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**TECHNIQUES OF INTEGRATION**

8 TECHNIQUES OF INTEGRATION

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**As we have seen, integration is more challenging than differentiation.**

TECHNIQUES OF INTEGRATION As we have seen, integration is more challenging than differentiation. In finding the derivative of a function, it is obvious which differentiation formula we should apply. However, it may not be obvious which technique we should use to integrate a given function.

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**Until now, individual techniques have been applied in each section.**

TECHNIQUES OF INTEGRATION Until now, individual techniques have been applied in each section. For instance, we usually used: Substitution in Exercises 5.5 Integration by parts in Exercises 7.1 Partial fractions in Exercises 7.4

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**Strategy for Integration**

TECHNIQUES OF INTEGRATION 7.5 Strategy for Integration In this section, we will learn about: The techniques to evaluate miscellaneous integrals.

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**STRATEGY FOR INTEGRATION**

In this section, we present a collection of miscellaneous integrals in random order. The main challenge is to recognize which technique or formula to use.

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**STRATEGY FOR INTEGRATION**

No hard and fast rules can be given as to which method applies in a given situation. However, we give some advice on strategy that you may find useful.

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**STRATEGY FOR INTEGRATION**

A prerequisite for strategy selection is a knowledge of the basic integration formulas.

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**STRATEGY FOR INTEGRATION**

In the upcoming table, we have collected: The integrals from our previous list Several additional formulas we have learned in this chapter

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**STRATEGY FOR INTEGRATION**

Most should be memorized. It is useful to know them all. However, the ones marked with an asterisk need not be memorized—they are easily derived.

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**TABLE OF INTEGRATION FORMULAS**

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**TABLE OF INTEGRATION FORMULAS**

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**TABLE OF INTEGRATION FORMULAS**

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**TABLE OF INTEGRATION FORMULAS**

Formula 19 can be avoided by using partial fractions. Trigonometric substitutions can be used instead of Formula 20.

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**STRATEGY FOR INTEGRATION**

Once armed with these basic integration formulas, you might try this strategy: Simplify the integrand if possible. Look for an obvious substitution. Classify the integrand according to its form. Try again.

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**1. SIMPLIFY THE INTEGRAND**

Sometimes, the use of algebraic manipulation or trigonometric identities will simplify the integrand and make the method of integration obvious.

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**1. SIMPLIFY THE INTEGRAND**

Here are some examples:

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**2. LOOK FOR OBVIOUS SUBSTITUTION**

Try to find some function u = g(x) in the integrand whose differential du = g’(x) dx also occurs, apart from a constant factor. For instance, in the integral , notice that, if u = x2 – 1, then du = 2x dx. So, we use the substitution u = x2 – 1 instead of the method of partial fractions.

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3. CLASSIFY THE FORM If Steps 1 and 2 have not led to the solution, we take a look at the form of the integrand f(x).

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**3 a. TRIGONOMETRIC FUNCTIONS**

We use the substitutions recommended in Section 7.2 if f(x) is a product of: sin x and cos x tan x and sec x cot x and csc x

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3 b. RATIONAL FUNCTIONS If f is a rational function, we use the procedure of Section 7.4 involving partial fractions.

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3 c. INTEGRATION BY PARTS If f(x) is a product of a power of x (or a polynomial) and a transcendental function (a trigonometric, exponential, or logarithmic function), we try integration by parts. We choose u and dv as per the advice in Section 7.1 If you look at the functions in Exercises 7.1, you will see most of them are the type just described.

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3 d. RADICALS Particular kinds of substitutions are recommended when certain radicals appear. If occurs, we use a trigonometric substitution according to the table in section 7.3 If occurs, we use the rationalizing substitution More generally, this sometimes works for

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4. TRY AGAIN If the first three steps have not produced the answer, remember there are basically only two methods of integration: Substitution Parts

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4 a. TRY SUBSTITUTION Even if no substitution is obvious (Step 2), some inspiration or ingenuity (or even desperation) may suggest an appropriate substitution.

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4 b. TRY PARTS Though integration by parts is used most of the time on products of the form described in Step 3 c, it is sometimes effective on single functions. Looking at Section 7.1, we see that it works on tan-1x, sin-1x, and ln x, and these are all inverse functions.

