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Section 8.2 – Integration by Parts. Find the Error The following is an example of a student response. How can you tell the final answer is incorrect?

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Presentation on theme: "Section 8.2 – Integration by Parts. Find the Error The following is an example of a student response. How can you tell the final answer is incorrect?"— Presentation transcript:

1 Section 8.2 – Integration by Parts

2 Find the Error The following is an example of a student response. How can you tell the final answer is incorrect? Where did the student make an error? The integral of a product is not equal to product of the integrals. This should remind us of the Product Rule. Is there a way to use the Product Rule to investigate the antiderivative of a product?

3 Integration by Parts: An Explanation When u and v are differentiable functions of x : The Product Rule tells us… If we integrate both sides… If we simplify the integrals… If we solve for one of the integrals…

4 Integration by Parts Rewrite the function into the product of u and dv. The integral equals… u times the antiderivative of dv. The integral of the product of the antiderivative of dv and the derivative of u.

5 Integration by Parts: The Process

6 Example 1 Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate.

7 Example 2 Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate. You may need to apply Integration by Parts Again. Pick the u and dv. Find du and v. Apply the formula.

8 White Board Challenge

9 Example 3 Since, multiple Integration by Parts are needed, a Tabular Method is a convenient method for organizing repeated Integration by parts. Repeated DifferentiationRepeated Integration + – + – Must get 0. Start with + Alternate Find the sum of the products of each diagonal: Differentiate the u. Integrate the dv. Connect the diagonals. Notice the cubic function will go to zero. So it is a good choice for u.

10 Example 4 Pick the u and dv. Find du and v. This was a bad choice for u and dv. Differentiate.Integrate.

11 Example 4: Second Try Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate. Try the opposite this time.

12 Example 5 If there is only one function, rewrite the integral so there is two. Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate.

13 Example 6 Pick the u and dv. Find du and v. Apply the formula. You may need to apply Integration by Parts Again. Apply the formula. Pick the u and dv. Find du and v. If you see the integral you are trying to find, solve for it.

14 Example 7 If there is only one function, rewrite the integral so there is two. Pick the u and dv. Find du and v. Apply the formula.

15 Integration by Parts: Helpful Acronym When deciding which product to make u, choose the function whose category occurs earlier in the list below. Then take dv to be the rest of the integrand. L I A T E ogarithmic nverse trigonometric lgebraic rigonometric xponential

16 White Board Challenge


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