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Lecture 19: Periodic Trends Reading: Zumdahl 12.14-12.16 Outline –Periodic Trends Ionization Energy, Electron Affinity, and Radii –A Case Example.

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Presentation on theme: "Lecture 19: Periodic Trends Reading: Zumdahl 12.14-12.16 Outline –Periodic Trends Ionization Energy, Electron Affinity, and Radii –A Case Example."— Presentation transcript:

1 Lecture 19: Periodic Trends Reading: Zumdahl 12.14-12.16 Outline –Periodic Trends Ionization Energy, Electron Affinity, and Radii –A Case Example

2 The Aufbau Principal (cont.) Lithium (Z = 3) 1s2s2p 1s2s2p Berillium (Z = 4) Boron (Z = 5) 1s2s2p 1s 2 2s 1 1s 2 2s 2 1s 2 2s 2 2p 1

3 The Aufbau Principal (cont.) Carbon (Z = 6) 1s2s2p 1s2s2p Nitrogen (Z = 7) Hund’s Rule: Lowest energy configuration is the one in which the maximum number of unpaired electrons are distributed amongst a set of degenerate orbitals. 1s 2 2s 2 2p 2 1s 2 2s 2 2p 3

4 The Aufbau Principal (cont.) Oxygen (Z = 8) 1s2s2p 1s2s2p Fluorine (Z = 9) 1s 2 2s 2 2p 4 1s 2 2s 2 2p 5 1s2s2p Neon (Z = 10) 1s 2 2s 2 2p 6 full

5 The Aufbau Principal (cont.) This orbital filling scheme gives rise to the modern periodic table.

6 The Aufbau Principal (cont.) After Lanthanum ([Xe]6s 2 5d 1 ), we start filling 4f.

7 The Aufbau Principal (cont.) After Actinium ([Rn]7s 2 6d 1 ), we start filling 5f.

8 The Aufbau Principal (cont.) Heading on column given total number of valence electrons.

9 Periodic Trends The valence electron structure of atoms can be used to explain various properties of atoms. In general, properties correlate down a group of elements. A warning: such discussions are by nature very generalized…exceptions do occur.

10 Periodic Trends: Ionization If we put in enough energy, we can remove an electron from an atom. The electron is completely “removed” from the atom (potential energy = 0).

11 Periodic Trends: Ionization Generally done using photons, with energy measured in eV (1 eV = 1.6 x 10 -19 J). The greater the propensity for an atom to “hold on” to its electrons, the higher the ionization potential will be. Koopmans’ Theorem: The ionization energy of an electron is equal to the energy of the orbital from where the electron came.

12 Periodic Trends: Ionization One can perform multiple ionizations: Al(g)Al + (g) + e - I 1 = 580 kJ/mol first Al + (g)Al 2+ (g) + e - I 2 = 1815 kJ/mol second Al 2+ (g)Al 3+ (g) + e - I 3 = 2740 kJ/mol third Al 3+ (g)Al 4+ (g) + e - I 4 = 11,600 kJ/mol fourth

13 Periodic Trends: Ionization First Ionization Potentials: Column 1 Column 8

14 Periodic Trends: Ionization First Ionization Potentials: Increases as one goes from left to right. Decrease as one goes down a group. Reason: increased Z + Reason: increased distance from nucleus

15 Periodic Trends: Ionization Removal of valence versus core electrons Na(g)Na + (g) + e - I 1 = 495 kJ/mol Na + (g)Na 2+ (g) + e - I 2 = 4560 kJ/mol [Ne]3s 1 [Ne] 1s 2 2s 2 2p 5 (removing “valence” electron) (removing “core” electron) Takes significantly more energy to remove a core electron….tendency for core configurations to be energetically stable.

16 Periodic Trends: Electron Affinity Electron Affinity: the energy change associated with the addition of an electron to a gaseous atom.

17 Periodic Trends: Electron Affinity We will stick with our thermodynamic definition, with energy released being a negative quantity. Wow!

18 Periodic Trends: Electron Affinity Elements that have high electron affinity: Group 7 (the halogens) and Group 6 (O and S specifically).

19 Periodic Trends: Electron Affinity Some elements will not form ions: Orbital configurations can explain both observations. N?

20 Periodic Trends: Electron Affinity Why is EA so great for the halogens? F(g) + e - F - (g)EA = -327.8 kJ/mol 1s 2 2s 2 2p 5 1s 2 2s 2 2p 6 [Ne] Why is EA so poor for nitrogen? N(g) + e - N - (g)EA > 0 (unstable) 1s 2 2s 2 2p 3 1s 2 2s 2 2p 4 (e - must go into occupied orbital)

21 Periodic Trends: Electron Affinity How do these arguments do for O? O(g) + e - O - (g)EA = -140 kJ/mol 1s 2 2s 2 2p 4 1s 2 2s 2 2p 5 What about the second EA for O? O - (g) + e - O 2- (g)EA > 0 (unstable) 1s 2 2s 2 2p 5 1s 2 2s 2 2p 6 [Ne] configuration, but electron repulsion is just too great. Bigger Z + overcomes e - repulsion.

22 Atomic Radii Atomic Radii are defined as the covalent radii, and are obtained by taking 1/2 the distance of a bond: r = atomic radius

23 Atomic Radii Decrease to right due due increase in Z + Increase down column due to population of orbitals of greater n.

24 Looking Ahead We can partition the periodic table into general types of elements. Metals: tend to give up e - non-Metals: tend to gain e - Metalloids: can do either


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