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Lecture 11: Polymorphism and Dynamic Binding Polymorphism Static (compile-time) binding Dynamic (run-time) binding
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Polymorphism A fundamental feature of OOP Greek for many shapes Idea: one abstract operation is implemented differently for different classes Example: toString method x.toString() calls different implementations of the toString method depending on whether x is an object reference of class Object, String, Date, Time, etc aside: toString is called by System.out.println(x) when x is an object reference in other words, System.out.println(x) has the same effect as System.out.println(x.toString())
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The Words Static and Dynamic These words are opposites Static means fixed, unchanging Dynamic means changing with time Static variable of a class: value does not depend on individual objects (instances) of a class Static method of a class: effect does not depend on individual objects (instances) of a class Static binding (this term not used by text): binding a method call to the right method implementation at compile time Dynamic binding (this term is used by text): binding a method call to the right method implementation at run time
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Static (Compile-Time) Binding Binding a method call to the right method implementation at compile-time This is possible for static methods because it depends only on matching the argument types to the method signature NOT POSSIBLE for instance methods, because at compile-time we only know the type of the object reference, NOT the actual class of the object instance
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Example Object o = new Time(); Date d = new Time(); Time t = new Time(); System.out.println(o.toString()); System.out.println(d.toString()); System.out.println(t.toString()); Which toString is called? Does it know which one to call at compile time, or only at run time?
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Dynamic Binding Used for instance methods Actual class of object is not known at compile time, only at run time Then, binding of method call to the right implementation of the method takes place, based on the class of the implicit parameter object Which method is called when o.toString() is executed does not depend on type of the object reference o, but on the actual class of the object that it points to When execution takes place, the JVM looks for a matching method in that class. If there isn’t one, it looks in the superclass, and so on….if there are none in the inheritance tree below Object, it will use the toString method in the Object class
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What about the Explicit Parameters? The method binding does not depend on the class of any object that is passed as an explicit parameter! Thus, which implementation of x.equals(y) is called –depends on the class of the object instance that the implicit parameter x points to –does not depend on the class of the object instance that the explicit parameter y points to However, the method signatures must match!
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Matching the Method Signatures Consider x.equals(y) Which method is called depends on the actual type of the object instance that x points to However, the only candidates are methods whose signature matches the object reference type of y These are the ones with a formal parameter whose type is the same class or a subclass, but not a superclass If none match, there is a compile-time error
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Example class Date{ … public boolean equals(Date other){ return (this.year == other.year && this.month == other.month && this.day == other.day); } } Object o = new Date(2006,10,18); Date d = new Date(2006,10,18); System.out.println(d.equals(o));// no matching signature System.out.println(o.equals(d));// more subtle
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Overriding a Method in a Superclass Method in superclass is overridden ONLY if signature matches To override the equals method in the Object class, we must specify that the explicit parameter has type Object Then inside the method code, we must CAST this to the actual type of the object before we use it
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The instanceof operator note: not instanceOf x instanceof y returns true if the object that x points to is an instance of class y, and false otherwise good idea to use it inside any method such as Date that overrides the equals method of the Object class, checking whether the explicit parameter really is an instance of the right class before casting it (otherwise an error will be generated) equals should return false if the actual parameter object is an instance of the wrong class
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Now what happens? Object o = new Date(2006,10,18); Date d = new Date(2006,10,18); Time t = new Date(2006,10,18,11,0,0); o.equals(d) d.equals(o) o.equals(t) t.equals(o) etc….
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