1. Quadratic Relations and Functions
Chapter 13
Quadratic Relations and Functions
Corresponding Notes
Date Assigned
Assignment #
Day 1 & 2
Solving Quadratic Equations
Friday
3/9
Page 507: 3 – 12 (all) 15 – 42 every 3rd ( 1st column) 1
Day 3 Notes
Word Problems Consecutive ntegers
Monday
3/12
Worksheet: HW Day 3 Consecutive Integer 2
Day 4 Notes
Geometric Word Problems
Tuesday
3/13
Worksheet: HW Day 4 Geometric word problems 3
Day 5 Notes
More Word Problems
Wednesday 3/14
Worksheet: HW Day 5 More Geometric word problem 4
Day 6 Notes
Graphing Quadratics
Thursday
3/15
Worksheet: Parabolas 5

2. Consecutive Integer HW
7 or –3
5 or –3
and or
– 8 and -7
and 7
and or
–10 and –8
2(x – 4)(x + 3)
10.

3. Warm - up: Simplify

4. The ratio of the measures of the base and the altitude of a parallelogram is 3:4. The area of the parallelogram is 1,200 square centimeters. Find the measure of the base and altitude of the parallelogram.
A = bh
1200 = (3x)(4x)
1200 =12x2 4x
x2 = 100 3x
x2 – 100 = 0
Let 3x = base
4x = height
30 cm
40 cm
(x + 10) (x – 10) = 0
(x + 10) = 0 (x – 10) = 0
x = -10
x = 10

5. 2. The altitude of a triangle is 5 less than its base
The altitude of a triangle is 5 less than its base. The area of the triangle is 42 square inches. Find its base and altitude.
A = ½ bh
42 = ½ x (x – 5 )
x - 5
2(42 = ½ x (x – 5 ))
84 = x (x – 5 ) x
84 = x2 - 5x
0 = x2 – 5x – 84
12 in
7 in
Let x = base
x – 5 = altitude
0 =(x – 12)(x +7)
(x - 12) = 0 (x + 7) = 0
x = 12
x = -7

6. 3. The length of a rectangle exceeds its width by 4 inches
3. The length of a rectangle exceeds its width by 4 inches. Find the dimensions of the rectangle it its area is 96 square inches.
A =wl
96 =x(x+4) x
96 =x2 + 4x
X + 4
0 = x2 + 4x - 96
8 in
12 in
Let x = width
x + 4 = length
0 =(x – 8)(x +12)
(x - 8) = (x + 12) = 0
x = 8
x = -12

7. 4. If the measure of one side of a square is increased by 2 centimeters and the measure of the adjacent side is decreased by 2 centimeters, the area of the resulting rectangle is 32 square centimeters. Find the measure of one side of the square.
Let x = side
A =lw
6 cm
32 =(x + 2)(x - 2)
32 =x2 + 2x - 2x - 4
32 =x2 - 4
x - 2
0 =x2 – 36
0 =(x – 6)(x + 6)
x + 2
(x - 6) = (x + 6) = 0
x = 6
x = -6

8. 5. Joe’s rectangular garden is 6 meters long and 4 meters wide
5. Joe’s rectangular garden is 6 meters long and 4 meters wide. He wishes to double the area of his garden by increasing its length and width by the same amount. Find the number of meters by which each dimension must be increased.
A =lw
6 m
48 =(x + 6)(x + 4)
A =6(4) 24
4 m
48 = x2 + 6x + 4x + 24
48 = x2 + 10x + 24
0 = x2 + 10x - 24
x + 6
0 =(x – 2)(x + 12)
L= 8 m
W= 6 m
(x - 2) = (x + 12) = 0
x + 4
x = 2
x = -12

9. March 26, 2009
Pick up 1
Homework: Worksheet # 4
Geometric Problems