difference in the images formed from the one you use everyday in your bathroom? (b) Compare and contrast the type of surfaces of such mirrors, and explain why the images formed are different from one another? Lesson Closure

23. Pupils should be able to ◙ recall and use the terms for refraction, including normal, angle of incidence and angle of refraction. ◙ recall and apply the relationship, sin i  sin r = constant to new situation or to solve related problems. ◙ define refractive index of a medium in terms of the ratio of speed of light in vacuum and in the medium. Refraction of Light Lesson objectives

24. Behaviour of light When a beam of light encounters an obstacle in its path, a number of things can happen: 1 Reflection - 2 Refraction - 3 Absorption - The degree of each effect depends on the nature of the materials the light is incident upon. Refraction of Light

25. Using a laser pen, a beam of light is sent from water into air. laser pointer When light strikes such transparent boundary, both reflection and refraction occur. Refraction of Light water What do you think will happen to its path of travel as it strikes the air-water boundary? reflection refraction air glass reflection refraction reflection

26. When will refraction occur? 1 Refraction occurswhenever light passes between transparent media of different optical densities. Why does refraction occur? 2 Refraction occurs because light travel with different speed when in media of different optical densities. Refraction of Light

27. air glass The more optically dense the material, the slower the speed of light in that material Air has lower optical density – faster. Glass has higher optical density – slower. Air has lower optical density – faster. The change in speed at the transparent boundary between two media causes light to change direction. Optical density of glass > water > air > vacuum

28. air glass air water Refraction Terminology i = angle of incidence r = angle of refraction r i i r incident ray refracted rayincident rayrefracted ray Go to E-SimPhy_304.exe

29. Light bends away from the normal when emerging from water into air, which is from an optically denser medium to an optically less dense medium. Light bends towards normal when entering into water from air, which is from an optically less dense medium to an optically denser medium. Optical density of glass > water > air > vacuum Refraction Rules bends away from the normal bends towards the normal

30. air glass air glass i r from an optically less dense medium to an optically denser medium, i > r from an optically denser medium to an optically less denser medium, i < r bends towards the normal bends away from the normal i r Summary

31. For each of the diagram below, complete the path of blue light as it emerges from the transparent medium. Ray diagram Practice 2

32. Refractive Index, n air glass v air v glass v air For example, the refractive index of glass at the air-glass boundary is given as: v air v glass n = The refractive index of a medium is the ratio of the speed of light in one medium relative to the speed of light in the other medium. where v air and v glass are the speed of light in air and glass respectively.

33. air glass  2 2  1 1  1 1  2 2 The ratio of the two sin  s gives the same refractive index, and this relationship is called Snell’s Law. sin  1 sin  2 n =n = Then: if  1 represents the angle of incidence in the less dense medium, and  2 represents the angle of refraction in the denser medium; Refractive Index, n Go to Exp11c.mpg

34. A ray of light approaches a glass-air boundary at an angle of incidence i = 30 . What is the refractive index of the glass if the angle of refraction r = 49  ? air glass 30  49  sin  1 sin  2 n = sin 49  sin 30  = = 1.5 Sample Problem 1 angle in less dense medium Go to E-SimPhy_306.exe

35. water 35  air A ray of light approaches a water-air boundary at an angle of incident i = 35 . (i)Complete the path of the light as it crosses the water-air boundary. (ii) What is the angle of refraction if the refractive index of water n = 1.3? sin  1 sin  2 n = sin 35  sin r = 1.3 = 26  r Sample Problem 2 r

36. Prism disperses white light into its 7 component colours as the refractive index of each colour light is different in the glass prism. Analyse the diagram of dispersion, and infer the colour light thathas the greatest refractive index. Refraction of Light Lesson closure - Think about it

37. Pupils should be able to: explain the terms critical angle and total internal reflection. describe the action of a thin lens on a beam of light. define the focal length for a converging lens. draw ray diagrams to illustrate the formation of real and virtual images of an object by a thin converging lens. Total Internal Reflection Lesson objectives

38. Refraction occurs as light passes across the boundary between two transparent media. Think – Pair share (5 min) Review previous lesson on refraction. Take turn to share with your partner facts about refraction. Jot done your discussion in your Physics notebook. Lesson Review air glass reflection refraction reflection But why does light refract? What is the cause of such behaviour?

39. The picture below be easily reproduced with a laser pointer and a transparent semi- circle glass block in a darkened room. As light enters the glass block, it bends at the surface instead of traveling its original path. What do you think will happen if the angle of incidence in the glass block is increased gradually? Total Internal Reflection

40. A light ray from water is incident on the water - air boundary. The angle of incidence is gradually increased. (i)Calculate the angle of refraction if the refractive index of water is 1.3. (ii) What do you observe about the angle of refraction as the angle of incidence is gradually increased? 57 o air glass 40 o air glass 30 o 41 o 20 o air glass 26 o What is the maximum angle of refraction that can be produced? Total Internal Reflection As the angle of incidence increases, angle of refraction increases as well.

