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Solving Equations Involving Square Roots. Finding the Square Root of a Fraction.

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Presentation on theme: "Solving Equations Involving Square Roots. Finding the Square Root of a Fraction."— Presentation transcript:

1 Solving Equations Involving Square Roots

2 Finding the Square Root of a Fraction

3 Checking for Understanding

4

5

6 We could make estimates if the square roots are not perfect, but typically we simplify the square root instead by pulling out perfect squares so that we are keeping exact values. That is a topic for another day.

7 Discussion

8 Solving Equations Involving Square Roots Remember that when solving algebra problems, we must preserve the balance in the equation. We do this by performing inverse (opposite) operations to both sides of the equation. x + 3 = 125x – 4 = 21

9 Equations with Roots

10

11 Think Pair Share YES! (-4) could also be a solution to this equation because (-4) x (-4) = 16

12 Checking for Understanding Solve for x x² = 4

13 Checking for Understanding Solve for x 49 = x²

14 Checking for Understanding Solve for x x² = 196

15 Estimating Non – Perfect Solutions

16 You can use the same process for yesterday to make your estimation x² = 27

17 Solving Equations Involving Cube Roots

18 Negative Solutions

19 Lets Do a Few

20 Think Pair Share When taking the cube root of a negative number, what must be true about the solution?

21 Finding the Cube Root of a Fraction

22 Checking for Understanding

23

24

25 We could make estimates if the cube roots are not perfect, but typically we simplify the cube root instead by pulling out perfect cubes so that we are keeping exact values. That is a topic for another day.

26 Discussion

27 Equations with Roots

28

29 Think Pair Share NO! -6 cubed will produce a negative solution

30 Cube roots have only one possible solution, whereas square roots can have 2.

31 Checking for Understanding Solve for x x³ = 8

32 Checking for Understanding Solve for x 512 = x³

33 Checking for Understanding Solve for x x³ = -1000

34 Estimating Non – Perfect Solutions

35 You can use the same process for yesterday to make your estimation x³ = 100


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