1. Notes and Homework Assistance Inkster High School Resource: Chemistry Textbook, chapter 11 Mrs. Nicole Gall

2. DO NOW: Use Double Bubble to compare: product and reactant HOMEWORK: Continue from Chapter 11 AIMS: (c5.2) TLW Balance 8 – 12 equations.

3. DO NOW: Use Double Bubble to compare: product and reactant HOMEWORK: Continue from Chapter 11 AIMS: (c5.2) TLW Balance 8 – 12 equations.

4. Label your paper please. Name April 4, 2011 Fourth hour Chemistry Chapter 11 homework- due April 12 #3, 5, 7, 8, 9, 12, 22, 23, 24, 45, 52 PS: Chemistry observations: 5 physical properties, 5 chemical properties, due today: at least one full page. 20 points. Accepted tomorrow for 18 pts.

5. CHAPTER 11 TOPIC: CHEMICAL REACTIONS PAGE 327 #3. BALANCE EACH EQUATION. A. __AgNO 3 + __H 2 S __Ag 2 S + __HNO 3 B.__Zn(OH) 2 + __H 3 PO 4 __Zn 3 (PO 4 ) 2 + __H 2 O Clue: without changing molecular formulas, change coefficients so that the reactants and products contain the same numbers of each atom

6. Ag N O H S Ag N O H S 1 1 3 2 1 2 1 3 1 1 Step one: count the total number of each element listed on the reactant side of the chemical equation. Repeat for the product side of the equation. If these are the same, the equation is balanced. This chemical equation is NOT balanced.

7. Ag N O H S Ag N O H S 1 1 3 2 1 2 1 3 1 1 2 2 6 2 1 2 1 3 1 1 In the first count, there were 2 Ag atoms in the products, but only 1 in the reactants. I chose to double the number of AgNO 3 molecules in the reactants. Then I counted the new totals. This is NOT balanced! Lets keep trying…

8. Ag N O H S Ag N O H S 1 1 3 2 1 2 1 3 1 1 2 2 6 2 1 2 1 3 1 1 2 2 6 2 1 2 2 6 2 1 In our second count, we found that there were 2N, 6O, and 2H in the reactants, and only 1N, 3O, and 1H in the products. Lets double the number of HNO 3 molecules and count again.

9. Ag N O H S Ag N O H S 1 1 3 2 1 2 1 3 1 1 2 2 6 2 1 2 1 3 1 1 2 2 6 2 1 2 2 6 2 1 The equation is balanced! We have the same number of each atom in both the products and the reactants.

11. Zn O H P Zn O H P 1 6 5 1 3 8 2 2

12. Zn O H P Zn O H P 1 6 5 1 3 8 2 2 3 10 9 1 3 8 2 2

13. Zn O H P Zn O H P 1 6 5 1 3 8 2 2 3 10 9 1 3 8 2 2 3 14 12 2 3 8 2 2

14. Zn O H P Zn O H P 1 6 5 1 3 8 2 2 3 10 9 1 3 8 2 2 3 14 12 2 3 8 2 2 3 14 12 2 3 14 12 2

15. Zn O H P Zn O H P X x x x x x x x

16. #5a. _FeCl 3 + _NaOH _Fe(OH) 3 + _NaCl #5b. _CS 2 + _Cl 2 _CCl 4 + _ S 2 Cl 2

17. Fe Cl Na O H --- Fe Cl Na O H 1 3 1 1 1 1 1 1 3 3

18. Fe Cl Na O H --- Fe Cl Na O H 1 3 1 1 1 1 1 1 3 3 1 3 1 1 1 1 3 3 3 3

19. Fe Cl Na O H --- Fe Cl Na O H 1 3 1 1 1 1 1 1 3 3 1 3 1 1 1 1 3 3 3 3 1 3 3 3 3

20. C CS Cl I I2 C CS Cl I I2 CL4 2 2 2 2 1 1 0 4 4 1 1 Its balanced! No changes needed. Just kidding Try this one on your own before you switch to the next screen to check your answer (Thanks Catherine and Anthony )

21. C S Cl 1 2 2 1 2 6 1 2 6 The balanced equation is written: CS 2 + 3Cl 2 CCl 4 + S 2 Cl 2

22. Please read the textbook for these answers (previous section only)

23. #12a _SO 2 + _O 2 _SO 3 #12b _Fe 2 O 3 + _H 2 _Fe + _H 2 O #12c _P + O 2 P 4 O 10 #12d _Al + N 2 _AlN

24. 2SO 2 + O 2 2SO 3 Fe 2 O 3 + 3H 2 2Fe + 3H 2 O 4P + 5O 2 P 4 O 10 2Al + N 2 2AlN

26. Mg is in the second column (2 valence electrons) O is in the 16 th column (6 valence electrons) One Mg and one O combine to form a stable magnesium oxide, MgO molecule