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Lecture 371 Norton Equivalent Circuits. Lecture 372 Introduction Any Thevenin equivalent circuit is in turn equivalent to a current source in parallel.

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Presentation on theme: "Lecture 371 Norton Equivalent Circuits. Lecture 372 Introduction Any Thevenin equivalent circuit is in turn equivalent to a current source in parallel."— Presentation transcript:

1 Lecture 371 Norton Equivalent Circuits

2 Lecture 372 Introduction Any Thevenin equivalent circuit is in turn equivalent to a current source in parallel with a resistor. A current source in parallel with a resistor is called a Norton equivalent circuit. Finding a Norton equivalent circuit requires essentially the same process as finding a Thevenin equivalent circuit.

3 Lecture 373 Independent Sources Circuit with one or more independent sources R Th Norton equivalent circuit I sc

4 Lecture 374 No Independent Sources Circuit without independent sources R Th Norton equivalent circuit

5 Lecture 375 Finding the Norton Equivalent Circuits with independent sources: –Find V oc and I sc –Compute R Th Circuits w/o independent sources: –Apply a test voltage (current) source –Find resulting current (voltage) –Compute R Th

6 Lecture 376 Example: Strain Gauge Strain is the amount of deformation of a body due to an applied force-it is defined as the fractional change in length. Strain can be positive (tensile) or negative (compressive). One type of strain gauge is made of a foil grid on a thin backing.

7 Lecture 377 A Strain Gauge The strain gauge’s resistance varies as a function of the strain:  R = GF  R  is the strain, R is the nominal resistance, GF is the Gauge Factor Backing Foil

8 Lecture 378 Typical values Measured strain values are typically fairly small-usually less than 10 -3. GF is usually close to 2. Typical values for R are 120 , 350 , and 1000 . A typical change in resistance is  R = 2 10 -3 120  = 0.24 

9 Lecture 379 Measuring Small Changes in R To measure such small changes in resistance, the strain gauge is placed in a Wheatstone bridge circuit. The bridge circuit uses an exitation source voltage source and produces a voltage that depends on  R.

10 Lecture 3710 The Bridge Circuit R+  R V ex + - R R R + - V out

11 Lecture 3711 Find the Norton Equivalent 10V + - 120  + - 120.24  120 

12 Lecture 3712 Find V oc 10V + - 120  + - 120.24  120  V oc

13 Lecture 3713 10V + - 120  + - 120.24  120  V oc V1V1 V2V2

14 Lecture 3714 Compute V oc

15 Lecture 3715 Find I sc 10V + - 120  120.24  120  I sc

16 Lecture 3716 10V + - 120  120.24  120  I sc VxVx

17 Lecture 3717 Compute R Th

18 Lecture 3718 The Norton Equivalent 41.6  A 120.18 

19 Lecture 3719 Norton Equivalent for Any 

20 Lecture 3720


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