41. At a certain critical angle c, a maximum angle of refraction = 90  is produced. A weak reflected ray is also produced. If the next incident angle is greater than c, no more refraction will occur. The reflected ray becomes very strong and intense. 90  air glass c air glass i> c r if incident angle > critical angle:  no light ray from the optically denser medium will be refracted.  all light rays will be totally internally reflected into the optically denser medium. c weak reflection strong reflection Total Internal Reflection Go to Exp11d.mpg

42. Critical angle and Total Internal Reflection Total internal reflection only occurs when:  a light ray is travelling from an optically denser medium to an optically less dense medium. Critical angle c is defined as the angle of incidence from a denser medium which produces an angle of refraction of 90 . 90  air glass c c weak reflection air glass i> c r strong reflection  the angle of incidence is greater than the critical angle.

43. Sample Practice 1 For each combination of media, which light ray (A or B) will undergo total internal reflection if the incident angle is gradually increased? Explain your choice. air glass A B air water A B glass A B In both cases, light is approaching the boundary from an optically denser medium to an optically less dense medium. A gradual increase in the incident angle will produce an increasingly larger angle of refraction.

44. A ray of light approaches a water-air boundary at a angle of incidence c, which causes it to undergo total internal reflection. Calculate the critical angle c if the refractive index of water n = 1.3 sin  1 sin  2 n = sin 90  sin c = 1.3 = 50  c air water c 90  Sample Practice 2

45. A laparoscope is a medical equipment inside a hollow, thin tube. It is connected to a camera and a high intensity light for doctor to see the structure inside our body. Perform an internet search to find out how total internal reflection plays a part in different fields. Be prepared to share with your classmates what you have learnt from your research next week. Total Internal Reflection Enrichment

46. A ray of light that is incident at an angle on a transparent boundary will undergo refraction. Converging lens is a piece of glass which is thicker at the centre and thinner at the 2 ends. What do you think will happen to a light ray incident on its surface? Thin converging lens air glass A converging lens

47. A converging lens is simply a piece of glass which is thicker at the centre and thinner at the edge. Optical centre - geometric centre of the lens Principal axis - This imaginary line divides the lens into equal upper and lower halves. Another imaginary line used to mark the mid- point of the lens

48. Parallel rays from distant object will all converge at a plane called focal plane. focal plane principal focus focal length

49. Quick Check 1 What are the names of the various parts of a thin converging lens? Are you able to name each and every one of them? 1 2 4 3 5

50. Quick Check 2 What happens to each of the light rays as they pass through the converging lens? Can you complete the path they will take? F A beam of light parallel to the principle axis will bend at the principle focus F. A parallel beam of light not parallel to the principle axis will bend at some point on the focal plane. focal plane

51. For simplicity, a thin converging lens is represented by a double arrowed line. FFFF

52. 2Ray passing through optical centre will emerge unbent. 1(a)Rays parallel to principal axis will meet at the principal focus. F F (b)Rays passing though principal focus will emerge from converging lens as parallel rays.

53. An object O is placed in front of a converging lens L. (i)Draw ray diagram to show how its image is formed. Label the image as I. (ii)Describe the image formed. F O The image formed is: inverted, diminished, real I Sample Practice 3 L

54. Think – Pair share (5 min) Review previous lesson. Take turn to share with your partner facts about converging lens. Jot down your discussion in your Physics notebook. Lesson Review A converging lens is simply a piece of glass which is thicker at the centre and thinner at the edge. What do I know? What have I learnt?

55. Magnifying glass Same size photocopier Camera Slide projector Spot light Trends and patterns on the images formed The type of the image produced by a converging lens are determined by the distance an object is placed away from the lens. Go to E-SimPhy_309.exe

56. Challenge yourself 1 The positions of an object and its image are as shown. (i) How do you determine the position of the lens? (ii) Where is the principle focus of the lens? F L

57. Challenge yourself 2 Object O A thin converging lens casts an image a distance away from the centre of the lens. Given the position of the principle focus as shown below, where should the object be positioned?

58. Challenge yourself 2 Object O Complete the path of the rays to show how an image can be formed by the converging lens. L FF Since both blue coloured rays originate from the tip of the object arrow, both rays should end at the tip of the image arrow.

59. Summary By the end of this lesson pupils should be able to: Use the terms normal, angle of incidence and angle of reflection (for reflection). State the laws of reflection and use it in calculations and measurements. Use the terms normal, angle of incidence and angle of refraction (for refraction). Solve problems using sin i ÷ sin r. Define refractive index of a medium in terms of the ratio of speed of light in vacuum and in the medium. Explain the terms critical angle and total internal reflection.

60. Summary Describe the action of a thin converging lens on a beam of light. Define the term focal length for a thin converging lens. Draw ray diagrams to illustrate the formation of real and virtual images of an object by a thin converging lens.