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Using the 8254 Timer-Counter

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Presentation on theme: "Using the 8254 Timer-Counter"— Presentation transcript:

1 Using the 8254 Timer-Counter
Understanding the role of the system’s 8254 programmable Interval-Timer/Counter

2 Displaying ‘Time-Of-Day’
Algorithm steps: Get the count of timer-interrupts so far today Convert these ‘timer-ticks’ into seconds Breakdown the total number of seconds today into Hours, Minutes, Seconds, and AM/PM Convert numerical values into digit-strings Output these results to the video terminal

3 Where’s the ‘tick’ counter?
main memory Number of timer-tick interrupts so far today (longword at 0x0046C) 0x00500 ROM-BIOS DATA AREA 0040:006C tick_count 0x00400 Interrupt Vector Table (for real-mode) 0x00000

4 Getting the ‘tick’ count
The ROM-BIOS interrupt-handler for the timer interrupt stores the tick-count as a 32-bit integer located at address 0x046C (it’s in the ROM-BIOS DATA AREA) In real-mode, we can get it like this: xor %ax, %ax # address segment zero mov %ax, %fs # using FS register mov %fs:0x046C, %eax # copy tick-count to EAX mov %eax, total_ticks # save in a local variable segment-override prefix (segment used would be %ds)

5 Converting ‘ticks’ to seconds
total_ticks_today total_seconds_today = number of ticks-per-second The number of ‘ticks-per-second’ is based upon the way the PC’s timing hardware has been programmed

6 The 8254 PIT The 8254 Programmable Interval-timer is used by the PC system for (1) generating timer-tick interrupts (rate is 18.2 per sec), (2) performing dynamic memory-refresh (reads ram once every 15 microseconds), and (3) generates ‘beeps’ of PC speaker When the speaker-function isn’t needed, the 8254 is available for other purposes

7 Input/Output frequencies
The input-pulses to each Timer-channel is a long established PC standard, based on the design of the chrystal oscillator chip: 1,193,182 pulses-per-second (Hertz) The frequency of the output-pulses from any Timer-channel is determined by how that channel’s Latch was programmed

8 Three timer/counter ‘channels’
8284 PCLK Hz CLK0 Channel 0 OUT0 Interrupt IRQ0 GATE0 Port 0x61, bit #4 CLK1 Channel 1 OUT1 DRAM refresh GATE1 Port 0x61, bit #5 CLK2 Channel 2 OUT2 GATE2 AND speaker Port 0x61, bit #0 8254 PIT +5 V Port 0x61, bit #1

9 Counter decrements when pulsed

10 8254 Command-Port Commands are sent to the 8254 via io/port 0x43
CHANNEL COMMAND OUTPUT MODE binary / BCD Channel-ID 00 = chn 0 01 = chn 1 10 = chn 2 Command-ID 00 = Latch 01 = LSB r/w 10 = MSB r/w 11 = LSB-MSB r/w Output Mode 000 = one-shot level 001 = retriggerable 010 = rate-generator 011 = square-wave 100 = software strobe 101 = hardware strobe Counting Mode 0 = binary 1 = BCD Commands are sent to the 8254 via io/port 0x43

11 Programming a PIT channel
Step 1: send command to PIT (port 0x43) Step 2: read or write the channel’s Latch via port 0x40 for channel 0 via port 0x41 for channel 1 via port 0x42 for channel 2

12 Standard BIOS programming
For Channel 0 (the ‘timer-tick’ interrupt) the Latch is programmed during system startup with a value of zero But the Timer interprets zero as 65,536 So the frequency of the output-pulses from Timer-channel 0 is equal to this quotient: output-frequency = input-frequency / frequency-divisor = / (approximately 18.2)

13 Consequently… To compute ‘total_seconds’ from ‘total_ticks’:
total_seconds = total_ticks / ticks_per_second = total_ticks / ( / 65536) = ( total_ticks * ) / We can use the Pentium’s integer-arithmetic instructions MUL (multiply) and DIV (divide)

14 How ‘MUL’ works mull reg_or_mem Before executing the MUL instruction…
EAX multiplicand (32-bits) reg (or mem) multiplier (32-bits) 32-bit operands mull reg_or_mem Here’s the instruction… After executing the MUL instruction… product (64-bits) EDX EAX 64-bit product

15 How ‘DIV’ works divl reg_or_mem Before executing the DIV instruction…
dividend (64-bits) EDX EAX 64-bit dividend reg (or mem) divisor (32-bits) 32-bit operand divl reg_or_mem Here’s the instruction… After executing the DIV instruction… two results (32-bits) EDX EAX 32-bit remainder 32-bit quotient

16 Implementing the conversion
So use MUL and DIV to convert ‘ticks’ into ‘seconds’, like this: # total_seconds = ( total_ticks * FREQ_DIVISOR ) / PULSES_PER_SEC mov total_ticks, %eax mov $FREQ_DIVISOR, %ecx mul %ecx mov $PULSES_PER_SEC, %ecx div %ecx mov %eax, total_seconds # Now integer-quotient is in EAX, and integer-remainder is in EDX

17 ‘Time-Of-Day’ Format HH:MM:SS am/pm hours seconds morning or afternoon
minutes So we need to compute four numerical values from the ‘total_seconds’ integer

18 Our four time-parameters
We use these arithmetical ideas: total_minutes = ( total_seconds / 60 ); ss = ( total_seconds % 60 ); total_hours = (total_minutes / 60 ); mm = ( total_minutes % 60 ); total_halfdays = (total_hours / 12 ); hh = (total_hours % 12 ); Total_days = ( total_halfdays / 2 ); xm = total_halfdays % 2;

19 A subtle refinement Our ‘total_seconds’ value was gotten with an integer-division operation, so there’s likely to be some ‘round-off’ error How can we be sure we use the ‘closest’ integer to the actual quotient? We should remember the ‘rounding’ rule! When ‘remainder’ is equal or greater than 1/2 of ‘divisor’, ‘quotient’ gets incremented

20 How to implement rounding?
There is more than one way to do it – i.e., the “amateur’s” way or the “expert’s” way Knowledge of the Pentium’s architecture and instruction-set can assist The ‘obvious’ method: if ( 2 * remainder >= divisor ) ++quotient; But this uses a multiply and a conditional jump-instruction (inefficient!)

21 Avoiding inefficiency…
Replace the ‘multiply’ with an ‘addition’ Use ‘subtract’ and ‘add-with-carry’ instead of using ‘compare’ and ‘conditionally-jump’ # Recall: quotient was in EAX, remainder was in EDX, divisor was in ECX add %edx, %edx # doubles the remainder sub %ecx, %edx # computes: 2*quotient – divisor # now carry-flag is clear in case 2*quotient >= divisor cmc # complement the carry-flag bit # now carry-flag is set in case 2*quotient >= divisor adc $0, %eax # add the carry-flag to the quotient # So this achieves the same effect as the ‘rounding rule’, but wit no jump!

22 In-class exercise Can you enhance our ‘timeoday.s’ demo to make it more dramatic (and later useful) by creating a loop within its ‘main’ routine, so it continues to read and display the time (until the user presses a key) HINTS: Use an INT-0x16 keyboard service to ‘peek’ into the keyboard-queue, and omit the ‘\n’ (newline) control-code from the ‘report’ message-string

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