1. Oku losZ{k.k {ks=Qy,oa vk;ru

2. ewyHkwr vkdkj dks.k Angle,d gh fcUnq ls fudyus okyh nks js[kkvksa ds chp ds Hkkx dks dks.k dgrs gSa A muds mHk;fu"B fcUnq dks 'kh"kZ vkSj nksuksa js[kkvksa dks Hkqtk,a dgrs gSaA va'kksa ds vk/kkj ij dks.k 5 izdkj ds gksrs gSa % U;wudks.k vf/kd dks.k ledks.k ¼90^ ls de½ ¼90^ ls vf/kd½ ¼90^ ds cjkcj½ ljy js[kk ;k _tq js[kk Straight Line ljy js[kk ;k _tq js[kk,d fcUnq ls nwljs fcUnq ds,d gh fn'kk esa xeu djrh gSA mlds pyus dk tks iFk curk gS mls ljy js[kk dgrs gSA

3.  _tq dks.k 180^ ds dks.k dks _tq dks.k dgrs gSA _tq dks.k ljy dks.k Hkh dgrs gSA 180 ^ c v  o`gn~ dks.k tks dks.k 180^ ls vf/kd vkSj 360^ ls de curk gS mls o`gn~ dks.k dgrs gSA fLFkfr ds vk/kkj ij dks.k 3 izdkj ds gksrs gSa % vklUu dks.k'kh"kZfHkeq[k dks.kyEc

4. prqHkZt,oa f=Hkqt prqHkqZt Quadrilateral Pkkj js[kkvksa ls can vkd`fr dks prqHkqZt dgrs gSa A izR;sd js[kk dks Hkqtk vkSj fdUgh 2 Hkqtkvksa ds mHk;fu"B fcUnq dks 'kh"kZ dgrs gSaA f=Hkqt Triangle Rkhu js[kkvksa ls can vkd`fr dks f=Hkqt dgrs gSa A izR;sd js[kk dks Hkqtk vkSj fdUgh 2 Hkqtkvksa ds mHk;fu"B fcUnq dks 'kh"kZ dgrs gSaA Ok`RRk Circle,d can odz vkd`fr ftlds lHkh fcUnq,d fLFkj fcUnq ls leku nwjh ij gksrs gSa o`Rr dgykrk gSA A bl fLFkj fcUnq dks dsUnzfcUnq vkSj dsUnz ls o`RRk ds fdlh Hkh fcUnq dks tksM+us okyh js[kk dks f=T;k dgrs gSaA

5. Copyright © 2000 by Monica Yuskaitis Quadrilateral Family parallelogram rectangle rhombus square trapezoid

6. f=Hkqt ds izdkj v& Hkqtkvksa ds vk/kkj ij lef)ckgq f=Hkqt Isosceles Triangle lef=ckgq f=Hkqt Equilateral Triangle fo"keckgw f=Hkqt Scalene Triangle ledks.k f=Hkqt Right angled Triangle vf/kd dks.k f=Hkqt Obtuse Triangle U;wudks.k f=Hkqt Acute Triangle Lkef=dks.k f=Hkqt Equiangular Triangle Ck& dks.k ds vk/kkj ij

7. The area of a shape is defined as the number of square units that cover a closed figure. For most of the shape that we will be dealing with there is a formula for calculating the area. Area of a Rectangle b A = bh b = the base of the rectangle h = the height of the rectangle h Area of a Parallelogram b A = bh b = the base of the rectangle h = the height of the rectangle Area of a Trapezoid A = ½ (b1+ b2 )h b1 = the one base of the trapezoid b2 = the other base of the trapezoid h = the height of the trapezoid Area of a Triangle A = 1 / 2 bh b = the base of the triangle h = the height of the triangle Area of a Triangle Heron’s Formula for a triangle with only sides A = √{s (s -a )(s -b )(s -c )} a = one side of the triangle b = another side of the triangle c = the third side of the triangle

8. Surface Area of a Rectangular Solid (Box) SA = 2(lw +lh +wh ) l = length of the base of the solid w = width of the base of the solid h = height of the solid

9. Volume Volume of a Solid with a Matching Base and Top V =Ah A= area of the base of the solid h = height of the solid Volume of a Rectangular Solid (specific type of solid with matching base and top) V = lwh l = length of the base of the solid w = width of the base of the solid h = height of the solid

10. A cylinder is an object with straight sides and circular ends of the same size. The volume of a cylinder can be found in the same way you find the volume of a solid with a matching base and top. Volume of a Cylinder V =Ah Or V =  r 2 h A = the area of the base of the cylinder h = the height of the cylinder

11. The surface area of a cylinder can be easily found when you realize that you have to find the area of the circular base and top and add that to the area of the sides. If you slice the side of the cylinder in a straight line from top to bottom and open it up, you will see that it makes a rectangle. The base of the rectangle is the circumference of the circular base, and the height of the rectangle is the height of the cylinder. Surface Area of a Cylinder SA = 2(  r 2 ) + 2  rh r = the radius of the circular base of the cylinder h = the height of the cylinder π = the number that is approximated by 3.141593

12. Volume of a Cone V = 1 / 3  r 2 h r = radius of the base of the cone h= height of the cone

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