1. An Introduction to Forces: More Practice
Draw a free-body diagram for each of the following objects: (a) A car engine being lifted from a car by a rope attached to a pulley

2. An Introduction to Forces: More Practice
Draw a free-body diagram for each of the following objects: (b) an car moving with constant velocity on a level road

3. An Introduction to Forces: More Practice
Draw a free-body diagram for each of the following objects: (c) an apple hanging from a tree branch

4. An Introduction to Forces: More Practice
Draw a free-body diagram for each of the following objects: (d) a skydiver being slowed by a parachute

5. An Introduction to Forces: More Practice
Ms. Rosebery is pulling across level snow a sled on which is sitting her daughter Ivy. Tied to the back of Ivy's sled is another tiny sled on which Ivy's baby doll is sitting. Draw the free-body diagrams for (a) Ms. Rosebery

6. An Introduction to Forces: More Practice
Ms. Rosebery is pulling across level snow a sled on which is sitting her daughter Ivy. Tied to the back of Ivy's sled is another tiny sled on which Ivy's baby doll is sitting. Draw the free-body diagrams for (b) Ivy

7. An Introduction to Forces: More Practice
Ms. Rosebery is pulling across level snow a sled on which is sitting her daughter Ivy. Tied to the back of Ivy's sled is another tiny sled on which Ivy's baby doll is sitting. Draw the free-body diagrams for (d) Ivy’s sled

8. An Introduction to Forces: More Practice
Ms. Rosebery is pulling across level snow a sled on which is sitting her daughter Ivy. Tied to the back of Ivy's sled is another tiny sled on which Ivy's baby doll is sitting. Draw the free-body diagrams for (d) Ivy’s doll’s sled

9. Newton’s 1st Law of Motion: Learning Goal
The student will be able to state Newton’s 1st Law and apply it in qualitative and quantitative terms to explain the effect of forces acting on objects. (B3.4)

10. Newton’s 1st Law of Motion

11. Net Force The net force is the sum of all forces acting on an object.
Example: A weightlifter holds a weight above his head by exerting a force of 1.6 kN [up]. The force of gravity acting on the weight is 1.6 kN [down]. Draw a FBD of the weight. What is the net force on the weight?

12. Net Force
FA=1.6 kN
Fg=1.6 kN

13. Net Force The net force is zero: 1.6 kN + (-1.6 kN) = 0 FA=1.6 kN
Fg=1.6 kN

14. Newton’s First Law of Motion
If there is no net force acting on an object, the object will remain at rest

15. Newton’s First Law of Motion
If there is no net force acting on an object, the object will remain at rest

16. Newton’s First Law of Motion
If there is no net force acting on an object, the object will remain at rest or will keep moving at the same constant velocity.

17. Newton’s First Law of Motion
If there is no net force acting on an object, the object will remain at rest or will keep moving at the same constant velocity.
(Conversely, if an object is at rest or is moving at constant velocity, there is no net force acting upon it.)

18. Inertia
This is the principle of inertia, first articulated by Galileo:

19. “Inertia is a property of matter.”
Inertia is the property of matter that causes it to resist changes to its motion.
The greater the mass of an object, the greater its inertia.
“Inertia is a property of matter.”

21. Newton’s First Law of Motion
Question: An object is being pushed along at constant velocity by a force of 5 N [left]. What is the force of friction acting on the object?

22. Newton’s First Law of Motion
Question: An object is being pushed along at constant velocity by a force of 5 N [left]. What is the force of friction acting on the object?
If the velocity is constant, there is no net force, so the force of friction must be equal in magnitude and opposite in direction to the applied force:

23. Newton’s First Law of Motion
Question: An object is being pushed along at constant velocity by a force of 5 N [left]. What is the force of friction acting on the object?
If the velocity is constant, there is no net force, so the force of friction must be equal in magnitude and opposite in direction to the applied force:
Ff = 5 N [right]

24. More Practice
Explaining Why with Newton’s 1st Law of Motion