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Chapter 10 Basic Concepts of Chemical Bonding

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Presentation on theme: "Chapter 10 Basic Concepts of Chemical Bonding"— Presentation transcript:

1 Chapter 10 Basic Concepts of Chemical Bonding

2 Which atom sometimes violates the octet rule?
N O F S

3 Which atom sometimes violates the octet rule?
N O F S

4 Order the following according to increasing atomic radius.
Ge Si Se Cl Ge < Si < Se < Cl Se < Si < Ge < Cl Si < Cl < Ge < Se Cl < Si < Se < Ge Si < Ge < Se < Cl

5 Order the following according to increasing atomic radius.
Ge Si Se Cl Ge < Si < Se < Cl Se < Si < Ge < Cl Si < Cl < Ge < Se Cl < Si < Se < Ge Si < Ge < Se < Cl

6 Which of the following will have the largest lattice energy?
CsCl ZnS CaF2 NaCl Diamond

7 Which of the following will have the largest lattice energy?
CsCl ZnS CaF2 NaCl Diamond

8 What is the electronic configuration of Fe2+?
4s2 3d4 4s1 3d5 3d5 3d6 4s2 3d8

9 What is the electronic configuration of Fe2+?
4s2 3d4 4s1 3d5 3d5 3d6 4s2 3d8

10 How many unpaired electrons are there in Cu+?
1 2 3 4

11 How many unpaired electrons are there in Cu+?
1 2 3 4

12 What is the average bond order in the molecule ozone, O3?
1 1.33 1.5 1.67 2

13 What is the average bond order in the molecule ozone, O3?
1 1.33 1.5 1.67 2

14 What is the average S—O bond order in the Lewis structure of sulfur trioxide, SO3?
0.5 1 1.33 1.5 2

15 What is the average S—O bond order in the Lewis structure of sulfur trioxide, SO3?
0.5 1 1.33 1.5 2

16 How many resonance structures can be drawn for NO3- ?
1 2 3 4 5

17 How many resonance structures can be drawn for NO3- ?
1 2 3 4 5

18 Considering formal charge, what is the preferred Lewis structure of NCO-?

19 Considering formal charge, what is the preferred Lewis structure of NCO-?

20 The electron configuration: 1s22s22p53s23p64s23d 7
is consistent with which atom? Fe Co Cu Ni

21 Correct Answer: The electron configuration [Ar]4s23d 7 corresponds to cobalt. Fe Co Cu Ni

22 The electron configuration of Fe3+ is which of the following?
1s22s22p53s23p64s23d6 1s22s22p53s23p64s23d3 1s22s22p53s23p63d5 1s22s22p53s23p64s13d4

23 Correct Answer: 1s22s22p53s23p64s23d6 1s22s22p53s23p64s23d3
1s22s22p53s23p63d5 1s22s22p53s23p64s13d4

24 Arrange the following ionic compounds in order of increasing lattice energy: LiCl, NaCl, MgCl2
NaCl < LiCl < MgCl2 LiCl < NaCl < MgCl2 MgCl2 < NaCl < LiCl

25 Correct Answer: Lattice energy depends on size of the ions and their charges. MgCl2 has the highest lattice energy because it has a more positive cation. LiCl is higher than NaCl because the interatomic distance between cation and ion is shorter. NaCl < LiCl < MgCl2 LiCl < NaCl < MgCl2 MgCl2 < NaCl < LiCl

26 Which of the following carbon–carbon atom bonds would be expected to be the shortest?
CC CC CC

27 Correct Answer: The bond length decreases as the bond enthalpy increases; in general, as the number of bonds between two atoms increases, the bond grows shorter and stronger. CC CC CC

28 Based on the electronegativities of the atoms, which of the following bonds would you predict is most polar? CC CN CO CSi CBr

29 Correct Answer: The difference in electronegativities is greatest between O (3.5) and C (2.5) for a net difference of Each of the other combinations yields a smaller value for electronegativity difference. CC CN CO CSi CBr

30 Boron (B) has an electronegativity of 2
Boron (B) has an electronegativity of 2.0; chlorine (Cl) has an electronegativity of Which of the following BEST describes a BCl bond? Ionic Polar covalent Nonpolar covalent

31 Correct Answer: The difference in electronegativities is 1.0 because Cl = 3.0 and B = This is too low to be an ionic bond but too high to be a nonpolar covalent bond. Ionic Polar covalent Nonpolar covalent

32 Which of the following molecules has a zero dipole moment?
HF H2O CS2 CHCl3

33 Correct Answer: HF H2O CS2 CHCl3 Even though each C=S bond is polar, their dipole vector quantities cancel each other out, and CS2 has no net dipole.

34 Which of the following BEST describes the formal charges on the atoms in the cyanide ion, CN ?

35 Correct Answer: The formal charges are calculated from the difference between number of valence electrons and number of electrons assigned to each atom in the Lewis structure, thus: C: 4 valence e  5 e =  1 N: 5 valence e  5 e = 0 C = +1, N = 1 C = 1, N = +1 C = 0, N = 1 C = 1, N = 0

36 Which is predicted to have the longest carbon–oxygen bonds: CO, CO2, or CO32?

37 Correct Answer: In CO, the carbon–oxygen bond is a triple bond, while in CO2 both carbon–oxygen bonds are double bonds. In CO32, there are three resonance structures and the average carbon–oxygen bond is 1 1/3. CO32 CO2 CO

38 Calculate DH from the following bond enthalpies for the reaction:
2 NCl3  N2 + 3 Cl2 D(NCl) = 200, D(NN) = 941, D(ClCl) = 242 (all kJ/mol). 467 kJ +467 kJ +17 kJ 983 kJ

39 Correct Answer: DH = S(bond enthalpies of bonds broken)  S ( bond enthalpies of bonds formed) DH = 6(200)  [ (242)] DH = 1200  (1667) DH =  467 467 kJ +467 kJ +17 kJ 983 kJ


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