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CS 140L Lecture 1 Professor CK Cheng 3/31/02. CMOS Logic (3.2 – 3.6) Complementary Metal-Oxide Semiconductor.

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Presentation on theme: "CS 140L Lecture 1 Professor CK Cheng 3/31/02. CMOS Logic (3.2 – 3.6) Complementary Metal-Oxide Semiconductor."— Presentation transcript:

1 CS 140L Lecture 1 Professor CK Cheng 3/31/02

2 CMOS Logic (3.2 – 3.6) Complementary Metal-Oxide Semiconductor

3 1. Transistors (FET) Field Effect Transistor G S D NMOS D WG S D L G =1 => D =S { D = 1 => S = 0.8 D = 0 => S = 0 G = 0 => D&S are separated.

4 G C D S r L W, c WxL A C ’ C B G S D PMOS G = 0 => D =S { D = 1 => S = 1 D = 0 => S = 0.2 G = 1 => D&S are separated.

5 2. Transmission Gate A C C BC = 0 => A&B are separated. C = 1 => A = B

6 3. Inverter AB A = 1 => B = 0 A = 0 => B = 1 Thus B = A

7 4. NAND gate B A A B A B Z 0 0 1 0 1 1 1 0 1 1 1 0 Z = D iff AB = 1. Z = (AB)’ Z

8 5. NOR gate B A A B A B Z 0 0 1 0 1 0 1 0 0 1 1 0 Z = 1 iff A+B = 0. Z = (AB)’ = (A+B)’ Z

9 6. XOR gate B A Z B’ A’ B A B’ A’ Z = ab’ + a’b = a + b

10 7. Multiplexer d1 d2 S S S ‘ Z If S=1, Z = d1 Else (S=0), Z = d0 Z = S d1 + S’ d0

11 Basic Boolean Algebra a + a = 1 a * a = 0 1 + a = 1 1*a = 1 a + a = a a * a = a a a

12 DeMorgan’s Law (a + b)’ = a’ * b’ (a*b)’ = a’ + b’ ab


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