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Check it out! 2.2.2: Solving Systems of Linear Equations 1.

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Presentation on theme: "Check it out! 2.2.2: Solving Systems of Linear Equations 1."— Presentation transcript:

1 Check it out! 2.2.2: Solving Systems of Linear Equations 1

2 Benito is a waiter. He earns a base salary of $1,500 a month, plus 20% of the price of the meals he serves. 1.Write an equation to predict the amount of money Benito will earn if he serves $350 in meals. 2.Benito earned $1,650 in one month. What was the total price of the meals that Benito served? 3.Create a graph to show the possible amount of money Benito could earn each month. 2

3 1.Write an equation to predict the amount of money Benito will earn if he serves $350 in meals. Translate the verbal description of Benito’s pay into an algebraic equation. Let x represent the total cost of the meals Benito serves. Let y represent the amount of money Benito earns. Benito earns a base salary of $1,500, plus 20% of the price of the meals. 20% of the price of the meals is 0.20x. y = 1500 + 0.20x 2.2.2: Solving Systems of Linear Equations 3

4 Benito served $350 in food. Substitute $350 for x and solve the equation for y, the amount of money Benito will earn. y = 1500 + 0.20xOriginal equation y = 1500 + 0.20(350) Substitute 350 for x. y = 1500 + 70Simplify. y = 1570 Benito will earn $1,570 if he serves $350 worth of food. 2.2.2: Solving Systems of Linear Equations 4

5 2.Benito earned $1,650 in one month. What was the total price of the meals that Benito served? Use your equation from part 1 to find the price of the meals Benito served. Substitute $1,650 for y, the total amount of money Benito earned. 1650 = 1500 + 0.20x 2.2.2: Solving Systems of Linear Equations 5

6 Solve for x. Benito served $750 worth of meals. 2.2.2: Solving Systems of Linear Equations 6 1650 = 1500 + 0.20xOriginal equation 150 = 0.20x Subtract 1,500 from both sides. 750 = xDivide both sides by 0.20.

7 3.Create a graph to show the possible amount of money Benito could earn each month. The equation y = 1500 + 0.20x can be graphed using slope-intercept form. The slope of the equation is 0.20. The y-intercept is 1,500. 2.2.2: Solving Systems of Linear Equations 7

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