1. Problem 7.15 Use the REL chart below and find the Total Closeness Ratings for all departments. Let the values of 81, 27, 9, 3, 1, & -81 be for A, E, I, O, U, and X ratings respectively.

2. Total Closeness Rating Using eqn. 7.9 (pg 217) V(r ij ) is the function for determining an adjacency of importance of r ij. Given V(A) = 81, V(E) = 27, V(I) = 9, V(O) = 3, V(U) = 1, & V(X) = -81 Since V(X) is negative we will ignore all X relationships First calculate the TCR for the Receiving Department. TCR recieving = V(r rec’v,test ) + V(r rec’v,comp. ) + V(r rec’v,sub ) + V(r rec’v,assy. ) + V(r rec’v,ship ) TCR recieving = V(I) + V(I. ) + V(U) + V(U. ) + V(A) = 9+9+1+1+81 TCR recieving = 101 TCR test = V(r test, rec’v ) + V(r test,comp. ) + V(r test,sub ) + V(r test,assy. ) + V(r test,ship ) TCR test = V(I) + V(X. ) + V(I) + V(E) + V(U) = 9+9+27+1 TCR test = 46 TCR components = V(r comp, rec’v ) + V(r comp,test. ) + V(r comp,sub ) + V(r comp,assy. ) + V(r comp,ship ) TCR components = V(I) + V(X. ) + V(I) + V(E) + V(O) = 9+9+27+3 TCR components = 48 TCR subassembly = V(r sub, rec’v ) + V(r sub,test. ) + V(r sub,comp. ) + V(r sub,assy. ) + V(r sub,ship ) TCR subassembly = V(U) + V(I. ) + V(I) + V(A. ) + V(O) = 1+9+9+81+3 TCR subassembly = 103

3. TCR assembly = V(r sub, rec’v ) + V(r sub,test. ) + V(r rec’v,comp. ) + V(r rec’v,sub ) + V(r rec’v,ship ) TCR assembly = V(U) + V(E. ) + V(E) + V(A. ) + V(A) = 1+27+27+81+81 TCR assembly = 217 TCR shipping = V(r ship,rec’v ) + V(r ship,test. ) + V(r ship,comp. ) + V(r ship,sub ) + V(r ship,assy ) TCR shipping = V(A) + V(U. ) + V(O) + V(O. ) + V(A) = 81+1+3+3+81 TCR shipping = 169 Thus the department rating is such (1) Assembly, (2) Shipping, (3) Subassembly, (4) Receiving, (5) Components, & (6) Test Attempting to construct a relationship diagram based on these ratings. Assembly is ranked the highest so it is placed in the center of the layout. Shipping is next. It can be located anywhere around Assembly, all positions increase the adjacency score by V(r ship,assy ). Arbitrarily pick below Assembly. Third is Subassembly. There are now six possible locations. Right, left or top of Assembly, are the best choices based on the increase in adjacency score of V(r sub, assy ). Arbitrarily pick left of Assembly. Sub Assy. Ship. 81 3 3 3 Assy. Ship. Assy. Ship.

4. SubAssy. Ship. 1 1 81 3 82 9 1 Fourth is Receiving. There are now seven possible locations. The best location is between Subassembly and Shipping because of the A relationship. SubAssy. Ship.Rec’v Next choice is Components. There are only two best possible locations, either above or right of Assembly, both with and increase of 27. I arbitrarily choose above Assembly. SubAssy. Ship.Rec’v 9 27 9 3 93 SubAssy. Ship.Rec’v Comp. The final department is Test. For a gain of 27, place Test to the right of Assembly. SubAssy. Ship.Rec’v Comp. 9 9 27 9 1 91 SubAssy. Ship.Rec’v Comp. Test The final department is Test. For a gain of 27, place Test to the right of Assembly. Another pass at trying to create a layout is as follows: SubAssy.Ship. 1 1 81 1 1 1 SubAssy.Ship. 9 36 3 27 9 9 3 9 Rec’v 9 SubAssy.Ship. 9 1 27 9 9 1 9 Rec’v 9 Comp. SubAssy.Ship. Rec’vComp. Test