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Physical Modelling: 1.Out there world inside here 2.Modelling and Design Cycle 3.Practical example: Passive Dynamic Walkers 4.Base systems and concepts.

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Presentation on theme: "Physical Modelling: 1.Out there world inside here 2.Modelling and Design Cycle 3.Practical example: Passive Dynamic Walkers 4.Base systems and concepts."— Presentation transcript:

1 Physical Modelling: 1.Out there world inside here 2.Modelling and Design Cycle 3.Practical example: Passive Dynamic Walkers 4.Base systems and concepts 5.Ideals, assumptions and real life 6.Similarities in systems and responses

2 Design Cycle: https://stillwater.sharepoint.okstate.edu/ENGR1113/default.aspx

3 Similarities in systems and responses: 1.Similarities in systems – why is a spring like a water tank like a capacitor??? 2.First derivative time response 3.Second derivative time responses (note there is more than one!) 4.Damping 5.Parallel verses Serial connection of components

4 Electronic components: Resistors: Voltage is proportional to current, Ohms law V = RI Voltage - Impedance Current http://ecee.colorado.edu/~mathys/ ecen1400/labs/resistors.html

5 Electronic components: Resistors: Voltage is proportional to current, Ohms law V = RI Voltage - Current http://ecee.colorado.edu/~mathys/ ecen1400/labs/resistors.html

6 Electronic components: Capacitors: Voltage is proportional to integral of current Voltage - Current http://ecee.colorado.edu/~mathys /ecen1400/labs/capacitors.html

7 Electronic components: Capacitors: Voltage is proportional to integral of current Voltage - Impedance Current [think of s as the rate of change of output variable in an instant] http://ecee.colorado.edu/~mathys /ecen1400/labs/capacitors.html

8 Electronic components: Inductors: Voltage is proportional to differential of current Voltage - Current http://electronics.stackexchange.com/

9 Electronic components: Inductors: Voltage is proportional to differential of current Voltage - Impedance Current http://electronics.stackexchange.com/

10 Force - Impedance Distance Spring Damper Mass Source Nise 2004 Mechanical: Electrical: Capacitor Resistor Inductor Source Nise 2004 Voltage - Impedance Current

11 Force - Impedance Velocity Spring Damper Mass Source Nise 2004 Mechanical Electrical: Capacitor Resistor Inductor Source Nise 2004 Voltage - Impedance Current

12 Modelling: Dynamic Systems www.pbase.com www.millhouse.nl

13 Consider dynamic systems: these change with time As an example consider water system with two tanks Water will flow from first tank to second [Assume I stays constant due to nature of Dams] Plot time response of system….? Modelling: Dynamic Systems I F L

14 Water flows because of pressure difference [Ignore atmospheric pressure – approx. equal at both ends of pipe] If have water at one end - what is its pressure? [Tanks with constant cross sectional area A] Pressure is force per unit area, = F / A, Force (F) is mass of water times gravity g Mass of water (M) is volume of water * density M = V *  Volume (V) is height of water, h, times its area A:V = h * A Combining: pressure is Dynamic Systems F Pressure

15 For first tank, pressure is p f = I *  * g For second tank, pressure is p s = L *  * g Thus flow is proportional to the difference in pressures: driving (effort) variable Flow ∝ p f – p s ∝ (I-L) *  * g as well as on the pipe (its restrictance, R) Here R is the constant of proportionality… Does flow Increase or decrease as the constant R is changed in different systems? Flow changes volume of tanks: Volume change = A * rate of change in height (L) = Flow

16 Flow changes volume of tanks: Volume change = A * rate of change in height (L) = Flow We write ‘rate of change in height L’ as dL/dt = Flow / A A tank has a capacitance - constantscollected together in C = Thus rate of change in height L: = Flow stops, and there is no change in height when I = L

17 Level change – not instantaneous Initially: Large height difference  Large flow  L up a lot Then: Height difference less  Less flow  L increases, but by less Later: Height difference ‘lesser’  Less flow  L up, but by less, etc Graphically we can thus argue the variation of level L and flow F is: Dynamic Flow F t T T L t I

18 Any system of the form: Rate of change of output variable in an instant = Input variable – Output variable Has a time response (depending on step input): Time Response of System Time Output Exponential

19 Time responses: Proportional components Or Ratio governed by constant of proportionality x f Time x t Input Output Time x t Input Output

20 Time responses: Proportional to derivative components (+ previous) Or Ratio governed by gain constant Time of response governed by time constant dx/dt f Time x t Input Output Time x t Input Output

21 Time responses: Proportional to second derivative components (+ previous) Or Ratio governed by gain constant Time of response governed by time constants Overshoot governed by damping constant. d 2 x/dt 2 f Time x t Input Output Time x t Input Output Time x t Input Output

22 Serial connection of components: Opposite to parallel connections What is equivalent spring? Draw a free body diagram of a spring Write down individual equations:F t = k t x t Consider laws to combine them:x t = x 1 + x 2 Consider what does not change:Force must be equal on each spring F t = F 1 = F 2 F t = k t x t = k t (x 1 + x 2 ) = k t (F 1 / k 1 + F 2 / k 2 ) cancel forces: k t = (1 / k 1 + 1 / k 2 ) -1 Can extend method to any number of springs in series https://notendur.hi.is/eme1/skoli/edl_h05/ masteringphysics/13/springinseries.htm

23 Parallel connection of components: Opposite to serial connections Draw a free body diagram of a spring Write down individual equations:F t = k t x t Consider laws to combine them:F t = F 1 + F 2 Consider what does not change:x t = x 1 = x 2 F t = k t x t F 1 + F 2 = k t x t k t x t = k 1 x 1 + k 2 x 2 cancel distances: k t = k 1 + k 2 Can extend method to any number of springs in series

24 Remember to test: http://sploid.gizmodo.com/cool-new- video-shows-nasas-flying-saucer-in-action- at-l-1618380912/+jesusdiaz

25 Example test questions for PM 1.In the Researching phase of the engineering design cycle: state and describe at least five (5) steps when defining the problem. 2.Given a system has the following instantaneous (dynamic) relationships, sketch their characteristic graphs on appropriate axes: i) y ∝ x ii) y ∝ dx/dt iii) y ∝ d 2 x/dt 2 Initially a system starts with a component with the relationship given in (i) sketch its time response to a step change in the effort variable. Plot both the input and output on the same axes (Hint: time is the independent variable). An additional component with the relationship given in (ii) is added; add the new time response clearly labelling the graph. Finally, a component described by (iii) is added; plot and discuss the possible outputs. 3.Given two resistors are in parallel in a connected circuit with a unit voltage effort driving the current flow, draw the diagram labelling important components, variables and constants. Calculate the equivalent resistor value for the circuit. Help session available in Mon, Wed AM103, @5 PM, with Howard


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