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Chapter 14 Fluids
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Fluids at Rest (Fluid = liquid or gas)
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Density ( ) unit: kg/m 3 we will consider only = m/V = constant (incompressible fluid) we will also assume g = constant
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Pressure (p) A fluid exerts a force dF normal to any area dA you consider in it. For a fluid at rest, the force is equal and opposite on each side.
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Pressure (p) Why is there a force? Microscopically: the fluid particles are in motion and collide with dA Macroscopically: the fluid is at rest
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Pressure (p) pressure p is a scalar (no intrinsic direction) reason: it acts normal to any surface dA
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Pressure (p) units used: pascal, millibar, atm 1 Pa = 1 N/m 2 1 millibar = 100 Pa 1 atm = 1.013×10 5 Pa
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Terminology ‘gauge pressure’ = p – p atm (can be > 0 or < 0) (e.g., read on a car tire pressure gauge) p = absolute pressure (> 0) = atmospheric pressure + gauge pressure = p atm + gauge pressure
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Pressure and depth pressure: p coordinate: y pressure decreases with ‘elevation’ y: Derive this result and integrate it
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Pressure and depth coordinate: y distance: h > 0 p increases with depth for any shape of vessel Demonstration: depth and shape of container
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Exercise 14-10 The dangers of a long snorkel tube: Find the gauge pressure at the depth shown. Will this cause the snorkeler’s lungs to collapse? Demonstration: atmospheric pressure
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Pascal’s Law If any change in pressure p is applied at one point, it is transmitted to all points in the fluid and to walls enclosing it.
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Example: Hydraulic Lift At equilibrium, p = F 1 /A 1 = F 2 /A 2 Demonstration
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Two Pressure Gauges Notes on (a) and Exercise 14-9 Notes on (b) first
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Homework Hints: Exercise 14-55
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Buoyancy and Buoyant Force
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A (fully or partially) submerged object feels an upward force equal to the weight of fluid it displaces
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(a) fluid element with weight w fluid (b) body of same shape feels buoyant force B = w fluid Demonstration
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Surface Tension Molecules of liquid attract each other (else no definite volume) center: net force = 0 surface: net force is directed inward
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Surface Tension So the surface acts like a membrane under tension (like a stretched drumhead) The surface resists any change in surface area Strength characterized by ‘surface tension’ Demonstration
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Surface Tension = F/d = cohesive force per unit length surface tension force F = d We can measure by just balancing F Do Example 14-23 Notes on measuring
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cohesion: attraction of like molecules example: liquid-liquid forces (surface tension)
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adhesion: attraction between unlike molecules example: liquid-glass forces
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(a) adhesion > cohesion: water wets glass (b) adhesion < cohesion: mercury beads up
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Capillarity For these two cases, the surface tension force F pushes the column of liquid either up or down: (a) up for water (b) down for mercury Notes on capillary tubes
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Homework Announcements Homework Set 5: Correction to hints for 14-55 (handout at front and on webpage) Recent changes to classweb access (see HW 5 sheet at front and webpage) Homework Sets 1, 2, 3: returned at front (scores to be entered on classweb soon)
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Midterm Announcements Friday: review required topics practice problems (from class, HW, new?) Monday: (midterm) you can bring a sheet of notes (both sides) you will be given a list of equations
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Fluid Flow (Fluid Dynamics)
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Flow Fluid Flow line = path of fluid element Flow tube = bundle of flow lines passing through area A (just a useful construct)
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Simplifying Assumptions Steady flow: At any given point in the fluid, its properties (v, , p) don’t change in time
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Simplifying Assumptions Steady flow: different flow lines never cross each other fluid entering a flow tube never leaves it
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Simplifying Assumptions Incompressible fluid: = constant No friciton: no ‘viscosity’
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Continuity Equation A 1 v 1 = A 2 v 2 the same volume dV of fluid enters and exits tube: dV = volume passing through A in dt = Av dt Notes
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Continuity Equation A 1 v 1 = A 2 v 2 along the flow: A = area of flow tube v = speed of fluid if one increases, the other must decrease Notes and Demonstration: water flow
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Continuity Equation A 1 v 1 = A 2 v 2 Where the flow lines are crowding together, the fluid speed is increasing
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Bernoulli’s Equation only valid for: steady flow, incompressible fluid, no viscosity! Notes
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Bernoulli’s Equation if v 1 = v 2 = 0: reduces to previous result for fluid at rest
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Bernoulli’s Equation if y 1 = y 2 then for p and v: if one increases, the other must decrease Demonstration
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Applications of Bernoulli’s Equation
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Venturi Meter (Example 14-10) horizontal flow tube Notes
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Note: if viscosity is present, then v decreases with distance from tube center
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Venturi Meter: Homework Problem 14-90 (c) Notes Demonstration
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Wing Lift
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Can’t predict flow lines but they indicate low pressure above wing, so net force up Demonstration: propellor
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Efflux Speed: vertical flow tube Notes
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Siphon: flow tube points up, then down First: you must fill the tube There is a limit: H + h < 10 m
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Curve Ball: viscosity makes it possible Warm-up demonstrations
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Viscosity drags air with spinning ball: low pressure=net force so the ball curves Demonstration
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Homework Announcements Homework Set 5: Correction to hints for 14-55 (handout at front and on webpage) Recent changes to classweb access (see HW 5 sheet at front and webpage) Homework Sets 1, 2, 3: returned at front (scores to be entered on classweb soon)
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