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Strategic Network Formation With Structural Holes By Jon Kleinberg, Siddharth Suri, Eva Tardos, Tom Wexler.

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Presentation on theme: "Strategic Network Formation With Structural Holes By Jon Kleinberg, Siddharth Suri, Eva Tardos, Tom Wexler."— Presentation transcript:

1 Strategic Network Formation With Structural Holes By Jon Kleinberg, Siddharth Suri, Eva Tardos, Tom Wexler

2 Structural Holes Structural holes theory suggests that node A is in a stronger position than the other nodes, because it can control the flow of information between the three otherwise independent groups of nodes

3 Structural Holes The paper looks at what would happen to a social network graph if all the nodes were incentivized to become 'bridging' nodes

4 The Model The payoff for a node u is a | N(u) | + Σ v,w ∈ N (u) (β(r vw ) ) − Σ v ∈ L(u) (c uv ), where a = the static benefit associated with having a link with another node N(u) = the number of nodes connected to u β = any decreasing function r vw = the number of length 2 paths between v and w, if v and w are not connected, 0 otherwise L(u) = the number of nodes u has bought a link to c uv = the cost associated with the u,v edge

5 Computing a node's best move Can be done in polynomial time Proof in the paper, via a reduction to the largest weight ideal problem, which can be reduced to the minimum cut of a network

6 What kinds of graphs does this create? Does equilibria exist for any number of nodes? Can we always reach equilibria using best response updates?

7 Experiments: The possibility of cycling a =.9 β(r) = 2a/r c xy = 1

8 The Cost Matrix: Uniform We first look at what would happen if the 'cost' of maintaining an edge was constant (in this case, c uv = 1 for every edge), and will try to answer the following questions: Does there always exist some equilibrium, for a graph of n nodes? If so, is it always reachable by round robin best response updates?

9 Does equilibrium exist: Uniform Metric Let G n,k be a multipartite graph of n nodes, where the nodes are split up into n/k roughly equal sized groups, and every node in the ith group buys connections to every node in the jth group, for all j<i

10 Does equilibrium exist: Uniform Metric Can we chose k such that Gn,k is at equilibrium? Yes - we do this by defining a benefit function B(n,k) = k(a-1) + Ck,2 β(n-k), and picking k' such that B(n, k')>0 and B(n, k'-1)<=0

11 Can we always reach equilibrium: Uniform Metric We have shown that for any n, there is always a k, such that G n,k is in equilibrium. Will our algorithm for computing best response dynamics reach an equilibrium?

12 Do other Equilibria exist: Uniform Yes! After running several experiments, all equilibria were found to be dense, Ω(n^2) edges The paper then proves that all equilibria are dense, assuming rβ(r) >0

13 The Cost Matrix: Hierarchical Useful for situations like the dynamics of a large company's social network Here, we let the cost c uv, be the unique simple path between nodes u,v in the tree

14 Does equilibrium exist: Hierarchical Metric This is still an open question, for arbitrarily large n However, running experiments suggest that when equilibrium does exist, it occurs with a small group of people with links to everyone, a few people with a significant number of links, and most with very few links Average degree being O(√n)

15 Conclusions In both hierarchical and uniform metrics, we end up with a network divided into social classes, where a small number of nodes maintain O(n) links, and most nodes have much less Even starting from an empty graph, the bridging incentive causes a break in the symmetry, but what happens under different bridging conditions?

16 Other Research Sanjeev Goyal and Fernando Vega-Redondo's 'Structural holes in social networks' uses a model where a node u receives benefits from residing on arbitrarily long paths between two other nodes, w and v. Here, star networks turn out to be the most robust equilibrium, for a wide range of parameters Vincent Buskens and Arnout van de Rijt's 'Dynamics of networks if everyone strives for structural holes' looks at only benefits from length 2 paths, but uses a stricter form of equilibrium, which they call unilateral stability

17 Questions?


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