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Chapter 4 Radicals.

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Presentation on theme: "Chapter 4 Radicals."— Presentation transcript:

1 Chapter 4 Radicals

2 4.1 – Mixed and Entire Radicals
Chapter 4: Radicals

3 Review: Squares and Square Roots
Remember: Squares and Square Roots are opposite operations. The principal square root is the positive square root of a number. The secondary square root is the negative square root of a number. Unless specified, typically a square root symbol is only looking for the principal square root.

4 Example: Simplifying a)
When you’re simplifying radicals, the first step is to factor the number into its prime factors. c) b)

5 Example: Expanding a) b) c)
When turning a mixed radical into an entire radical, you must first pull the outside coefficient in underneath the radical sign. Remember, roots and exponents are opposite operations!

6 pg , #1, 2, 3, 5, 6, 7, 11, 12, 13, 16, 18, 20 Independent practice

7 4.2 – Adding and Subtracting Radicals
Chapter 4: Radicals

8 Example Check on your calculator! What is the answer different?
Karen’s uncle needs 9 metres of fascia. Determine the length of fascia needed.

9 Example Determine the difference in length between each pair of sides.
PS and SR b) RQ and PQ a) Let D represent the difference between PS and SR The difference between PS and SR is cm. Why is our answer positive? b) Let E represent the difference between RQ and PQ The difference between RQ and PQ is cm.

10 Example a) b)

11 Your turn… Create a negative mixed radical using one addition sign, one subtraction sign, and the radicals , and Challenge the person sitting next to you to simplify it!

12 The Rules You can take a number out from under a root sign by square-rooting (or cube-rooting, if it’s a cubed root) the number. Ex: You can bring a number inside the a root sign by squaring (or cubing, if it’s a cubed root) the number. You can add or subtract like radicals. You cannot add or subtract unlike radicals.

13 pg , #1, 2, 3, 5, 6, 8, 9, 11, 13, 15, 16, 18, 19 Independent practice

14 4.3 – Multiplying and Dividing Radicals
Chapter 4: Radicals

15 Rules for multiplication and division
The product of two square roots is equal to the square root of the product. i.e. The quotient of two square roots is equal to the square root of the quotient.

16 Prove: Now, try to prove the division rule on your own:
What is a square root? Is there a way to represent a square root with exponents? Now, try to prove the division rule on your own: Recall that exponent laws dictate that ax  bx=(ab)x

17 Example Simplify:

18 Try this! Express the following expression in its simplest form:

19 Method 2 is called rationalizing the denominator, which is done by multiplying both the numerator and the denominator by the radical in the denominator. Example Simplify: Method 2: (Rationalizing the denominator) Method 1:

20 Example continued… Simplify: Which method seemed easiest to you?
Method 3: (Finding a common factor) Which method seemed easiest to you? What might be some advantages to each method? What might be some disadvantages? Will all the methods work all of the time?

21 pg , #1-5, 8-16, 19-21 Independent practice

22 Handout Today we will be working on an project about Pythagorean fractal trees. Make sure to answer all the questions to your fullest ability, as this is a summative assessment. You may need a ruler for parts of the assignment.

23 4.4 – Simplifying Algebraic Expressions Involving Radicals
Chapter 4: Radicals

24 If an algebraic expression involves a radical like , can x be any real number?
We sometimes have to apply restrictions to variables. Restrictions are the values of the variable in an expression that ensure the expression in defined. Ex. For 1/x, x cannot be equal to zero, or symbolically we can write x ≠ 0. What about:

25 Example: Identify the restrictions
Remember you can’t take the square root of a negative number is defined when where is defined when where Square roots and squares are opposites, so they cancel to leave the absolute value of x. b) is defined when Simplify the expression, and remember that you can’t take the square root of a negative.

26 Can we make any general rules about the restrictions on radicals in algebraic expressions? Consider

27 Example a) b) is defined when where is defined when
You must always identify your restrictions when simplifying algebraic expressions involving radicals.

28 Example Simplify: is defined when y ≥ 0, where y R.

29 Example Simplify: is defined when x ≥ 0, where x R.
Remember, while multiplying radical expressions, you multiply the coefficients by the coefficients, and combine the radicals.

30 Example Simplify: is defined for x > 0, where x R.

31 What about an expression like ? What are the restrictions?
Just remember that the number underneath the radical needs to stay positive.

32 pg , #1, 3, 6, 8, 9, 10, 11, 13, 14, 15, 17 Independent practice

33 4.5 – Exploring Radical Equations
Chapter 4: Radicals

34 Solving Radical Equations
What is the opposite of a square root? Ex. To get rid of a cube root, you need to cube both sides. Make sure that you simplify the equations as much as possible before solving. Remember your orders of operations.

35 Try it! Solve for x:

36 pg. 215, #1-5 Independent practice

37 4.6 – Solving Radical Equations
Chapter 4: Radicals

38 Solving Radical Equations
If the solution does not work when substituted back into the equation, then it is an extraneous root, and the equation does not have a solution. Ex is defined for x ≥ -2, where x R. because You always must check your solution when solving radical equations. Since 3 ≠ -3, this is an extraneous root. Check by substitution:

39 Example The length of the chain is 1.55 metres, or 155 cm.
The forward and backward motion of a swing can be modeled using the formula where T represents the time in seconds for a swing to return to its original position, and L represents the length of the chain supporting the swing, in metres. When Cara was swinging, it took 2.5 s for the swing to return to its original position. Determine the length of the chain supporting her swing to the nearest centimetre. Solution: The length of the chain is 1.55 metres, or 155 cm. Substitute:

40 Alternate Solution Another way of solving these types of problems is to first substitute in your values, and then manipulate the equation. Solution #2: The solution is the same! Which method do you prefer? What are some of the advantages and disadvantages of each? What if you had to solve multiple problems using the same equation?

41 pg , #1-15 Independent practice


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