Presentation is loading. Please wait.

Presentation is loading. Please wait.

Announcements Assignment 1 solutions posted Assignment 2 due Thursday First mid-term Thursday October 27 th (?)

Similar presentations


Presentation on theme: "Announcements Assignment 1 solutions posted Assignment 2 due Thursday First mid-term Thursday October 27 th (?)"— Presentation transcript:

1 Announcements Assignment 1 solutions posted Assignment 2 due Thursday First mid-term Thursday October 27 th (?)

2 Lecture 8 Overview Inductors in transient circuits Semiconductors Diodes Rectifying circuits Other Diode Applications Transistors

3 Time response of Inductors Switch to position a: Integrate and apply boundary condition t=0, i=0 Time constant τ=L/R. Switch to position b: Talk about "Charging a capacitor" "Current build-up" in an inductor

4 Time response of Inductors A battery is connected to an inductor. When the switch is opened does the light bulb: 1.Remain off 2.Go off 3. Slowly Dim out 4. Keep burning as brightly as it did before the switch was opened 5. Flare up brightly, then dim and go out Answer 5

5 Semiconductors Simple review of basic concepts: What is a semiconductor? (for more detail see e.g. Simpson Ch. 4) Elements such as Silicon and Germanium have 4 valence electrons in their outer shell They form covalent bonds with neighbouring atoms to form strong crystal lattice structures. In pure silicon, all valence electrons are bound in the lattice structure

6 Semiconductors The addition of impurities ("doping"), such as Sb(Antimony) with 5 valence electrons, leaves one electron unbound and free to move and create a current flow (n-type semiconductor). Alternatively, an impurity with 3 valence electrons can be used to create positive "holes". When a p-type and an n-type are joined (p-n junction), mobile electrons diffuse from the n-type to the p-type, forming positive and negative ions at fixed positions in a state of equilibrium which inhibit further transfer of electrons (depletion region) depletion region E-field (~0.2V Ge, ~0.5V Si) +-

7 What happens when you apply a voltage? Reverse bias: Apply an electric field in this direction, mobile electrons are driven away from the junction (unlike fixed charged ions). Mobile holes are also driven away in the opposite direction. Depletion region acts like an insulating slab - No current flows Forward bias: Helps electrons overcome the depletion region. Current flows easily For the device to conduct, electrons from the n-type region must cross the junction applied E-field Depletion region E-field

8 Ideal diode A diode is a non-linear circuit element Only passes current in one direction Constructed from a p-n semiconductor junction

9 Real diode Diode law: I S = reverse-leakage current v = voltage across the diode k B = Boltzmann's constant e - = electron charge T = Temperature (K) Strong dependence on T I S is small ~ 10 -6 A (Ge), ~10 -8 (Si)

10 Diode Circuit Diodes are non-linear; how do we calculate the operating conditions? (Can’t easily use V=IR) Consider the simplest diode circuit Must satisfy both equations: Operating point can be calculated by seeing when diode law line intersects load line KVL: When I D =0; V D =V DD When V D =0; I D =V DD /R

11 Rectifying Circuit One of the most important applications of a diode is in rectifying circuits: used to convert an AC signal into the DC voltage required by most electronics Ideal transformer: V S /V P =N S /N P Real transformers are ~98% efficient

12 Half-wave rectifier Only lets through positive voltages. Rejects negative voltages

13 Full-wave rectifier To use both halves of the input sinusoid,can use a centre-tapped transformer: ++ + - - - e.g. Battery Charger

14 or use a Bridge rectifier Does not require centre-tapped transformer Requires 2 diodes in each direction – cheap, but voltage drop is double

15 Bridge rectifier Current flow in the bridge vOvO vOvO + +--

16 Peak rectifier Most devices need steady DC To smooth out the peaks and obtain a DC voltage When source voltage < capacitor voltage Diode is reversed biased Capacitor discharges through resistor

17 Another diode application: Voltage doubler High Voltage transformers are expensive and impractical at voltages above a few thousand Volts. How do we get higher? C 2 charges to V sec C 1 charges to 2 V sec

18 Voltage doubler Can extend this circuit to produce extremely high voltages (~750kV). Voltage Quadrupler Cockroft-Walton voltage multiplier 1932, Cavendish Labs reached 250 kV Accelerated protons onto a Lithium target Split the atom! http://www.youtube.com/watch?v=RdBqMtioh6U


Download ppt "Announcements Assignment 1 solutions posted Assignment 2 due Thursday First mid-term Thursday October 27 th (?)"

Similar presentations


Ads by Google