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**4 c. MANIPULATE THE INTEGRAND**

Algebraic manipulations (rationalizing the denominator, using trigonometric identities) may be useful in transforming the integral into an easier form. These manipulations may be more substantial than in Step 1 and may involve some ingenuity.

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**4 c. MANIPULATE THE INTEGRAND**

Here is an example:

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**4 d. RELATE TO PREVIOUS PROBLEMS**

When you have built up some experience in integration, you may be able to use a method on a given integral that is similar to a method you have already used on a previous integral. You may even be able to express the given integral in terms of a previous one.

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**4 d. RELATE TO PREVIOUS PROBLEMS**

For instance, ∫ tan2x sec x dx is a challenging integral. If we make use of the identity tan2x = sec2x – 1, we can write: Then, if ∫ sec3x dx has previously been evaluated, that calculation can be used in the present problem.

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**Sometimes, two or three methods are required to evaluate an integral.**

4 e. USE SEVERAL METHODS Sometimes, two or three methods are required to evaluate an integral. The evaluation could involve several successive substitutions of different types. It might even combine integration by parts with one or more substitutions.

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**STRATEGY FOR INTEGRATION**

In the following examples, we indicate a method of attack, but do not fully work out the integral.

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SIMPLIFY INTEGRAND Example 1 In Step 1, we rewrite the integral: It is now of the form ∫tanmx secnx dx with m odd. So, we can use the advice in Section 7.2

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**Suppose, in Step 1, we had written:**

TRY SUBSTITUTION Example 1 Suppose, in Step 1, we had written: Then, we could have continued as follows.

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TRY SUBSTITUTION Example 1 Substitute u = cos x:

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TRY SUBSTITUTION Example 2 According to (ii) in Step 3 d, we substitute u = √x. Then, x = u2, so dx = 2u du and The integrand is now a product of u and the transcendental function eu. So, it can be integrated by parts.

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RATIONAL FUNCTIONS Example 3 No algebraic simplification or substitution is obvious. So, Steps 1 and 2 don’t apply here. The integrand is a rational function. So, we apply the procedure of Section 7.4, remembering that the first step is to divide.

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**Here, Step 2 is all that is needed. **

TRY SUBSTITUTION Example 4 Here, Step 2 is all that is needed. We substitute u = ln x, because its differential is du = dx/x, which occurs in the integral.

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MANIPULATE INTEGRAND Example 5 Although the rationalizing substitution works here [(ii) in Step 3 d], it leads to a very complicated rational function. An easier method is to do some algebraic manipulation (either as Step 1 or as Step 4 c).

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**Multiplying numerator and denominator by , we have:**

MANIPULATE INTEGRAND Example 5 Multiplying numerator and denominator by , we have:

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**CAN WE INTEGRATE ALL CONTINUOUS FUNCTIONS?**

The question arises: Will our strategy for integration enable us to find the integral of every continuous function? For example, can we use it to evaluate ∫ ex2dx?

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**CAN WE INTEGRATE ALL CONTINUOUS FUNCTIONS?**

The answer is ‘No.’ At least, we cannot do it in terms of the functions we are familiar with.

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ELEMENTARY FUNCTIONS The functions we have been dealing with in this book are called elementary functions. For instance, the function is an elementary function.

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**If f is an elementary function, then f’ is an elementary function.**

ELEMENTARY FUNCTIONS If f is an elementary function, then f’ is an elementary function. However, ∫ f(x) dx need not be an elementary function.

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**Consider f(x) = ex2. ELEMENTARY FUNCTIONS**

Since f is continuous, its integral exists. If we define the function F by then we know from Part 1 of the Fundamental Theorem of Calculus (FTC1) that Thus, f(x) = ex2 has an antiderivative F.

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**However, it has been proved that F is not an elementary function.**

ELEMENTARY FUNCTIONS However, it has been proved that F is not an elementary function. This means that, however hard we try, we will never succeed in evaluating ∫ ex2dx in terms of the functions we know. In Chapter 11, however, we will see how to express ∫ ex2dx as an infinite series.

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**The same can be said of the following integrals:**

ELEMENTARY FUNCTIONS The same can be said of the following integrals:

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ELEMENTARY FUNCTIONS In fact, the majority of elementary functions don’t have elementary antiderivatives. You may be assured, though, that the integrals in the exercises are all elementary functions.

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