1. ARITHMETIC LOGIC SHIFT UNIT
Shift Microoperations
ARITHMETIC LOGIC SHIFT UNIT S3 S2 C i S1 S0
Arithmetic D i
Circuit
Select
4 x 1 C F
i+1 1
MUX i 2 3
Logic E i B i
Circuit A i
shr A
i-1 A
shl
i+1
S3 S2 S1 S0 Cin Operation Function
F = A Transfer A
F = A Increment A
F = A + B Addition
F = A + B Add with carry
F = A + B’ Subtract with borrow
F = A + B’ Subtraction
F = A Decrement A
F = A TransferA
X F = A  B AND
X F = A B OR
X F = A  B XOR
X F = A’ Complement A
X X X F = shr A Shift right A into F
X X X F = shl A Shift left A into F

2. BASIC COMPUTER REGISTERS
Registers in the Basic Computer 11 PC
Memory 11
4096 x 16 AR 15 IR
CPU 15 15 TR DR 7 7 15
OUTR
INPR AC
List of Registers
DR Data Register Holds memory operand
AR Address Register Holds address for memory
AC Accumulator Processor register
IR Instruction Register Holds instruction code
PC Program Counter Holds address of instruction
TR Temporary Register Holds temporary data
INPR Input Register Holds input character
OUTR Output Register Holds output character

3. Fundamental Concepts
Processor fetches one instruction at a time and perform the operation specified.
Instructions are fetched from successive memory locations until a branch or a jump instruction is encountered.
Processor keeps track of the address of the memory location containing the next instruction to be fetched using Program Counter (PC).
Instruction Register (IR)
Mr. Mukul Varshney

4. Instruction codes
PROCESSOR REGISTERS
A processor has many registers to hold instructions, addresses, data, etc
The processor has a register, the Program Counter (PC) that holds the memory address of the next instruction
Since the memory in the Basic Computer only has 4096 locations, the PC only needs 12 bits
In a direct or indirect addressing, the processor needs to keep track of what locations in memory it is addressing: The Address Register (AR) is used for this
The AR is a 12 bit register in the Basic Computer
When an operand is found, using either direct or indirect addressing, it is placed in the Data Register (DR). The processor then uses this value as data for its operation
The Basic Computer has a single general purpose register – the Accumulator (AC)

5. Instruction codes
PROCESSOR REGISTERS
The significance of a general purpose register is that it can be used for loading operands and storing results
e.g. load AC with the contents of a specific memory location; store the contents of AC into a specified memory location
Often a processor will need a scratch register to store intermediate results or other temporary data; in the Basic Computer this is the Temporary Register (TR)
The Basic Computer uses a very simple model of input/output (I/O) operations
Input devices are considered to send 8 bits of character data to the processor
The processor can send 8 bits of character data to output devices
The Input Register (INPR) holds an 8 bit character gotten from an input device
The Output Register (OUTR) holds an 8 bit character to be send to an output device

6. Instruction Format
A computer usually have a variety of instruction code formats. It is the function of control unit within the CPU to interpret each instruction code and provide the necessary control functions needed to process the instruction.
The format of an instruction is depicted by a rectangular box. The bits of the instruction are divided into groups called fields.
The most common fields found in instruction format are:
1) An operation code field that specifies the operation to be performed.
2) An address field that designates a memory address or a processor register.
3) A mode field that specifies the way the operands or the effective address is determined.
Opcode
Address
Mode
Mr. Mukul Varshney

7. 5-3. Computer Instruction
Instruction Code Formats :
Memory-reference instruction
Opcode = 000  110
Register-reference instruction
Input-Output instruction ,
I=0 : Direct,
I=1 : Indirect
I Opcode Address
Register Operation
I/O Operation
Reading this table:
the presented code is for any instruction that has 16 bits. The xxx represents don’t care ( any data for the first 12 bits). Example for is a hexadecimal code equivalent to Which means B1 (Bit 1) is set to 1 and the rest of the first 12 bits are set to zeros.

8. Instruction cycle
The control unit of a computer is designed to go through an instruction cycle that is divided into three major phases:
1) Fetch the instruction from memory
2) Decode the instruction 3) Execute the instruction
PC holds the address of the instruction to be executed next and incremented each time an instruction is fetched from memory.
The decoding determines the operation to be performed , the addressing modes and the location of the operands.
The computer than executes the instruction
Mr. Mukul Varshney

9. Instruction cycle
The instruction execution cycle can be clearly divided into three different parts
Fetch Cycle The fetch cycle takes the address required from memory, stores it in the instruction register, and moves the program counter on one so that it points to the next instruction.
PC contains address of next instruction
Address moved to MAR
Address placed on address bus
Control unit requests memory read
Result placed on data bus, copied to MBR, then to IR
Meanwhile PC incremented by 1
Decode Cycle Here, the control unit checks the instruction that is now stored within the instruction register. It determines which opcode and addressing mode have been used, and as such what actions need to be carried out in order to execute the instruction in question.
Execute Cycle The actual actions which occur during the execute cycle of an instruction depend on both the instruction itself, and the addressing mode specified to be used to access the data that may be required
Mr. Mukul Varshney

10. Instruction cycle
• The fetch & decode phases of the instruction cycle consists of the following microoperations synchronized with the timing signals (clocking principle).
Timing signal microoperations
T0: AR ¬ PC
T1: IR ¬ M[AR], PC ¬ PC + 1
T2: D0, ..., D7 ¬ Decode IR(12-14), AR ¬ IR(0-11), I ¬ IR(15)
Mr. Mukul Varshney

11. 1. Enable the read input of the memory.
T0: Since only AR is connected to the address inputs of memory, the address of instruction is transferred from PC to AR.
1. Place the content of PC onto the bus by making the bus selection inputs S2S1S0 = 010.
2. Transfer the content of the bus to AR by enabling the LD input to AR
( AR ¬ PC).
T1: The instruction read from memory is then placed in the instruction register IR. At the same time, PC is incremented to prepare for the address of the next instruction.
1. Enable the read input of the memory.
2. Place the content of memory onto the bus by making the bus selection inputs S2S1S0 = 111. (Note that the address lines are always connected to AR, and we have already placed the next instruction address in AR.)
3. Transfer the content of the bus to IR by enabling the LD input to IR
(IR ¬ M[AR]).
4. Increment PC by enabling the INR input of PC ( PC ¬ PC + 1 ).
T2: The operation code in IR is decoded; the indirect bit is transferred to I; the address part of the instruction is transferred to AR. (See the common bus skeleton diagram.)
Mr. Mukul Varshney

12. Control function Microoperation
Similar circuits are used to realize the microoperations at T2.
• At T3, microoperations which take place depend on the type of instruction. The four different paths are symbolized as follows, where the control functions must be connected to the proper inputs to activate the desired microoperations.
Control function Microoperation
D7’IT3: AR ¬ M[AR], indirect memory transfer
D7’I’T3: Nothing, direct memory transfer
D7I’T3: Execute a register-reference instruction
D7IT3: Execute an I/O instruction
When D7’T3 = 1 (At T3 & IR(12-14) ¹ 111), the execution of memory-reference instructions takes place with the next timing variable T4.
Mr. Mukul Varshney

13. Mr. Mukul Varshney