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Published byRalph Palmer Modified over 8 years ago
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Transistors Three-terminal devices with three doped silicon regions and two P-N junctions versus a diode with two doped regions and one P-N junction Two basic ways of implementation: Bipolar Junction Transistor (BJT) Field-Effect Transistor (FET)
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Transistors Many types ! 3- terminal devices Made with semiconductor materials Used for … amplifier design and as switches ! (but many more … ) Common types: –BJT: Bipolar Junction Transistor –FET: Field Effect Transistor MOSFET: Metal Oxide Semiconductor FET MISFET: Metal Insulator Semiconductor FET CMOS Technology: Complementary Metal Oxide Semiconductor FETs !
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Transistors Bipolar Junction Transistors n n p B C E C = collector B = base E = emitter NPN transistor
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Transistors BJT
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Transistors BJT
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Transistors BJT PNP NPN
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Typical Transistor Circuit Both DC and AC signals DC signals for “powering” up the transistor and establishing an “operating point” AC signals – what we want to “process” i.e. amplify
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8 Common Emitter Amplifier
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9 DC Equivalent Circuit
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10 Common Emitter Amplifier AC Equivalent Circuit
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How Do We Handle Trans ?? Determine “operating mode” and replace transistor with appropriate model (linear!)
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12 Analysis Method
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13 Analysis Method
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14 a.Since V BB = 0.3V < 0.7V, transistor operates in CUTOFF region So I B = I C = 0. Write KVL equation around the input loop: V BB = 80k(I B ) + V BE V BE = 0.3 V Write KVL equation around the output loop: V CC = 2k(I C ) + V CE V CE = 10 V
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15 b.Since V BB = 2.7V > 0.7V, transistor is ON and V BE = 0.7V Write KVL equation around the input loop: V BB = 80k(I B ) + V BE I B = (2.7 – 0.7)/80k = 25 A Assuming ACTIVE mode, I C = I B I C = 2.5 mA Write KVL equation around the output loop: V CE = V CC – 2k(I C ) = 5V > 0.2V, so transistor IS in active region
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16 c.Since V BB = 6.7V > 0.7V, transistor is ON and V BE = 0.7V Write KVL equation around the input loop: V BB = 80k(I B ) + V BE I B = (6.7 – 0.7)/80k = 75 A Assuming ACTIVE mode, I C = I B I C = 7.5 mA Write KVL equation around the output loop: V CE = V CC – 2k(I C ) = –5V < 0.2V, so transistor is in SATURATION region I C = (V CC – V CE ) / 2k = 4.9 mA
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Transistors Field-Effect Transistors
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Transistors Field-Effect Transistors
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Transistors FET
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MOSFETs – Circuit Symbols n-MOS and p-MOS “working together” “n” and “p” for n- type and p-type semiconductor n-type: negative charges – electrons p-type: positive charges – “holes”
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Transistors FET When V G is positive, electrons in the p-type substrate are attracted to the oxide–silicon interface, and form an n-type conduction channel. The electrical model is represented by resistors in series. The transistor is in its ON state. NMOS
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Transistors FET When V G = 0, the area underneath the oxide layer is still p-type, which forms a “back-to-back” diode with the n region, as shown in the electrical representation. The transistor is in its OFF state. NMOS
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Transistors FET PMOS
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NMOS vs. PMOS - Operation
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NMOS vs PMOS INPUTNMOS High “1”ON Low “0”OFF INPUTPMOS High “1”OFF Low “0”ON
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NMOS Inverter What happens when V in is “high” ? i.e. logic level “1” What happens when V in is “low” ? i.e. logic level “0” 100011110100111010001110 INPUTOUTPUT High “1” Low “0”
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CMOS Inverter
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CMOS “Gate” ABOUT LO HI LO HI
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CMOS “AND Gate” ABOUT LO HI LO HI
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CMOS “AND Gate” ABOUT LO HI LO HI
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CMOS “AND Gate” ABOUT LO HILO HILO HI
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CMOS “AND Gate” ABOUT 000 010 100 111
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