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Notes on. Energy Is the capacity to do work or to produce heat Forms: Kinetic energy = energy of motion Potential energy = energy of position Thermal.

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Presentation on theme: "Notes on. Energy Is the capacity to do work or to produce heat Forms: Kinetic energy = energy of motion Potential energy = energy of position Thermal."— Presentation transcript:

1 Notes on

2 Energy Is the capacity to do work or to produce heat Forms: Kinetic energy = energy of motion Potential energy = energy of position Thermal energy = a form of KE caused by random internal motion of particles of matter

3 Heat A form of energy Is measured in calories (cal) or Joules (J) 1 cal = 4.184 J 1 Cal = 1000 cal Is not the same as temperature !

4 Temperature A measure of the Kinetic Energy in a system Units are: Fahrenheit or Celsius (Centigrade) or Kelvin

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6 Absolute Zero Corresponds to about -273 o C Is the (theoretical) point at which the motion of particles of matter – their kinetic energy - ceases

7 More about Temperature For most applications in Chemistry, we will use the Celsius scale. There is at least one topic for which we must change our temperature units to Kelvins – that is for Gas Laws. On the Kelvin scale there is no “zero” and no negative values. That becomes important in calculations involving gases, since a negative temp might make it look like, in calculations, that there is a negative volume.

8 Law of Conservation of Energy Energy is neither created nor destroyed…it just Changes form. We can record a reading as, for example, 102.3 degrees Celsius - but - if we were to record a temperature using the Kelvin scale, we would simply state, for example, “275 Kelvins” (not “degrees kelvin”) By the way…

9 Conversions C = K – 273 so therefore K = C + 273 C = 5/9 (F – 32) and F = (9/5 * C) + 32 22.5 o C = ___ K 55 o F = ___ o C 290 K = ___ o C 97 o F = ___ o C Temperature “Sense” – Memorize these: Room Temp in C: 22 Body Temp in C: 37 Boiling Pt/Freezing Pt: 100/0

10 Specific Heat A property of matter that is unique to each element or compound – It does not depend on the amount of matter present, so is an intensive property Also called “heat capacity” “the amount of energy needed to raise the temperature of 1 g of a substance by 1 degree Celsius”

11 Formula for Specific Heat Q = mc  T Where Q = “heat” and is measured in J Where m = mass and is measured in g Where c = specific heat and is measured in …(see next slide!) Where  T = (“delta T”) is “change in temperature” and is measured in C

12 Unit for Specific Heat So what is the unit for “c”? Let’s rearrange the formula Q = mc  T in terms of c (we call this “deriving”) c = Q / m  T All units in Chemistry and Physics come from the formulas that they’re in Therefore, c = Q / m  T Jg/ oCoC

13 Specific Heat of Water Water, H 2 O, has an extremely high “heat capacity”, which in plain language, means that it takes a lot of energy to heat it up and it has a tremendous ability to retain heat (aka: takes a lot to cool it down) The specific heat of water is 4.18 J/g o C (which you may recognize as 1 calorie) Memorize this!!!!!!!!!!!

14 Why That’s Important It affects your life every day. The reason it tends to be cooler at the ocean than in the valley is due to the c H2O The reason that hurricanes get stronger over warm water is that they’re deriving their energy from the heat contained in the water (maybe that doesn’t affect you every day); it gives them energy The reason a steam burn is worse than a regular burn is due to the energy in the steam Can you think of other examples?

15 Reminder: Law of Conservation of Energy We know that energy cannot be created or destroyed We know that heat is a form of energy So…it must be true that the heat lost by one substance must be “accountable” by another substance or substances, or… Q lost = Q gained

16 If Q lost = Q gained …and if Q = mc  T, then it must be true that… (mc  T) lost = (mc  T) gained And that’s the foundation for our next lab: “Specific Heat of a Metal”

17 Pre-Lab: Specific Heat of a Metal Discussion: You will be given a sample of a metal. You will have to determine its specific heat. We already know the specific heat of water (4.18 J/g o C) We will use the concept of … (mc  T) lost =(mc  T) gained to solve for the unknown c for the metal

18 Lab: Specific Heat of a Metal (mc  T) gained = (mc  T) lost (mc  T) gained by water = (mc  T) lost by metal (mc  T) water = (mc  T) metal Measure the mass of the water You know the “c” for water (4.18 J/gC) Measure the initial temp of the water before the metal was added; the final temp after the metal heats it up Measure the mass of the metal You will be calculating the “c” for the metal If the metal starts at the boiling point of water, that’s your T 1. The temp after the water has stopped rising has to be the temp of the metal as well, so that is T 2.


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