Download presentation

Published byHector Goodman Modified over 7 years ago

1
Green text p.138 #s 21. The length of the second side of a triangle is 2 inches less than the length of the first side. The length of the third side is 12 inches more than the length of the first side. The perimeter of the triangle is 73 inches. Find the length of each side of the triangle. 20. Find the length of a rectangle whose perimeter is 34.6 centimeters and whose width is 5.7 centimeters. P = 34.6 5.7 Ans: x = 21 in x – 2 = 19 in x + 12 = 33 in x x + 12 3rd side 1st side x P = 2l + 2w 34.6 = 2x + 2(5.7) 10[34.6 = 2x ] 346 = 20x + 114 232 = 20x x = 11.6 Length = 11.6 cm P = 73 2nd side x – 2 P = add up all sides 73 = x + x – 2 + x + 12 73 = 3x + 10 63 = 3x 21 = x

2
**22. Two sides of a triangle are equal in length**

22. Two sides of a triangle are equal in length. The length of the third side exceeds the length of one of the other sides by 3 centimeters. The perimeter of the triangle is 93 centimeters. Find the length of each side of the triangle. 23. The length of a rectangle is 5 meters more than its width. The perimeter is 66 meters. Find the dimensions of the rectangle. Width = 14 m Length = 19 m P = 66 x Ans: x = 30 cm x + 3 = 33 cm x + 5 x x P = 2l + 2w 66 = 2(x + 5) + 2(x) 66 = 2x x 66 = 4x + 10 56 = 4x x = 14 x + 5 14 + 5 19 P = 93 x + 3 P = add up all sides 93 = x + x + x + 3 93 = 3x + 3 90 = 3x 30 = x

3
**24. The width of a rectangle is 3 yards less than its length**

24. The width of a rectangle is 3 yards less than its length. The perimeter is 130 yards. Find the length and the width of the rectangle. 25. The length of each side of an equilateral triangle is 5 centimeters more than the length of each side of a square. The perimeters of the two figures are equal. Find the lengths of the sides of the square and of the triangle. Width = 31 yd Length = 34 yd P = 130 x – 3 x + 5 x x + 5 x P = 93 P = 2l + 2w 130 = 2(x) + 2(x – 3) 130 = 2x + 2x – 6 130 = 4x – 6 136 = 4x x = 34 x – 3 34 – 3 31 x x + 5 Ptri = Psq 3(sides) = 4(sides) 3(x + 5) = 4(x) 3x + 15 = 4x -3x x 15 = x Ans: x = 15 cm x + 5 = 20 cm

4
26. The length of each side of a square is 1 centimeter more than the width of a rectangle. The length of the rectangle is 1 centimeter less than twice its width. The perimeters of the two figures are equal. Find the dimensions of the rectangle. Ans: width = 3 cm length = 5 cm x + 1 x 2x – 1 x + 1 Psq = Prect 4(sides) = 2l + 2w 4(x + 1) = 2(2x – 1) + 2x 4x + 4 = 4x – 2 + 2x 4x + 4 = 6x – 2 -4x x 4 = 2x – 2 6 = 2x x = 3 2x – 1 2(3) – 1 6 – 1 5

Similar presentations

© 2023 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google