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 Nearly everything we use is manufactured from chemicals. › Soaps, shampoos, conditioners, cd’s, cosmetics, medications, and clothes.  For a manufacturer.

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Presentation on theme: " Nearly everything we use is manufactured from chemicals. › Soaps, shampoos, conditioners, cd’s, cosmetics, medications, and clothes.  For a manufacturer."— Presentation transcript:

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2  Nearly everything we use is manufactured from chemicals. › Soaps, shampoos, conditioners, cd’s, cosmetics, medications, and clothes.  For a manufacturer to make a profit the cost of making any of these items can’t be more than the money paid for them.  Chemical processes carried out in industry must be economical, this is where balanced equations help.

3  Equations are a chemist’s recipe. ◦ They tell chemists what amounts of reactants to mix and what amounts of products to expect.  When you know the quantity of one substance in a reaction, you can calculate the quantity of any other substance consumed or created in the rxn. ◦ Quantity meaning the amount of a substance in grams, liters, molecules, or moles.

4  YouTube - How an Airbag works YouTube - How an Airbag works

5  The calculation of quantities in chemical reactions is called stoichiometry.

6  Assume that the major components of the bike are the frame (F), the seat (S), the wheels (W), the handlebars (H), and the pedals (P).  The finished bike has a “formula” of FSW 2 HP 2.  The balanced equation for the production of 1 bike is. F +S+2W+H+2P  FSW 2 HP 2

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8  Now in a 5 day workweek, A company is scheduled to make 640 bikes. How many wheels should be in the plant on Monday morning to make these bikes?  What do we know? ◦ Number of bikes = 640 bikes ◦ 1 FSW 2 HP 2 =2W (balanced eqn)  What is unknown? ◦ # of wheels = ? wheels F +S+2W+H+2P  FSW 2 HP 2

9  The connection between wheels and bikes is 2 wheels per bike. We can use this information as a conversion factor to do the calculation. 640 FSW 2 HP 2 1 FSW 2 HP 2 2 W = 1280 wheels We can make the same kinds of connections from a chemical rxn eqn. N 2 (g) + 3H 2 (g)  2NH 3 (g) The key is the “coefficient ratio”.

10 ◦ The coefficients of the balanced chemical equation indicate the numbers of moles of reactants and products in a chemical rxn.  1 mole of N 2 reacts with 3 moles of H 2 to produce 2 moles of NH 3. ◦ N 2 and H 2 will always react to form ammonia in this 1:3:2 ratio of moles.  So if you started with 10 moles of N 2 it would take 30 moles of H 2 and would produce 20 moles of NH 3 N 2 (g) + 3H 2 (g)  2NH 3 (g)

11  Using the coefficients, from the balanced equation to make connections between reactants and products, is the most important information that a rxn equation provides. › Using this information, you can calculate the amounts of the reactants involved and the amount of product you might expect. › Any calculation done with the next process is a theoretical number, the real world isn’t always perfect.

12  The following rxn shows the synthesis of aluminum oxide. 3O 2 (g) + 4Al(s)  2Al 2 O 3 (s) If you only had 1.8 mols of Al how much product could you make? Given: 1.8 moles of Al Uknown: ____ moles of Al 2 O 3 3O 2 (g) + 4Al(s)  2Al 2 O 3 (s)

13  Solve for the unknown: 1.8 mol Al 4 mol Al 2 mol Al 2 O 3 = 0.90mol Al 2 O 3 3O 2 (g) + 4Al(s)  2Al 2 O 3 (s) Mole Ratio

14  The following rxn shows the synthesis of aluminum oxide. 3O 2 (g) + 4Al(s)  2Al 2 O 3 (s) If you wanted to produce 24 mols of product how many mols of each reactant would you need? Given: 24 moles of Al 2 O 3 Uknown: ____ moles of Al ____ moles of O 2

15  Solve for the unknowns: 24 mol Al 2 O 3 2 mol Al 2 O 3 4 mol Al = 48 mol Al 3O 2 (g) + 4Al(s)  2Al 2 O 3 (s) 24 mol Al 2 O 3 2 mol Al 2 O 3 3 mol O 2 = 36 mol O 2

16  1. How many moles of potassium chlorate, KClO 3 are needed to produce 5 mol O 2 given the following BALANCED EQUATION? 2KClO 3  2 KCl + 3O 2

17  2. Sodium metal reacts with chlorine gas to produce sodium chloride. Write a balanced chemical equation. If 3.75 mol Na react with enough chlorine gas, how much sodium chloride is produced?

