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We have been studying patterns of inheritance for the last several weeks. We have used such terminology as traits and genes, but have not specifically targeted the mechanism behind the transfer of those traits and genes from generation to generation. Identify the material that provides the instructions for ALL of your traits and design an experiment to prove that this material is in fact the “stuff” of what you are made.
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T.H. Morgan ◦ worked with Drosophila ◦ associated phenotype with specific chromosome white-eyed male had specific X chromosome 1908 | 1933
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Morgan’s conclusions ◦ genes on chromosomes ◦ BIG QUESTION – The Gene Wars: Is protein or DNA that are the genes? Why all the fuss???
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1928 Frederick Griffith Observe the following data – explain what is going on
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Conclusion: heat-killed, virulent bacteria must have released genetic material transferred to R cells Transformation – DNA from dead cells cut into fragments & exits cell → healthy cells pick up free floating DNA and integrate chromosomes via recombination
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Oswald Avery Maclyn McCarty Colin MacLeod
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Avery, McCarty & MacLeod ◦ purified DNA & proteins separately from Streptococcus pneumonia bacteria Experimental Question: which will transform non-pathogenic bacteria? ◦ 1. injected protein into bacteria Mice lived! ◦ 2. injected DNA into bacteria transformed bacteria Mice died!
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Alfred HersheyMartha Chase 1952 | 1969
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Protein coat labeled with 35 S DNA labeled with 32 P bacterial cells are agitated to remove viral protein coats 35 S radioactivity found in the medium 32 P radioactivity found in the bacterial cells Which radioactive marker is found inside the cell? This will be the molecule containing genetic info! bacteriophages infect bacterial cells T2 bacteriophages are labeled with radioactive isotopes S vs. P
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Watson and Crick 1952
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DNA composition: “Chargaff’s rules” ◦ varies from species to species ◦ all 4 bases not in equal quantity ◦ bases present in characteristic ratio humans: A = 30.9% T = 29.4% G = 19.9% C = 19.8% 1947 Rules A = T C = G
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Review with Hank!
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◦ base pairing suggests that each side can serve as a template for a new strand “It has not escaped our notice that the specific pairing we have postulated immediately suggests a possible copying mechanism for the genetic material.”— Watson & Crick * DNA Replication Machinery – 1:45DNA Replication Machinery
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Prokaryotes: DNA usually circular (1 fork) Eukaryotes: DNA linear (many forks)
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BBacterial DNA is circular - Animation EEukaryotic DNA is linear ◦C◦C an you think of any problems this may pose in the successful completion of replication? Animation
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A scientist is using an ampicillin-sensitive strain of bacteria that cannot use lactose because it has a nonfunctional gene in the lac operon. She has two plasmids. One contains a functional copy of the affected gene of the lac operon, and the other contains the gene for ampicillin resistance. Using restriction enzymes and DNA ligase, she forms a recombinant plasmid containing both genes. She then adds a high concentration of the plasmid to a tube of the bacteria in a medium for bacterial growth that contains glucose as the only energy source. This tube (+) and a control tube (-) with similar bacteria but no plasmid are both incubated under the appropriate conditions for growth and plasmid uptake. The scientist then spreads a sample of each bacterial culture (+ and -) on each of the three types of plates indicated below.
