1. Bellringer
Compare and explain in complete sentences
what is distance.

2. Previous homework Graph your motion: distance, velocity, and
acceleration for your travel on a bus/car
from home to school and back

3. Homework
CALCULATE DISTANCE, VELOCITY AT ANY TIME FOR THE ARROW SHOOT VERTICALLY IN THE AIR

4. Graphing Motion
Every Picture Tells A Story

5. Position Time Graphs of Accelerated motion
Position vs. time graphs give you an easy and obvious way of determining an object’s displacement at any given time, and a subtler way of determining that object’s velocity at any given time.

6. A very useful aspect of these graphs is that the area under the v-t graph tells us the distance travelled during the motion.

7. Since the slope represents the speed, if the speed is
increasing over time, the slope must be also be increasing
over time.
The graph is a curve that gets steeper as you move along
The x-axis.
A position-time graph for a ball in free fall is shown below.

8. The graph of an object slowing down is also cuved. The
example below show the position-time graph for a car coming
to a gradual stop at a red l ight.
As time passes, the car’s speed decreases. The slope must
therefore decrease.

10. answers

11. Velocity vs Time Graphsd t
slope = velocity
slope = acceleration v t
area = distance a t
area = velocity

12. If the graph is a horizontal line, there is no change in velocity, therefore there is no acceleration (the slope is 0).
If the acceleration is positive then the slope is positive (the line moves upward to the right).
If the acceleration is negative, then the slope is negative (the line moves downward to the right).).

13. Calculating acceleration from a velocity-time graph

14. Calculating the distance on velocity-time graph.

15. An object is moving in the positive direction if the line is located in the positive region of the graph (whether it is sloping up or sloping down).
An object is moving in the negative direction if the line is located in the negative region of the graph (whether it is sloping up or sloping down).
If a line crosses over the x-axis from the positive region to the negative region of the graph (or vice versa), then the object has changed directions.

16. The object moves in the + direction at a constant speed - zero acceleration (interval A). The object then continues in the + direction while slowing down with a negative acceleration (interval B). Finally, the object moves at a constant speed in the + direction, slower than before (interval C).

17. The object moves in the + direction while slowing down; this involves a negative acceleration (interval A). It then remains at rest (interval B). The object then moves in the - direction while speeding up; this also involves a negative acceleration (interval C).

18. The object moves in the + direction with a constant velocity and zero acceleration (interval A). The object then slows down while moving in the + direction (i.e., it has a negative acceleration) until it finally reaches a 0 velocity (stops) (interval B). Then the object moves in the - direction while speeding up; this corresponds to a - acceleration (interval C).

19. a plot of velocity versus time can also be used to determine the displacement of an object. The diagram below shows three different velocity-time graphs; the shaded regions between the line and the time-axis represents the displacement during the stated time interval.

23. The velocity-time graph for a two-stage rocket is shown below
The velocity-time graph for a two-stage rocket is shown below. Use the graph and your understanding of slope calculations to determine the acceleration of the rocket during the listed time intervals. When finished, click the buttons to see the answers.
20 m/s2
40 m/s2
-20 m/s2

24. Constant positive (rightward) velocity

25. Constant negative (leftward) velocity

26. Rightward velocity with rightward acceleration.

27. Rightward Velocity and negative acceleration

28. Leftward velocity, leftward acceleration

29. Leftward velocity rightward acceleration

30. Acceleration Acceleration – the rate at which velocity is changing
Acceleration = ∆v/ ∆t
Can increase or decrease (sometimes called deceleration)
Think of traveling in a car, you can feel the acceleration
3 ways to accelerate in a car
Brake pedal—slowing down; coming to a stop (changing speed)
Steering wheel—going around a corner or curve (changing direction)
Gas pedal—leaving from a stopped position (changing speed)

32. The object moves in the + direction at a constant speed - zero acceleration (interval A). The object then continues in the + direction while slowing down with a negative acceleration (interval B). Finally, the object moves at a constant speed in the + direction, slower than before (interval C).

33. The object moves in the + direction at a constant speed - zero acceleration (interval A). The object then continues in the + direction while slowing down with a negative acceleration (interval B). Finally, the object moves at a constant speed in the + direction, slower than before (interval C).

34. The object moves in the + direction while slowing down; this involves a negative acceleration (interval A). It then remains at rest (interval B). The object then moves in the - direction while speeding up; this also involves a negative acceleration (interval C).

35. Zero to 90s - On this graph we see a horizontal line that reads “5m/s” for those same first 90 seconds.
On a v-t graph a flat line means constant velocity. Constant velocity means zero acceleration.

37. Graphs of Motion—Uniform Velocity
The area under a velocity vs time graph is the displacement of the object.
Find the distance traveled by each object.

38. Acceleration
Suppose you are traveling in a car and your speed goes from 10.km/h to 60.km/h in 2.0s. What is your acceleration?
Suppose a car goes from 80.km/h to 15km/h in 5.0 seconds. What is the acceleration?
A car is coasting backwards down a hill at a speed of 3.0m/s when the driver gets the engine started. After 2.5s, the car is moving uphill at 4.5m/s. Assuming that uphill is in the positive direction, what is the car’s average acceleration?

39. Graphs of Motion
Velocity vs time graphs: How can you tell if the object is accelerating or decelerating?
Accelerating (speeding up) – when the magnitude of the velocity is increasing
Decelerating (slowing down) – when the magnitude of the velocity is decreasing

40. Which pair of graphs shows the same motion?

41. Stage 1: The car moves forwards from the origin to in the first 5 s.

42. Stage 2: The car moves backwards, passes the origin, to in the next 5 s.

43. Stage 3: The car remains at rest in the last 5 s.

51. What is the velocity for each stage of the journey?
b. What is the average (mean) velocity for the whole journey

54. Distance or Displacement
Distance—how far an object has traveled
Indianapolis is about 45 miles away…
The distance to Indianapolis is 45 miles; the distance back to Bloomington is 45 miles—the total distance traveled round trip is 90 miles
Displacement—how far an object is from its original position (direction matters)
The displacement to Indianapolis is 45 miles north; the displacement back to Bloomington is 45 miles south—the total displacement is 0 miles
You can find displacement by
Finding the area under a velocity time graph
Using the equation d = vavg * t

57. Understanding the Connection Between Slope and Velocity
The slope of a line for a distance vs. time graph represents the velocity for the object in motion.
Slope can be determined using the following formula:
The change in y values divided by the change in x values determines the average velocity for the object between any two points.

58. Pick two points on the line and determine their coordinates.
Determine the difference in y-coordinates of these two points (rise).
Determine the difference in x-coordinates for these two points (run).
Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

59. rise over run
Calculate the velocity between 3 and 4 seconds.
Note: This is a constant speed graph, so the velocity
should be the same at all points.