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Equations as Relations Lesson for Glencoe Algebra I Math
By: Cathy Miller Bartlett High School Lesson for Glencoe Algebra I Math Section 4-4 Algebra I Glencoe Mathematics 2004 The McGraw Hill Companies Inc.
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Ways to write a relation
Set of ordered pairs Table Mapping Graph Equation in two variables
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New Vocabulary Equation in Two Variables – Equations with 2 different variables. Solution to Equation in Two Variables – any point that makes a true statement when you substitute the x and y values into the equation.
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Solve Using a Replacement Set
Replacement set = a set of possible solutions. Substitute the points to find the true solutions… these are the ones that make the equation true. Solution set = the set of true solutions.
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Solve -3x+y=7 if the replacement set is {(-5,0),(-3,-2),(2,13),(4,19)}
-3(-5)+(0)=7 15 = 7 -3(-3)+(-2)=7 7=7
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Solve -3x+y=7 if the replacement set is {(-5,0),(-3,-2),(2,13),(4,19)}
-3(2)+(13)=7 7=7 -3(4)+(19)=7 7=7
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Solve y=7+3x if the replacement set is {(-5,0),(-3,-2),(2,13),(4,19)}
Solution set = {(-3,-2),(2,13),(4,19)}
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Solve Using a Given Domain
Domain = the x’s for your solution setlthat you can use Substitute the x’s to find their y’s. Solution set = the set (x,y)’s
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Solve 9x+3y=15 if the domain is { 0,1,2,3}
First…solve the equation for y
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Solve 9x+3y=15 if the domain is { 0,1,2,3}
y=-3x+5 y y=-3(0)+5 = 5 1 y=-3(1)+5 = 2
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x y y=-3x+5 y=-3(0)+5 = 5 1 y=-3(1)+5 = 2 2 y=-3(2)+5 = -1 3 y=-3(3)+5
Solve 9x+3y=15 if D={ 0,1,2,3} x y y=-3x+5 y=-3(0)+5 = 5 1 y=-3(1)+5 = 2 2 y=-3(2)+5 = -1 3 y=-3(3)+5 = -4 Sol. Set={(0,5),(1,2),(2,-1),(3,-4)|
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