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If no new mutations occur, it would be most reasonable to expect bacterial growth on which of the following plates? a. 1 and 2 only b. 3 and 4 only c. 5 and 6 only d. 4, 5, and 6 only e. 1, 2, 3, and 4 only
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If the scientist had forgotten to use DNA ligase during the preparation of the recombinant plasmid, bacterial growth would most likely have occurred on which of the following? a. 1 and 2 only b. 1 and 4 only c. 4 and 5 only d. 1, 2, and 3 only e. 4, 5, and 6 only
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proteinscellsbodies How does DNA code for cells & bodies? DNA
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Flow of genetic information in a cell ◦ DNA to proteins? transcription translation replication protein RNA DNAtrait
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suggest genes code for enzymes ◦ Disruptions in pathways result in lack of an enzyme disease variation of phenotype ABCDE disease metabolic pathway
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Make a model! o Steps o Structures
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ribose sugar N-bases ◦ uracil instead of thymine ◦ U : A ◦ C : G single stranded many RNAs ◦ mRNA, tRNA, rRNA, siRNA… RNADNA transcription
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Making mRNA ◦ transcribed DNA strand = template strand ◦ untranscribed DNA strand = coding strand ◦ synthesize complementary RNA strand transcription bubble ◦ Enzymes involved RNA polymerase Helicase template strand mRNA RNA polymerase coding strand DNA C C C C C C C CC C G G G GG GG G G G A A A AA A A A A A A A A T T T T T T T T T T T T UU 5 3 5 3 3 5 build RNA 5 3
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3 types of RNA polymerases 1. RNA polymerase 1 transcribe rRNA genes ONLY makes ribosomes 2. RNA polymerase 2 transcribe genes into mRNA 3. RNA polymerase 3 transcribe tRNA genes ONLY **each has a specific promoter sequence it recognizes**
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Promoter region - site marking the start of gene ◦ TATA box binding site ◦ transcription factors (ie. proteins, hormones?) - on/off switch; trigger binding of RNA pol ◦ RNA polymerase Enhancer region ◦ binding site far upstream ◦ turns transcription on HIGH
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Eukaryotic genes contain “fluff” – spliced ◦ exons = expressed / coding DNA ◦ introns = the junk; inbetween sequence; now thought to be involved in switches 5’ Cap & PolyA tail added eukaryotic DNA exon = coding (expressed) sequence intron = noncoding (inbetween) sequence primary mRNA transcript mature mRNA transcript pre-mRNA spliced mRNA ~10,000 bases ~1,000 bases
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snRNPs exon intron snRNA 5'3' spliceosome exon excised intron 5' 3' lariat exon mature mRNA 5' snRNPs “snurps” ◦ small nuclear RNA ◦ Proteins Spliceosome ◦ several snRNPs ◦ recognize splice site sequence cut & paste gene
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A A A A A 3' poly-A tail mRNA 5' 5' cap 3' G P P P 50-250 A’s Enzymes in cytoplasm attack mRNA – protection is needed add 5 GTP cap add poly-A tail longer the tail, longer mRNA lasts: produces more protein
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Make a model! o Steps o Structures
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TAC GCA CAT TTA CGT ACG CGG DNA AUG CGU GUA AAU GCA UGC GCC mRNA Met Arg Val Asn Ala Cys Ala protein ? How can you code for 20 amino acids with only 4 nucleotide bases (A,U,G,C)? 4 4 20 ATCG AUCG
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20 different amino acids aa’s coded for by THREE nucleotides –codons 4 bases, 3 per codon: 4 3 = 64 total possible combinations
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WOBBLE Code is redundant ◦ several codons for each amino acid ◦ 3rd base “wobble” ◦ Most codons = aa’s Start codon AUG methionine Stop codons UGA, UAA, UAG
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“Clover leaf” structure ◦ anticodon on “clover leaf” end ◦ amino acid attached to 3 end
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Aminoacyl tRNA synthetase - enzyme bonds aa’s to tRNA ◦ requires energy ATP AMP bond is unstable can easily release amino acid at ribosome activating enzyme anticodon tRNA Trp binds to UGG codon of mRNA Trp mRNA C=O OH H2OH2O O tRNA Trp tryptophan attached to tRNA Trp C=O O
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RIBOSOMES!!! Facilitate binding of tRNA anticodon to mRNA codon Organelle or enzyme?? Structure ◦ rRNA & proteins ◦ 2 subunits large small ◦ 3 sites
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A site (aminoacyl-tRNA site) ◦ tRNA carrying next aa to be added to chain binds here P site (peptidyl-tRNA site) ◦ holds tRNA carrying growing polypeptide chain E site (exit site) ◦ empty tRNA leaves ribosome from exit site Met U U A C A G APE 3' U U A C A G APE 5'
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Initiation ◦ brings together mRNA, ribosomal subunits, initiator tRNA Elongation ◦ adding amino acids based on codon sequence Termination ◦ end codon 123
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Prokaryotes ◦ DNA in cytoplasm ◦ circular chromosome ◦ naked DNA ◦ no introns ◦ continuous process Eukaryotes ◦ DNA in nucleus ◦ linear chromosomes ◦ DNA wound on histone proteins ◦ introns vs. exons ◦ mRNA processing
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Transcription & translation simultaneous in bacteria ◦ DNA in cytoplasm ◦ no mRNA editing ◦ ribosomes read mRNA as transcribed ◦ Faster than in eukaryotes (DNA to protein ~1hr)
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Transcription Transcription mRNA processing mRNA processing mRNA splicing mRNA splicing
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Translation Animation Translation Animation Protein Synthesis Protein Synthesis
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