18  No lab balance measures moles directly, generally mass is the unit of choice.  From the mass of 1 reactant or product, the mass of any other reactant or product in a given chemical equation can be calculated, provided you have a balanced rxn equation.  As in mole-mole calcs, the unknown can be either a reactant or a product.

19 Acetylene gas (C 2 H 2 ) is produced by adding water to calcium carbide (CaC 2 ). How many grams of C 2 H 2 are produced by adding water to 5.00 g CaC 2 ? CaC 2 + 2H 2 O  C 2 H 2 + Ca(OH) 2

20  What do we know? ◦ Given mass = 5.0 g CaC 2 ◦ Mole ratio: 1 mol CaC 2 = 1 mol C 2 H 2 (from balanced equation) ◦ Molar Mass (MM) of CaC 2 = 64.0 g/mol CaC 2 ◦ Molar Mass of C 2 H 2 = 26.0g/mol C 2 H 2  What are we asked for? ◦ grams of C 2 H 2 produced CaC 2 + 2H 2 O  C 2 H 2 + Ca(OH) 2 mass A  moles A  moles B  mass B

21  What mass of copper is required to react with 4.00g of silver nitrate ? Cu + 2AgNO 3  2Ag + Cu(NO 3 ) 2

22 How many grams of O 2 are produced when a sample of 29.2 g of H 2 O is decomposed by electrolysis according to this balanced equation: 2H 2 O  2H 2 + O 2

23 Aspirin can be made from a chemical rxn between the reactants salicylic acid and acetic anhydride. The products of the rxn are acetyl-salicylic acid (aspirin) and acetic acid (vinegar). Our factory makes 125,000 100-count bottles of Bayer Aspirin/day. Each bottle contains 100 tablets, and each tablet contains 325mg of aspirin. How much in kgs + 10% for production problems, of each reactant must we have in order to meet production? C 7 H 6 O 3 + C 4 H 6 O 3  C 9 H 8 O 4 + HC 2 H 3 O 2 Salicylic acid Acetic anhydride aspirinvinegar

24  What are we asked for? ◦ Mass of salicylic acid in kgs + 10% ◦ Mass of acetic anhydride in kgs + 10%  What do we know? ◦ Make 125,000 aspirin bottles/day ◦ 100 aspirin/bottle ◦ 325 mg aspirin/tablet ◦ Mole ratio of aspirin to salicylic acid (1:1) and acetic anhydride (1:1) ◦ MM aspirin = 180.11g/mol ◦ MM C 7 H 6 O 3 = 138.10g/mol ◦ MM C 4 H 6 O 3 = 102.06g / mol C 7 H 6 O 3 + C 4 H 6 O 3  C 9 H 8 O 4 + HC 2 H 3 O 2

25 125,000 bottles 1 bottle 100 tablets 1 tablet 325mg asp. 1000 mg 1 g How many grams of aspirin do I need to produce? C 7 H 6 O 3 + C 4 H 6 O 3  C 9 H 8 O 4 + HC 2 H 3 O 2

26  In a chemical reaction, an insufficient quantity of any of the reactants will limit the amount of product that forms.  Limiting reactant (reagent): reactant that determines the amount of product that can be formed in the reaction.  Excess reactant (reagent): reactant that is not completely used up in a reaction.  Theoretical yield: The maximum quantity of product that a reaction could theoretically make (calculated based upon limiting reactant).

27 Calculate how much product ( Cu 2 S) each amount of reactant produces respectively.

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