Presentation is loading. Please wait.

Presentation is loading. Please wait.

Momentum O.Sato. Chant Dt momentum(GBTR) check(‘96+’97) 0muEventcheck#track#match#DtDt/trackDt/match kink 69 63 64 31 19 0.30 0.61 Vee.

Similar presentations


Presentation on theme: "Momentum O.Sato. Chant Dt momentum(GBTR) check(‘96+’97) 0muEventcheck#track#match#DtDt/trackDt/match kink 69 63 64 31 19 0.30 0.61 Vee."— Presentation transcript:

1 Momentum Apr/2003@Ishigaki O.Sato

2 Chant Dt momentum(GBTR) check(‘96+’97) 0muEventcheck#track#match#DtDt/trackDt/match kink 69 63 64 31 19 0.30 0.61 Vee 73 72 143 73 47 0.33 0.64 tri 30 90 34 22 0.24 0.65 4vee 15 60 30 19 0.32 0.63 1muEventcheck#track#match#DtDt/trackDt/match kink 159 155 120 85 0.55 0.71 Vee 339 335 664 400 255 0.39 0.64 tri 164 161 480 256 170 0.35 0.66 4vee 86 85 339 185 126 0.37 0.68  0mu sample  1mu sample

3 Vee daughter sign consistency sample all(+,-)(+,+)(-,-) 0mu 11 7 1 3 1mu 54 38 7 9 0mu+1mu 65 45 8 12 Sample: Vee with both daughters have Dt momentum. Asuming right sign efficiency as ε (+,-) : ε 2 +(1-ε)(1-ε) (+,+) : ε(1-ε ) (-,-) : ε(1-ε ) ε =0. 81 ± 0.05

4 Kink daughter sign sample all + - +/all 0mu 19 12 70.61±0.12 1mu 85 75 100.88±0.04 Sample: Kink with Dt momentum.  Consistent with Vee daughter analysis, for kinks in 1mu sample. But not for 0mu sample. (White kink or.Tau)

5 MCS momentum measurement data set = 7pl Every 7 plate gives momentum <7 GeV/c (Cell length 3pl) Merge the momentum => momentum of the track 2mm X 2mm

6 MCS momentum measurement 0mu kink sample

7

8 Another MCS sample Pilot scan for D* analysis 1ry tracks of Vee events (1ry plate#>7) Sample # of ev # of tracls ALL 402 1062 Mod 160 10(12) 23(29) Mod 860 20(22) 60(74)

9 MCS momentum measurement 1ry track sample for D*

10 MCS momentum measurement Both sample

11 MCS momentum measurement error dP/P=0.3 5 GeV/c

12 Muons momentum measured by MCS Sample # of muon # MCS ok Mod 160/860 18 16 Some 1ry muon was MCS momentum measured. Check the momentum to distinguish from 1ry tracks.

13 Muons momentum (SP,MCS)

14 MCS momentum distribution all track (mu 16ev) muon track

15 Muons momentum Muon is enriched in MCS momentum > 5GeV/c Efficiency = 9/16 = 56 % (> 5GeV/c) Efficiency = 5/16 = 31 % (>10GeV/c) Miss judge as muon will be Miss ratio = 3/16 = 19 % (>5GeV/c) Miss ratio = 1/16 = 6 % (>10GeV/c) (Need to collect statistics )

16 Check with ‘0mu’ events 4 D 0 event in 0mu sample have been MCS scanned. 12 tracks/4events 3 track/2events Momentum measured Above 5GeV/c 15 tracks/4events Are they muon?

17 Check with ‘0mu’ events 3 track/2event information trackRunEvent ay azP MCS (GeV/c) #1 7085 816-0.061-0.008 6.7 #2 8223 4711-0.035-0.017 12.5 #3 8223 4711-0.089 0.108 6.8

18 Check with ‘0mu’ events After display check 1event have a clear Muon. And slope(-0.032,-0.023) is matched #2 track. (Other 3 have no muon )

19 Check with ‘0mu’ events 4 events was tried and 2 event was selected as possible muonic event! 1 ev was true. 1 ev was fake Next:: Measurement of all 1ry track’s MCS momentum for ‘0mu’ kink events.

20 Summary Dt works for about 30% fraction of kink daughters. And Charge determination efficiency about 80%. MCS momentum measurement works bellow 5 GeV/c. Above 5GeV/c is consistent with momentum infinity. These tracks were muon by high probability.


Download ppt "Momentum O.Sato. Chant Dt momentum(GBTR) check(‘96+’97) 0muEventcheck#track#match#DtDt/trackDt/match kink 69 63 64 31 19 0.30 0.61 Vee."

Similar presentations


Ads by Google